[Rd] Aggregate factor names

Gabor Grothendieck
2007-09-27T16:06:09Z

You can do this:

aggregate(iris[-5], iris[5], mean)


On 9/27/07, Mike Lawrence <Mike.Lawrence at dal.ca>
wrote:
> Hi all,
>
> A suggestion derived from discussions amongst a number of R users in
> my research group: set the default column names produced by aggregate
> () equal to the names of the objects in the list passed to the 'by'
> object.
>
> ex. it is annoying to type
>
> with(
>        my.data
>        ,aggregate(
>                my.dv
>                ,list(
>                        one.iv = one.iv
>                        ,another.iv = another.iv
>                        ,yet.another.iv = yet.another.iv
>                )
>                ,some.function
>        )
> )
>
> to yield a data frame with names = c
>
('one.iv','another.iv','yet.another.iv','x')
when this seems more
> economical:
>
> with(
>        my.data
>        ,aggregate(
>                my.dv
>                ,list(
>                        one.iv
>                        ,another.iv
>                        ,yet.another.iv
>                )
>                ,some.function
>        )
> )
>
> --
> Mike Lawrence
> Graduate Student, Department of Psychology, Dalhousie University
>
> Website: http://memetic.ca
>
> Public calendar: http://icalx.com/public/informavore/Public
>
> "The road to wisdom? Well, it's plain and simple to express:
> Err and err and err again, but less and less and less."
>        - Piet Hein
>
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