[R] problem with using transace

Frank E Harrell Jr
Mon, 29 Nov 2004 17:57:08 -0000

anne.piotet at urbanet.ch wrote:
>>I am trying to use the Hmisc function transace to transform predictors
>>
>>test<-cbind(flowstress,pressres,alloy)
>>xtrans<-transace(x,binary=pressres',monotonic='flowstress',
categorical='alloy')
>>
>>
>>and I am getting the following message??
>>Error in ace(x[, -i], x[, i], monotone = im, categorical = ic) :
>>	unused argument(s) (monotone ...)
>>
>>Any idea?
>
>
> thanks anne
>
>>thank for your help
>>Anne

The corrected version (below) will fix that problem but note that there
is a bug in ace causing it not to allow a monotonicity constraint when a
variable is on the left hand side.  This is inconsistent with the ace
documentation.  There are other problems in ace in which it checks
column numbers against the number of rows in the x matrix instead of the
number of columns.  The internal version of ace defined inside areg.boot
fixes the latter problem.  Note that I reported these problems a long
time ago.

Frank

transace <- function(x, monotonic=NULL, categorical=NULL, binary=NULL,
pl=TRUE) {
   if(.R.) require('acepack')  # provides ace, avas

nam <- dimnames(x)[[2]]
omit <- is.na(x %*% rep(1,ncol(x)))
omitted <- (1:nrow(x))[omit]
if(length(omitted)) x <- x[!omit,]
p <- ncol(x)
xt <- x  # binary variables retain original coding
if(!length(nam)) stop("x must have column names")
rsq <- rep(NA, p)
names(rsq) <- nam


for(i in (1:p)[!(nam %in% binary)])	{
   lab <- nam[-i]
   w <- 1:(p-1)
   im <- w[lab %in% monotonic]
   ic <- w[lab %in% categorical]
   if(nam[i] %in% monotonic) im <- c(0, im)
   if(nam[i] %in% categorical) ic <- c(0, ic)
   m <- 10*(length(im)>0)+(length(ic)>0)
   if(m==11) a <- ace(x[,-i], x[,i], mon=im, cat=ic)
   else if (m==10) a <- ace(x[,-i], x[,i], mon=im)
   else if(m==1) a <- ace(x[,-i], x[,i], cat=ic)
   else a <- ace(x[,-i], x[,i])
   xt[,i] <- a$ty
   rsq[i] <- a$rsq
   if(pl)plot(x[,i], xt[,i], xlab=nam[i],
ylab=paste("Transformed",nam[i]))
}

cat("R-squared achieved in predicting each variable:\n\n")
print(rsq)

attr(xt, "rsq") <- rsq
attr(xt, "omitted") <- omitted
invisible(xt)
}

>>
>>
>
>
> ______________________________________________
> R-help at stat.math.ethz.ch mailing list
> https://stat.ethz.ch/mailman/listinfo/r-help
> PLEASE do read the posting guide!
http://www.R-project.org/posting-guide.html
>


--
Frank E Harrell Jr   Professor and Chair           School of Medicine
                      Department of Biostatistics   Vanderbilt University