[R] time management graph

PIKAL Petr
2015-06-24T14:33:35Z

Hi Thierry

Thanks a lot. This is the option I found later.

Still not 100% satisfactory. Maybe somebody did similar task and will have
different opinion how to visualise such data.

Jim?s gant diagrams are worth consideration so I will try to elaborate it
further.

Cheers
Petr

From: Thierry Onkelinx [mailto:thierry.onkelinx at inbo.be]
Sent: Wednesday, June 24, 2015 1:48 PM
To: PIKAL Petr
Cc: r-help at r-project.org
Subject: Re: [R] time management graph

Another option would be to use segments instead of lines.

library(lubridate)
temp$end <- temp$time + minutes(temp$duration)
library(ggplot2)
ggplot(temp, aes(x=time, xend = end, y=Typ, yend = Typ, colour=person)) +
geom_segment()


ir. Thierry Onkelinx
Instituut voor natuur- en bosonderzoek / Research Institute for Nature and
Forest
team Biometrie & Kwaliteitszorg / team Biometrics & Quality Assurance
Kliniekstraat 25
1070 Anderlecht
Belgium

To call in the statistician after the experiment is done may be no more than
asking him to perform a post-mortem examination: he may be able to say what the
experiment died of. ~ Sir Ronald Aylmer Fisher
The plural of anecdote is not data. ~ Roger Brinner
The combination of some data and an aching desire for an answer does not ensure
that a reasonable answer can be extracted from a given body of data. ~ John
Tukey

2015-06-24 12:50 GMT+02:00 Jim Lemon <drjimlemon at
gmail.com<mailto:drjimlemon at gmail.com>>:
Hi Petr,
I'm not exactly sure this is what you are looking for, but try:

start_indices<-which(!is.na<http://is.na>(temp$duration))
pp_gantt_info<-list(
 labels=paste(as.character(temp$person[start_indices]),
 temp$Akce,temp$Typ,sep="-"),
 starts=temp$time[start_indices],
 ends=temp$time[start_indices+1],
require(plotrix)
vgridpos<-as.POSIXct(strptime(
 paste("2015-06-23
",c(16,17,18,19,20,21,22,23),":00:00",sep=""),
 format="%Y-%m-%d %H:%M:%S"))
vgridlab<-paste(c(16,17,18,19,20,21,22,23),":00",sep="")
gantt.chart(pp_gantt_info,vgridpos=vgridpos,vgridlab=vgridlab)

Jim


On Wed, Jun 24, 2015 at 2:05 AM, PIKAL Petr <petr.pikal at
precheza.cz<mailto:petr.pikal at precheza.cz>>
wrote:
> Dear all
>
> Did anybody tried to do time management graphs in R?
>
> I could do some aggregation
>
> xtabs(duration~person+Typ, data=temp)
>
> but I would like to make also a graph to show which task (Typ) and when was
done by which person. The closest I came till this evening is following graph,
but it is not exactly what I want.
>
> library(ggplot2)
> p<-ggplot(temp, aes(x=time, y=Typ, colour=person))
> p+geom_line()
>
> If anybody can focus me to proper functions or packages I would be
greatful.
>
> Here are the data.
>
> temp <- structure(list(Akce = structure(c(16L, 18L, 20L, 13L, 1L, 15L,
> 4L, 12L, 8L, 22L, 16L, 15L, 5L, 24L, 13L, 16L, 6L, 1L, 15L, 11L,
> 1L, 5L, 24L, 7L, 1L, 10L, 21L, 23L, 3L, 2L, 9L, 14L, 17L, 20L,
> 13L, 14L, 19L, 14L, 4L, 1L, 15L, 5L, 24L, 13L, 15L, 1L, 14L,
> 11L, 15L, 5L, 24L, 7L, 1L, 10L, 14L, 23L, 3L, 2L, 9L), .Label =
c("a",
> "b", "c", "d", "e", "f",
"g", "h", "i", "j", "k",
"l", "m", "n",
> "o", "p", "q", "r", "s",
"t", "u", "v", "w", "x"),
class = "factor"),
>     Typ = structure(c(4L, 6L, 6L, 6L, 2L, 6L, 6L, 1L, 1L, 8L,
>     4L, 6L, 6L, 6L, 6L, 4L, 1L, 2L, 6L, 5L, 2L, 6L, 6L, 6L, 2L,
>     3L, 4L, 6L, 7L, 4L, 4L, 7L, 7L, 6L, 6L, 7L, 6L, 7L, 6L, 2L,
>     6L, 6L, 6L, 6L, 6L, 2L, 7L, 5L, 6L, 6L, 6L, 6L, 2L, 3L, 7L,
>     6L, 7L, 4L, 4L), .Label = c("A", "B",
"C", "D", "E", "F",
>     "G", "H"), class = "factor"), person =
structure(c(1L, 1L,
>     1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L,
>     1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 2L,
>     2L, 2L, 2L, 2L, 2L, 2L, 2L, 2L, 2L, 2L, 2L, 2L, 2L, 2L, 2L,
>     2L, 2L, 2L, 2L, 2L, 2L, 2L, 2L, 2L, 2L, 2L, 2L), .Label =
c("One",
>     "Two"), class = "factor"), time =
structure(c(1435038600,
>     1435039200, 1435039800, 1435040100, 1435040400, 1435040760,
>     1435042200, 1435042680, 1435043220, 1435043400, 1435043700,
>     1435044300, 1435044600, 1435045200, 1435046400, 1435046700,
>     1435047000, 1435047300, 1435047600, 1435048800, 1435050600,
>     1435051200, 1435051800, 1435053300, 1435053900, 1435054500,
>     1435060800, 1435061700, 1435062000, 1435064400, 1435068000,
>     1435038600, 1435039200, 1435039800, 1435040100, 1435040280,
>     1435041060, 1435041600, 1435042200, 1435042800, 1435043400,
>     1435044600, 1435045200, 1435046400, 1435047000, 1435047300,
>     1435047600, 1435048800, 1435050600, 1435051200, 1435051800,
>     1435053300, 1435053900, 1435054500, 1435060800, 1435061700,
>     1435062000, 1435065600, 1435068000), class = c("POSIXct",
>     "POSIXt"), tzone = ""), duration = c(10, 10, 5, 5,
6, 24,
>     8, 9, 3, 5, 10, 5, 10, 20, 5, 5, 5, 5, 20, 30, 10, 10, 25,
>     10, 10, 105, 15, 5, 40, 60, NA, 10, 10, 5, 3, 13, 9, 10,
>     10, 10, 20, 10, 20, 10, 5, 5, 20, 30, 10, 10, 25, 10, 10,
>     105, 15, 5, 60, 40, NA)), .Names = c("Akce", "Typ",
"person",
> "time", "duration"), class = "data.frame",
row.names = c(NA,
> -59L))
>>
>
> Best regards
> Petr
>
>
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- a obsahuje-li nab?dku, je adres?t opr?vn?n nab?dku bezodkladn? p?ijmout;
Odes?latel tohoto e-mailu (nab?dky) vylu?uje p?ijet? nab?dky ze strany p??jemce
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??dn? smlouvy s v?jimkou p??pad?, kdy k tomu byl p?semn? zmocn?n nebo p?semn?
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