[R] aggregate dataframe by multiple factors

David Winsemius
Sun, 20 Nov 2016 19:11:29 -0000

> On Nov 20, 2016, at 10:49 AM, Karim Mezhoud <kmezhoud at gmail.com>
wrote:
>
> Yes the results does not have a date but
> successive DCE.1, DCE2, DCE.3 indicates
>  DCE.date1 , DCE.date2, DCE.date3
> I hope that the chronological order of date is conserved.

There are, however, 4 dates. See this pair of results. You can probably do
something if you ever figure out what it is that you precisely want. I think the
date ordering is automatic here:

> require(reshape2)
Loading required package: reshape2

> dcast(dat, first.Name +  Name + Department ~ date, value.var='DCE')
  first.Name   Name Department 2013-09-30 2013-12-28 2014-03-30 2014-06-28
1      Amish  Wives        TAS       0.59         NA       0.59         NA
2    Ancient Nation        QLH       0.54       0.28       0.54       0.28
3    Auction Videos        YME       0.57         NA       0.57
NA
> dcast(dat, first.Name +  Name + Department ~ date, value.var='DP')
  first.Name   Name Department 2013-09-30 2013-12-28 2014-03-30 2014-06-28
1      Amish  Wives        TAS       0.56         NA       0.56         NA
2    Ancient Nation        QLH       0.58       0.29       0.58       0.29
3    Auction Videos        YME       0.56         NA       0.56         NA



> Thanks,
> Karim
>
>
> On Sun, Nov 20, 2016 at 7:44 PM, David Winsemius <dwinsemius at
comcast.net> wrote:
>
> > On Nov 20, 2016, at 5:28 AM, Karim Mezhoud <kmezhoud at
gmail.com> wrote:
> >
> > Sorry for the delay,
> > Many Thanks for Mr. David and Mr. Petr
> > I thinked  to use "sort" function to arrange chronologically
value by  'date' (without 'date' is colnames) of each variables
(DCE, DP).
> >
> >
> > The solution of David seems to be simple to understand with
"unlist" function.
> > The solution of Petr seems to be fancy. I did not find document  about
"I" argument for aggregate function.
> >
> > How can know which value for which date?
>
> You asked for a functional reshaping that did not have the date. Now you
want the date? There was no date in the result you indicated was desired.
....??????
>
> --
> David.
>
> >
> > I will save the reshaping/ordering dataframe  for later use.
> > Many Thanks,
> > Karim
> >
> >
> > On Fri, Nov 18, 2016 at 11:34 AM, PIKAL Petr <petr.pikal at
precheza.cz> wrote:
> > Hi
> >
> > same result can be achieved by
> >
> > dat.ag<-aggregate(dat[ , c("DCE","DP")], by=
list(dat$first.Name, dat$Name, dat$Department) , "I")
> >
> > Sorting according to the first row seems to be quite tricky. You could
probably get closer by using some combination of split and order and arranging
back chunks  of data
> >
> > ooo1<-order(split(dat$DCE,interaction(dat$first.Name, dat$Name,
dat$Department, drop=T))[[1]])
> > data.frame(sapply(split(dat$DCE,interaction(dat$first.Name, dat$Name,
dat$Department, drop=T)), rbind))[ooo1,]
> >   Ancient.Nation.QLH Amish.Wives.TAS Auction.Videos.YME
> > 2               0.28              NA                 NA
> > 4               0.28              NA                 NA
> > 1               0.54            0.59               0.57
> > 3               0.54            0.59               0.57
> >
> > however I wonder why the order according to the first row is necessary
if all NAs are on correct positions?
> >
> > Cheers
> > Petr
> >
> >
> > > -----Original Message-----
> > > From: R-help [mailto:r-help-bounces at r-project.org] On Behalf
Of David
> > > Winsemius
> > > Sent: Friday, November 18, 2016 9:30 AM
> > > To: Karim Mezhoud <kmezhoud at gmail.com>
> > > Cc: r-help at r-project.org
> > > Subject: Re: [R] aggregate dataframe by multiple factors
> > >
> > >
> > > > On Nov 17, 2016, at 11:27 PM, Karim Mezhoud <kmezhoud at
gmail.com>
> > > wrote:
> > > >
> > > > Dear all,
> > > >
> > > > the dat  has missing values NA,
> > > >
> > > >    first.Name   Name Department  DCE   DP       date
> > > > 5      Auction Videos        YME 0.57 0.56 2013-09-30
> > > > 18       Amish  Wives        TAS 0.59 0.56 2013-09-30
> > > > 34     Ancient Nation        QLH 0.54 0.58 2013-09-30
> > > > 53     Auction Videos        YME   NA   NA 2013-12-28
> > > > 66       Amish  Wives        TAS   NA   NA 2013-12-28
> > > > 82     Ancient Nation        QLH 0.28 0.29 2013-12-28
> > > > 102    Auction Videos        YME 0.57 0.56 2014-03-30
> > > > 115      Amish  Wives        TAS 0.59 0.56 2014-03-30
> > > > 131    Ancient Nation        QLH 0.54 0.58 2014-03-30
> > > > 150    Auction Videos        YME   NA   NA 2014-06-28
> > > > 163      Amish  Wives        TAS   NA   NA 2014-06-28
> > > > 179    Ancient Nation        QLH 0.28 0.29 2014-06-28
> > > >
> > > >
> > > > agg <- as.data.frame(aggregate(dat[ ,
c("DCE","DP")], by> > > > list(dat$first.Name,
dat$Name, dat$Department) , "sort"))
> > >
> > > The closest I could get on a few attempts was:
> > >
> > > (agg <- as.data.frame(aggregate(dat[ ,
c("DCE","DP")], by> > > list(dat$first.Name,
dat$Name, dat$Department) , function(d) { unlist(d)}))
> > >  )
> > >
> > >   Group.1 Group.2 Group.3 DCE.1 DCE.2 DCE.3 DCE.4 DP.1 DP.2 DP.3
DP.4
> > > 1 Ancient  Nation     QLH  0.54  0.28  0.54  0.28 0.58 0.29 0.58
0.29
> > > 2   Amish   Wives     TAS  0.59    NA  0.59    NA 0.56   NA 0.56
NA
> > > 3 Auction  Videos     YME  0.57    NA  0.57    NA 0.56   NA 0.56
NA
> > >
> > > I think the sort operation might be somewhat ambiguous in this
instance. I
> > > tried:
> > >
> > >  (agg <- as.data.frame(aggregate(dat[ ,
c("DCE","DP")], by> > > list(dat$first.Name,
dat$Name, dat$Department) , function(d) {
> > > unlist(lapply(d,sort))}))
> > >  )
> > >
> > > With no success, not even a sorted result.
> > >
> > > --
> > > David.
> > > >
> > > >
> > > > agg has list of value. I would separate value in different
columns.
> > > >
> > > >  Group.1 Group.2 Group.3                    DCE
DP
> > > > 1 Ancient  Nation     QLH 0.28, 0.28, 0.54, 0.54 0.29, 0.29,
0.58, 0.58
> > > > 2   Amish   Wives     TAS             0.59, 0.59
0.56, 0.56
> > > > 3 Auction  Videos     YME             0.57, 0.57
0.56, 0.56
> > > >
> > > > The  goal:
> > > >
> > > > Group.1 Group.2 Group.3  DCE.1 DCE.2 DCE.3  DCE.4  DP.1
DP.2  DP.3  DP.4
> > > > 1 Ancient  Nation     QLH    0.28     0.28    0.54     0.54
0.29, 0.29,
> > > > 0.58, 0.58
> > > > 2   Amish   Wives     TAS        NA     NA     0.59, 0.59
NA
> > > > NA  0.56, 0.56
> > > > 3 Auction  Videos     YME         NA   NA      0.57, 0.57
NA
> > > > NA  0.56, 0.56
> > > >
> > > >
> > > >
> > > > dat <- structure(list(first.Name = structure(c(3L, 1L,
2L, 3L, 1L, 2L,
> > > > 3L, 1L, 2L, 3L, 1L, 2L), .Label = c("Amish",
"Ancient", "Auction",
> > > > "Ax", "Bachelorette",
"Basketball", "BBQ", "Cake",
"Celebrity",
> > > > "Chef", "Clean", "Colonial",
"Comedy", "Comic", "Crocodile", "Dog",
> > > > "Empire", "Extreme", "Farm",
"Half Pint", "Hollywood", "House", "Ice
> > > > Road", "Jersey", "Justice",
"Love", "Mega", "Model", "Modern",
> > > > "Mountain", "Mystery", "Myth",
"New York", "Paradise", "Pioneer",
> > > > "Queer", "Restaurant", "Road",
"Royal", "Spouse", "Star", "Storage",
> > > > "Survival", "The Great American",
"Tool", "Treasure", "Wedding",
> > > > "Wife"), class = "factor"), Name =
structure(c(43L, 47L, 29L, 43L,
> > > > 47L, 29L, 43L, 47L, 29L, 43L, 47L, 29L), .Label =
c("Aliens",
> > > > "Behavior", "Casino", "Casting
Call", "Challenge", "Contest",
> > > > "Crashers", "Crew", "Dad",
"Dancing", "Date", "Disasters",
"Dynasty",
> > > > "Family", "Garage",
"Greenlight", "Gypsies", "Haul", "Hot
Rod",
> > > > "Inventor", "Jail", "Job",
"Justice", "Marvels", "Master", "Mates",
> > > > "Model", "Moms", "Nation",
"Ninja", "Patrol", "People",
"Pitmasters",
> > > > "Queens", "Rescue", "Rivals",
"Room", "Rooms", "Rules", "Star",
> > > > "Stars", "Superhero",
"Videos", "VIP", "Wars", "Wishes",
"Wives",
> > > > "Wrangler"), class = "factor"),
Department = structure(c(8L, 6L, 2L,
> > > > 8L, 6L, 2L, 8L, 6L, 2L, 8L, 6L, 2L), .Label =
c("HXW", "QLH", "RAR",
> > > > "RYC", "SYI", "TAS",
"VUV", "YME"), class = "factor"),
> > > >    DCE = c(0.57, 0.59, 0.54, NA, NA, 0.28, 0.57, 0.59, 0.54,
> > > >    NA, NA, 0.28), DP = c(0.56, 0.56, 0.58, NA, NA, 0.29,
0.56,
> > > >    0.56, 0.58, NA, NA, 0.29), date = structure(c(15978,
15978,
> > > >    15978, 16067, 16067, 16067, 16159, 16159, 16159, 16249,
16249,
> > > >    16249), class = "Date")), description =
"", row.names = c(5L, 18L,
> > > > 34L, 53L, 66L, 82L, 102L, 115L, 131L, 150L, 163L, 179L),
class > > > > "data.frame", .Names =
c("first.Name", "Name", "Department",
"DCE",
> > > > "DP", "date"))
> > > >
> > > >     [[alternative HTML version deleted]]
> > > >
> > > > ______________________________________________
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> > > > and provide commented, minimal, self-contained, reproducible
code.
> > >
> > > David Winsemius
> > > Alameda, CA, USA
> > >
> > > ______________________________________________
> > > R-help at r-project.org mailing list -- To UNSUBSCRIBE and more,
see
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http://www.R-project.org/posting-
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> > > and provide commented, minimal, self-contained, reproducible
code.
> >
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David Winsemius
Alameda, CA, USA