[R] argument is of length 0 & condition has length>1

David Winsemius
2010-08-04T13:55:47Z

On Aug 4, 2010, at 9:46 AM, Leigh E. Lommen wrote:

>
> I have the following array:
>
>> head(stocks)
>  DATE      TICKER PERMNO EXCHCD TSYMBOL TRDSTAT SHROUT    PRC
> RET
>
> 1 19950131   EWST  10001      3    EWST       A   2224 -7.75000
> -0.031250
> 2 19950228   EWST  10001      3    EWST       A   2224  7.54688
> -0.026210
> 3 19950331   EWST  10001      3    EWST       A   2244  7.50000
> 0.00637
> 4 19950428   EWST  10001      3    EWST       A   2244  7.50000
> 0.000000
> 5 19950531   EWST  10001      3    EWST       A   2244 -7.87500
> 0.050000
> 6 19950630   EWST  10001      3    EWST       A   2254  8.25000
> 0.060317
>
> I am trying to find stocks(TICKER) that are delisted at points (t-5)
> to
> t(19950630) to (t+7) using the following code:
>
> #find delistings or incomplete returns
> for (i in 1:T)
> 	{
> 	if ( (stocks[i,1]==19950630)&
> (stocks[i,2]!=stocks[i5,2])|(stocks[i,2]!=stocks[i+5,2]) )
                        ^
Missing operator?



> 		{
> 		print("Delisted stocks are: ")
> 		print(stocks[i,2])
> 		}
> 	}
>
> But I get the following error message:
>
> Error in if ((stocks[i, 1] == 19950630) & (stocks[i, 2] != stocks[i
> -  :
>
>  argument is of length zero
> In addition: Warning messages:
> 1: In if ((stocks[i, 1] == 19950630) & (stocks[i, 2] != stocks[i -  :
>  the condition has length > 1 and only the first element will be used
> 2: In if ((stocks[i, 1] == 19950630) & (stocks[i, 2] != stocks[i -  :
>  the condition has length > 1 and only the first element will be used
> 3: In if ((stocks[i, 1] == 19950630) & (stocks[i, 2] != stocks[i -  :
>  the condition has length > 1 and only the first element will be used
> 4: In if ((stocks[i, 1] == 19950630) & (stocks[i, 2] != stocks[i -  :
>  the condition has length > 1 and only the first element will be used
>
> Please help??
>
> Regards,
> Leigh
>
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David Winsemius, MD
West Hartford, CT