R help - Sep 2024 - Is there a sexy way ...?

On 2024-09-26 11:55 p.m., Rolf Turner wrote:
> 
> I have (toy example):
> 
> x <- list(`1` = c(7, 13, 1, 4, 10),
>            `2` = c(2, 5,  14, 8, 11),
>            `3` = c(6, 9, 15, 12, 3))
> and
> 
> f <- factor(rep(1:3,5))
> 
> I want to create a vector v of length 15 such that the entries of v,
> corresponding to level l of f are the entries of x[[l]].  I.e. I want
> v to equal
> 
>      c(7, 2, 6, 13, 5, 9, 1, 14, 15, 4, 8, 12, 10, 11, 3)
> 
> I can create v "easily enough", using say, a for-loop.  It seems
to me,
> though, that there should be sexier (single command) way of achieving
> the desired result.  However I cannot devise one.
> 
Don't you find a for loop's naked display of intention to be sexy?

Duncan Murdoch

Oh glorious!? Thanks Duncan.

Fortune cookie nomination!

On 27/09/2024 11:13, Duncan Murdoch wrote:
> On 2024-09-26 11:55 p.m., Rolf Turner wrote:
>>
>> I have (toy example):
>>
>> x <- list(`1` = c(7, 13, 1, 4, 10),
>> ?????????? `2` = c(2, 5,? 14, 8, 11),
>> ?????????? `3` = c(6, 9, 15, 12, 3))
>> and
>>
>> f <- factor(rep(1:3,5))
>>
>> I want to create a vector v of length 15 such that the entries of v,
>> corresponding to level l of f are the entries of x[[l]].? I.e. I want
>> v to equal
>>
>> ???? c(7, 2, 6, 13, 5, 9, 1, 14, 15, 4, 8, 12, 10, 11, 3)
>>
>> I can create v "easily enough", using say, a for-loop.? It
seems to me,
>> though, that there should be sexier (single command) way of achieving
>> the desired result.? However I cannot devise one.
>>
>
> Don't you find a for loop's naked display of intention to be sexy?
>
> Duncan Murdoch
>
-- 
Chris Evans (he/him)
Visiting Professor, UDLA, Quito, Ecuador & Honorary Professor, 
University of Roehampton, London, UK.
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