R help - Feb 2022 - Convert a character string to variable names

"mtcars$disp" is not a variable name.
"mtcars" is a variable name, and
get("mtcars") will get the value of that variable
assign("mtcars", ~~whatever~~) will set it.
mtcars$disp is an *expression*,
where $ is an indexing operator
https://cran.r-project.org/doc/manuals/r-release/R-lang.html#Indexing
so what you want is
> mtcars <- list(cyl=4, disp=1.8)
> eval(parse(text="mtcars$disp"))
[1] 1.8

Though it's easy to do this, it's very seldom a good idea.
The combination of parse and eval can do ANYTHING, no matter
how disastrous.  Less powerful techniques are safer.
Where do these strings come from in the first place?
Why isn't it c("disp", "hp", "cyl")?

On Tue, 8 Feb 2022 at 11:56, Erin Hodgess <erinm.hodgess at gmail.com>
wrote:
> Hello!
>
> I have a character string that is a vector of variable names.  I would like
> to use those names to access the variables and create a matrix.
> I tried the following:
>
> > .x
>
> [1] "mtcars$disp" "mtcars$hp"   "mtcars$cyl"
>
> > .y <- NULL
>
> > for(i in 1:3) {
>
> + .y[i] <- c(as.name(.x[[i]]))
>
> + }
>
> > .y
>
> [[1]]
>
> `mtcars$disp`
>
>
> [[2]]
>
> `mtcars$hp`
>
>
> [[3]]
>
> `mtcars$cyl`
>
>
> But I am having trouble converting the variables in .y into a matrix.
>
>
> I tried all kinds of stuff with bquote, deparse, do.call, but no good.
>
>
> I have a feeling that it's something simple, and I'm just not
seeing it.
>
>
> Thanks,
>
> Erin
>
>
>
>
> Erin Hodgess, PhD
> mailto: erinm.hodgess at gmail.com
>
>         [[alternative HTML version deleted]]
>
> ______________________________________________
> R-help at r-project.org mailing list -- To UNSUBSCRIBE and more, see
> https://stat.ethz.ch/mailman/listinfo/r-help
> PLEASE do read the posting guide
> http://www.R-project.org/posting-guide.html
> and provide commented, minimal, self-contained, reproducible code.
>
	[[alternative HTML version deleted]]

I had thought that mtcars in "mtcars$disp" was the name of a dataframe
and that "disp" was the name of a column in the dataframe. If I would
make a model like horse power = displacement then "disp" would be a
variable in the model and I can find values for this variable in the
"disp" column in the "mtcars" dataframe. I am not sure how I
would use "mtcars" as a variable.
"mtcars$disp" has no specific value, though it will have a specific
value for any given row of data (assuming rows are observations).

Tim


-----Original Message-----
From: R-help <r-help-bounces at r-project.org> On Behalf Of Richard
O'Keefe
Sent: Tuesday, February 8, 2022 8:17 PM
To: Erin Hodgess <erinm.hodgess at gmail.com>
Cc: r-help at r-project.org
Subject: Re: [R] Convert a character string to variable names

[External Email]

"mtcars$disp" is not a variable name.
"mtcars" is a variable name, and
get("mtcars") will get the value of that variable
assign("mtcars", ~~whatever~~) will set it.
mtcars$disp is an *expression*,
where $ is an indexing operator
https://urldefense.proofpoint.com/v2/url?u=https-3A__cran.r-2Dproject.org_doc_manuals_r-2Drelease_R-2Dlang.html-23Indexing&d=DwICAg&c=sJ6xIWYx-zLMB3EPkvcnVg&r=9PEhQh2kVeAsRzsn7AkP-g&m=CI-7ZdIwlhUvhmOkVD7KJkv3IvSSWy4ix2Iz1netW81V-NUV8aOVVqyn5-fmD6cf&s=RjRC5kve6D8k59qZQYcX-PR-aA4TTu1yfLPBhHxSlWk&eso
what you want is
> mtcars <- list(cyl=4, disp=1.8)
> eval(parse(text="mtcars$disp"))
[1] 1.8

Though it's easy to do this, it's very seldom a good idea.
The combination of parse and eval can do ANYTHING, no matter how disastrous. 
Less powerful techniques are safer.
Where do these strings come from in the first place?
Why isn't it c("disp", "hp", "cyl")?

On Tue, 8 Feb 2022 at 11:56, Erin Hodgess <erinm.hodgess at gmail.com>
wrote:
> Hello!
>
> I have a character string that is a vector of variable names.  I would 
> like to use those names to access the variables and create a matrix.
> I tried the following:
>
> > .x
>
> [1] "mtcars$disp" "mtcars$hp"   "mtcars$cyl"
>
> > .y <- NULL
>
> > for(i in 1:3) {
>
> + .y[i] <- c(as.name(.x[[i]]))
>
> + }
>
> > .y
>
> [[1]]
>
> `mtcars$disp`
>
>
> [[2]]
>
> `mtcars$hp`
>
>
> [[3]]
>
> `mtcars$cyl`
>
>
> But I am having trouble converting the variables in .y into a matrix.
>
>
> I tried all kinds of stuff with bquote, deparse, do.call, but no good.
>
>
> I have a feeling that it's something simple, and I'm just not
seeing it.
>
>
> Thanks,
>
> Erin
>
>
>
>
> Erin Hodgess, PhD
> mailto: erinm.hodgess at gmail.com
>
>         [[alternative HTML version deleted]]
>
> ______________________________________________
> R-help at r-project.org mailing list -- To UNSUBSCRIBE and more, see 
> https://urldefense.proofpoint.com/v2/url?u=https-3A__stat.ethz.ch_mail
>
man_listinfo_r-2Dhelp&d=DwICAg&c=sJ6xIWYx-zLMB3EPkvcnVg&r=9PEhQh2kVeAs
> Rzsn7AkP-g&m=CI-7ZdIwlhUvhmOkVD7KJkv3IvSSWy4ix2Iz1netW81V-NUV8aOVVqyn5
> -fmD6cf&s=c8oCLZK8TFAAs5d3vhDyB52KR2I9WWSTg6kDjL8orcI&e> PLEASE
do read the posting guide
> https://urldefense.proofpoint.com/v2/url?u=http-3A__www.R-2Dproject.or
>
g_posting-2Dguide.html&d=DwICAg&c=sJ6xIWYx-zLMB3EPkvcnVg&r=9PEhQh2kVeA
> sRzsn7AkP-g&m=CI-7ZdIwlhUvhmOkVD7KJkv3IvSSWy4ix2Iz1netW81V-NUV8aOVVqyn
> 5-fmD6cf&s=fTO2Qrx6DmlzcB2uqN4fsDmTMVZwfCsDbLtzMigHWXI&e> and
provide commented, minimal, self-contained, reproducible code.
>
        [[alternative HTML version deleted]]

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do read the posting guide
https://urldefense.proofpoint.com/v2/url?u=http-3A__www.R-2Dproject.org_posting-2Dguide.html&d=DwICAg&c=sJ6xIWYx-zLMB3EPkvcnVg&r=9PEhQh2kVeAsRzsn7AkP-g&m=CI-7ZdIwlhUvhmOkVD7KJkv3IvSSWy4ix2Iz1netW81V-NUV8aOVVqyn5-fmD6cf&s=fTO2Qrx6DmlzcB2uqN4fsDmTMVZwfCsDbLtzMigHWXI&eand
provide commented, minimal, self-contained, reproducible code.