Laurent Rhelp
2021-Jul-09 17:40 UTC
[R] How to create a matrix from a list without a for loop
Dear R-Help-list, ? I have a list init_l containing 16 dataframes and I want to create a matrix 4 x 4 from this list with a dataframe in every cell of the matrix. I succeeded to do that but my loop is very uggly (cf. below). Could somebody help me to write nice R code to do this loop ? Thank you very much Laurent ## ## mock data, 16 dataframes in a list ## init_l <- lapply( seq(1,16) , function(x) { ? data.frame( V1 = rnorm(3), ????????????? V2 = rnorm(3), ????????????? V3 = rnorm(3) ??????????? ) }) ## ## lists matrix creation with n = 4 columns and n = 4 rows ## n <- 4 ## an example of row to create the matrix with lists in the cells one_row <- rbind( rep( list(rep(list(1),3)) , n) ) mymat <- do.call( "rbind" , rep( list(one_row) , n) ) ## ## The UGGLY loop I would like to improve: ## ## populate the matrix k <- 1 for( i in 1:n){ ? for( j in 1:n){ ??? mymat[i,j][[1]] <- list( init_l[[ k ]] ) ??? k <- k+1 ? } } colnames(mymat) <- c("X1", "X2", "X3", "X3") rownames(mymat) <- c("X1", "X2", "X3", "X4") mymat # X1???? X2???? X3???? X3 # X1 List,1 List,1 List,1 List,1 # X2 List,1 List,1 List,1 List,1 # X3 List,1 List,1 List,1 List,1 # X4 List,1 List,1 List,1 List,1 # # verification, it works # mymat[2,2] init_l[[6]] ## init_l[[6]] library(tidyverse) mymat.t <- as.tibble(mymat) mymat.t unnest(mymat.t[2,2],cols="X2")[[1]][[1]] mymat.df <- as.data.frame(mymat) mymat.df[2,2][[1]][[1]] thx -- L'absence de virus dans ce courrier ?lectronique a ?t? v?rifi?e par le logiciel antivirus Avast. https://www.avast.com/antivirus
Bill Dunlap
2021-Jul-09 17:50 UTC
[R] How to create a matrix from a list without a for loop
Try matrix(init_l, nrow=4, ncol=4, dimnames=list(c("X1","X2","X3","X4"),c("X1","X2","X3","X4"))) It doesn't give exactly what your code does, but your code introduces an extra level of "list", which you may not want. -Bill On Fri, Jul 9, 2021 at 10:40 AM Laurent Rhelp <LaurentRHelp at free.fr> wrote:> Dear R-Help-list, > > I have a list init_l containing 16 dataframes and I want to create a > matrix 4 x 4 from this list with a dataframe in every cell of the > matrix. I succeeded to do that but my loop is very uggly (cf. below). > Could somebody help me to write nice R code to do this loop ? > > Thank you very much > > Laurent > > > ## > ## mock data, 16 dataframes in a list > ## > init_l <- lapply( seq(1,16) , function(x) { > data.frame( V1 = rnorm(3), > V2 = rnorm(3), > V3 = rnorm(3) > ) > }) > > ## > ## lists matrix creation with n = 4 columns and n = 4 rows > ## > n <- 4 > ## an example of row to create the matrix with lists in the cells > one_row <- rbind( rep( list(rep(list(1),3)) , n) ) > mymat <- do.call( "rbind" , rep( list(one_row) , n) ) > > ## > ## The UGGLY loop I would like to improve: > ## > > ## populate the matrix > k <- 1 > for( i in 1:n){ > for( j in 1:n){ > mymat[i,j][[1]] <- list( init_l[[ k ]] ) > k <- k+1 > } > } > > colnames(mymat) <- c("X1", "X2", "X3", "X3") > rownames(mymat) <- c("X1", "X2", "X3", "X4") > > > mymat > > # X1 X2 X3 X3 > # X1 List,1 List,1 List,1 List,1 > # X2 List,1 List,1 List,1 List,1 > # X3 List,1 List,1 List,1 List,1 > # X4 List,1 List,1 List,1 List,1 > > > # > # verification, it works > # > mymat[2,2] > init_l[[6]] > > ## > init_l[[6]] > > library(tidyverse) > mymat.t <- as.tibble(mymat) > mymat.t > unnest(mymat.t[2,2],cols="X2")[[1]][[1]] > > mymat.df <- as.data.frame(mymat) > mymat.df[2,2][[1]][[1]] > > > thx > > > > -- > L'absence de virus dans ce courrier ?lectronique a ?t? v?rifi?e par le > logiciel antivirus Avast. > https://www.avast.com/antivirus > > ______________________________________________ > R-help at r-project.org mailing list -- To UNSUBSCRIBE and more, see > https://stat.ethz.ch/mailman/listinfo/r-help > PLEASE do read the posting guide > http://www.R-project.org/posting-guide.html > and provide commented, minimal, self-contained, reproducible code. >[[alternative HTML version deleted]]
David Winsemius
2021-Jul-09 17:50 UTC
[R] How to create a matrix from a list without a for loop
On 7/9/21 10:40 AM, Laurent Rhelp wrote:> Dear R-Help-list, > > ? I have a list init_l containing 16 dataframes and I want to create a > matrix 4 x 4 from this list with a dataframe in every cell of the > matrix. I succeeded to do that but my loop is very uggly (cf. below). > Could somebody help me to write nice R code to do this loop ? > > Thank you very much > > Laurent > > > ## > ## mock data, 16 dataframes in a list > ## > init_l <- lapply( seq(1,16) , function(x) { > ? data.frame( V1 = rnorm(3), > ????????????? V2 = rnorm(3), > ????????????? V3 = rnorm(3) > ??????????? ) > }) > > ## > ## lists matrix creation with n = 4 columns and n = 4 rows > ## > n <- 4Just assign a dimension attribute and you will have your two dimensional structure > dim(init_l) <- c(n,n) > init_l[ 2,2] [[1]] ????????? V1???????? V2???????? V3 1 -1.4103259? 1.9214184 -0.1590919 2? 0.1899490? 0.3842191? 2.4502078 3 -0.4282764 -0.9992190? 1.5384344 > is.matrix(init_l) [1] TRUE -- David> ## an example of row to create the matrix with lists in the cells > one_row <- rbind( rep( list(rep(list(1),3)) , n) ) > mymat <- do.call( "rbind" , rep( list(one_row) , n) ) > > ## > ## The UGGLY loop I would like to improve: > ## > > ## populate the matrix > k <- 1 > for( i in 1:n){ > ? for( j in 1:n){ > ??? mymat[i,j][[1]] <- list( init_l[[ k ]] ) > ??? k <- k+1 > ? } > } > > colnames(mymat) <- c("X1", "X2", "X3", "X3") > rownames(mymat) <- c("X1", "X2", "X3", "X4") > > > mymat > > # X1???? X2???? X3???? X3 > # X1 List,1 List,1 List,1 List,1 > # X2 List,1 List,1 List,1 List,1 > # X3 List,1 List,1 List,1 List,1 > # X4 List,1 List,1 List,1 List,1 > > > # > # verification, it works > # > mymat[2,2] > init_l[[6]] > > ## > init_l[[6]] > > library(tidyverse) > mymat.t <- as.tibble(mymat) > mymat.t > unnest(mymat.t[2,2],cols="X2")[[1]][[1]] > > mymat.df <- as.data.frame(mymat) > mymat.df[2,2][[1]][[1]] > > > thx > > >