[R] for(variable in [])do

Inchallah Yarab
2009-08-13T07:55:46Z

In this code i try to calculate le difference between too number for two value
of  th variable phase i have did this

> (output <- read.csv2("C:/RM2Param.csv",sep=","))
  OptimYear LRPhase   PriorLRPosition      OptimPosition
1      2009      -1  1.15641679414676  0.252662968666702
2      2009      -1  1.05365365779321  0.119348307634027
3      2009      -1 0.959670688361124 0.0179266585317901
4      2009      -1  0.87403582415134 0.0217791412141115
5      2009       1  1.15641679414676   0.33037984561357
6      2009       1  1.05365365779321  0.282266634171568
7      2009       1 0.959670688361124  0.199612536004054
8      2009       1  0.87403582415134  0.103774779139200
> PriorLRPosition <- as.numeric(as.character(output[,3]))
> OptimPosition <- as.numeric(as.character(output[,4]))
> (SimuLRPosition <- rep(1, nrow(output)))
[1] 1 1 1 1 1 1 1 1
> output <- cbind(output,SimuLRPosition)
> (diffLRPosition <- abs(PriorLRPosition - SimuLRPosition))
[1] 0.15641679 0.05365366 0.04032931 0.12596418 0.15641679 0.05365366 0.04032931
[8] 0.12596418
> output <- cbind(output,diffLRPosition)
> (NbOFPriorLRPosition <- nrow(output)/2)
[1] 4
>
> for (LRPhase  in c(-1,1))
+ {Phase1 <- output[output[,2]==LRPhase,]}
>
> Phase1 <- Phase1[order (Phase1[,6]),]
> Phase1
  OptimYear LRPhase   PriorLRPosition     OptimPosition SimuLRPosition
7      2009       1 0.959670688361124 0.199612536004054              1
6      2009       1  1.05365365779321 0.282266634171568              1
8      2009       1  0.87403582415134 0.103774779139200              1
5      2009       1  1.15641679414676  0.33037984561357              1
  diffLRPosition
7     0.04032931
6     0.05365366
8     0.12596418
5     0.15641679

why when i write for LRPhase in c(1,-1), it gives me the result only for Phase =
1??

i want two results for Phase = 1 and Phase = -1????!!!

someone can help me please!!!

thank you
regards



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