On Tue, Oct 19, 2021 at 01:39:13PM +0530, Viresh Kumar
wrote:> +Greg.
>
> On 19-10-21, 09:46, Vincent Whitchurch wrote:
> > If a timeout is hit, it can result is incorrect data on the I2C bus
> > and/or memory corruptions in the guest since the device can still be
> > operating on the buffers it was given while the guest has freed them.
> >
> > Here is, for example, the start of a slub_debug splat which was
> > triggered on the next transfer after one transfer was forced to
timeout
> > by setting a breakpoint in the backend (rust-vmm/vhost-device):
> >
> > BUG kmalloc-1k (Not tainted): Poison overwritten
> > First byte 0x1 instead of 0x6b
> > Allocated in virtio_i2c_xfer+0x65/0x35c age=350 cpu=0 pid=29
> > __kmalloc+0xc2/0x1c9
> > virtio_i2c_xfer+0x65/0x35c
> > __i2c_transfer+0x429/0x57d
> > i2c_transfer+0x115/0x134
> > i2cdev_ioctl_rdwr+0x16a/0x1de
> > i2cdev_ioctl+0x247/0x2ed
> > vfs_ioctl+0x21/0x30
> > sys_ioctl+0xb18/0xb41
> > Freed in virtio_i2c_xfer+0x32e/0x35c age=244 cpu=0 pid=29
> > kfree+0x1bd/0x1cc
> > virtio_i2c_xfer+0x32e/0x35c
> > __i2c_transfer+0x429/0x57d
> > i2c_transfer+0x115/0x134
> > i2cdev_ioctl_rdwr+0x16a/0x1de
> > i2cdev_ioctl+0x247/0x2ed
> > vfs_ioctl+0x21/0x30
> > sys_ioctl+0xb18/0xb41
> >
> > There is no simple fix for this (the driver would have to always
create
> > bounce buffers and hold on to them until the device eventually returns
> > the buffers), so just disable the timeout support for now.
>
> That is a very valid problem, and I have faced it too when my QEMU
> setup is very slow :)
>
> > Signed-off-by: Vincent Whitchurch <vincent.whitchurch at
axis.com>
> > ---
> > drivers/i2c/busses/i2c-virtio.c | 14 +++++---------
> > 1 file changed, 5 insertions(+), 9 deletions(-)
> >
> > diff --git a/drivers/i2c/busses/i2c-virtio.c
b/drivers/i2c/busses/i2c-virtio.c
> > index f10a603b13fb..7b2474e6876f 100644
> > --- a/drivers/i2c/busses/i2c-virtio.c
> > +++ b/drivers/i2c/busses/i2c-virtio.c
> > @@ -106,11 +106,10 @@ static int virtio_i2c_prepare_reqs(struct
virtqueue *vq,
> >
> > static int virtio_i2c_complete_reqs(struct virtqueue *vq,
> > struct virtio_i2c_req *reqs,
> > - struct i2c_msg *msgs, int num,
> > - bool timedout)
> > + struct i2c_msg *msgs, int num)
> > {
> > struct virtio_i2c_req *req;
> > - bool failed = timedout;
> > + bool failed = false;
> > unsigned int len;
> > int i, j = 0;
> >
> > @@ -132,7 +131,7 @@ static int virtio_i2c_complete_reqs(struct
virtqueue *vq,
> > j++;
> > }
> >
> > - return timedout ? -ETIMEDOUT : j;
> > + return j;
> > }
> >
> > static int virtio_i2c_xfer(struct i2c_adapter *adap, struct i2c_msg
*msgs,
> > @@ -141,7 +140,6 @@ static int virtio_i2c_xfer(struct i2c_adapter
*adap, struct i2c_msg *msgs,
> > struct virtio_i2c *vi = i2c_get_adapdata(adap);
> > struct virtqueue *vq = vi->vq;
> > struct virtio_i2c_req *reqs;
> > - unsigned long time_left;
> > int count;
> >
> > reqs = kcalloc(num, sizeof(*reqs), GFP_KERNEL);
> > @@ -164,11 +162,9 @@ static int virtio_i2c_xfer(struct i2c_adapter
*adap, struct i2c_msg *msgs,
> > reinit_completion(&vi->completion);
> > virtqueue_kick(vq);
> >
> > - time_left = wait_for_completion_timeout(&vi->completion,
adap->timeout);
> > - if (!time_left)
> > - dev_err(&adap->dev, "virtio i2c backend
timeout.\n");
> > + wait_for_completion(&vi->completion);
>
> Doing this may not be a good thing based on the kernel rules I have
> understood until now. Maybe Greg and Wolfram can clarify on this.
>
> We are waiting here for an external entity (Host kernel) or a firmware
> that uses virtio for transport. If the other side is hacked, it can
> make the kernel hang here for ever. I thought that is something that
> the kernel should never do.
What is the "other side" here? Is it something that you trust or not?
Usually we trust the hardware, but if you do not trust the hardware,
then yes, you need to have a timeout here.
thanks,
greg k-h