I can get it to work with
ifelse(is.matrix(r), r[w!=0, , drop=FALSE], r[w!=0])
With w and r as defined r is not a matrix, so the first part will never
execute. The test is for w not equal to zero so it is always true for these
vectors. It is usually good to have test code such that all possible cases are
activated.
r<--1:8
w<- -1:5
if(is.matrix(r)){
r[w!=0, , drop=FALSE]
} else r[w != 0]
I think this also works. The "else" must follow the } and you put in a
carriage return after the }
I think that is the answer, but not 100% sure.
Tim
-----Original Message-----
From: R-help <r-help-bounces at r-project.org> On Behalf Of Andrew Simmons
Sent: Friday, October 21, 2022 5:37 AM
To: Jinsong Zhao <jszhao at yeah.net>
Cc: R-help Mailing List <r-help at r-project.org>
Subject: Re: [R] unexpected 'else' in " else"
[External Email]
The error comes from the expression not being wrapped with braces. You could
change it to
if (is.matrix(r)) {
r[w != 0, , drop = FALSE]
} else r[w != 0]
or
{
if (is.matrix(r))
r[w != 0, , drop = FALSE]
else r[w != 0]
}
or
if (is.matrix(r)) r[w != 0, , drop = FALSE] else r[w != 0]
On Fri., Oct. 21, 2022, 05:29 Jinsong Zhao, <jszhao at yeah.net> wrote:
> Hi there,
>
> The following code would cause R error:
>
> > w <- 1:5
> > r <- 1:5
> > if (is.matrix(r))
> + r[w != 0, , drop = FALSE]
> > else r[w != 0]
> Error: unexpected 'else' in " else"
>
> However, the code:
> if (is.matrix(r))
> r[w != 0, , drop = FALSE]
> else r[w != 0]
> is extracted from stats::weighted.residuals.
>
> My question is why the code in the function does not cause error?
>
> Best,
> Jinsong
>
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