Better, I think (no indexing): t(apply(somematrix,1,function(x)pmin(x,UB))) Bert Gunter "The trouble with having an open mind is that people keep coming along and sticking things into it." -- Opus (aka Berkeley Breathed in his "Bloom County" comic strip ) On Wed, May 27, 2020 at 10:56 AM Rui Barradas <ruipbarradas at sapo.pt> wrote:> Hello, > > Try pmin. And loop by column/UB index with sapply/seq_along. > > > sapply(seq_along(UB), function(i) pmin(UB[i], somematrix[,i])) > # [,1] [,2] [,3] [,4] > #[1,] 1.0 5.5 8.5 7.0 > #[2,] 2.5 3.0 8.0 10.5 > #[3,] 2.5 5.5 5.0 10.5 > > > Hope this helps, > > Rui Barradas > > > ?s 18:46 de 27/05/20, Michael Ashton escreveu: > > Hi - > > > > I have a matrix of n rows and 4 columns. > > > > I want to cap the value in each column by a different upper bound. So, > suppose my matrix is > > > > somematrix <- matrix(c(1,4,3,6,3,9,12,8,5,7,11,11),nrow=3,ncol=4) > >> somematrix > > [,1] [,2] [,3] [,4] > > [1,] 1 6 12 7 > > [2,] 4 3 8 11 > > [3,] 3 9 5 11 > > > > Now I want to have the maximum value in each column described by > > UB=c(2.5, 5.5, 8.5, 10.5) > > > > So that the right answer will look like: > > [,1] [,2] [,3] [,4] > > [1,] 1 5.5 8.5 7 > > [2,] 2.5 3 8 10.5 > > [3,] 2.5 5.5 5 10.5 > > > > I've tried a few things, like: > > newmatrix <- apply(somematrix,c(1,2),function(x) min(UB,x)) > > > > but I can't figure out to apply the relevant element of the UB list to > the right element of the matrix. When I run the above, for example, it > takes min(UB,x) over all UB, so I get: > > > > newmatrix > > [,1] [,2] [,3] [,4] > > [1,] 1.0 2.5 2.5 2.5 > > [2,] 2.5 2.5 2.5 2.5 > > [3,] 2.5 2.5 2.5 2.5 > > > > I'm sure there's a simple and elegant solution but I don't know what it > is! > > > > Thanks in advance, > > > > Mike > > > > Michael Ashton, CFA > > Managing Principal > > > > Enduring Investments LLC > > W: 973.457.4602 > > C: 551.655.8006 > > Schedule a Call: https://calendly.com/m-ashton > > > > > > [[alternative HTML version deleted]] > > > > ______________________________________________ > > R-help at r-project.org mailing list -- To UNSUBSCRIBE and more, see > > https://stat.ethz.ch/mailman/listinfo/r-help > > PLEASE do read the posting guide > http://www.R-project.org/posting-guide.html > > and provide commented, minimal, self-contained, reproducible code. > > > > ______________________________________________ > R-help at r-project.org mailing list -- To UNSUBSCRIBE and more, see > https://stat.ethz.ch/mailman/listinfo/r-help > PLEASE do read the posting guide > http://www.R-project.org/posting-guide.html > and provide commented, minimal, self-contained, reproducible code. >[[alternative HTML version deleted]]
Always amazes me how many ways there are to do these things, none of which I was able to find myself. Thanks! I think the key here was ?pmin,? which I didn?t know before. Michael Ashton, CFA Managing Principal Enduring Investments LLC W: 973.457.4602 C: 551.655.8006 Schedule a Call: https://calendly.com/m-ashton From: Bert Gunter [mailto:bgunter.4567 at gmail.com] Sent: Wednesday, May 27, 2020 2:22 PM To: Rui Barradas Cc: Michael Ashton; r-help at r-project.org Subject: Re: [R] struggling with apply Better, I think (no indexing): t(apply(somematrix,1,function(x)pmin(x,UB))) Bert Gunter "The trouble with having an open mind is that people keep coming along and sticking things into it." -- Opus (aka Berkeley Breathed in his "Bloom County" comic strip ) On Wed, May 27, 2020 at 10:56 AM Rui Barradas <ruipbarradas at sapo.pt<mailto:ruipbarradas at sapo.pt>> wrote: Hello, Try pmin. And loop by column/UB index with sapply/seq_along. sapply(seq_along(UB), function(i) pmin(UB[i], somematrix[,i])) # [,1] [,2] [,3] [,4] #[1,] 1.0 5.5 8.5 7.0 #[2,] 2.5 3.0 8.0 10.5 #[3,] 2.5 5.5 5.0 10.5 Hope this helps, Rui Barradas ?s 18:46 de 27/05/20, Michael Ashton escreveu:> Hi - > > I have a matrix of n rows and 4 columns. > > I want to cap the value in each column by a different upper bound. So, suppose my matrix is > > somematrix <- matrix(c(1,4,3,6,3,9,12,8,5,7,11,11),nrow=3,ncol=4) >> somematrix > [,1] [,2] [,3] [,4] > [1,] 1 6 12 7 > [2,] 4 3 8 11 > [3,] 3 9 5 11 > > Now I want to have the maximum value in each column described by > UB=c(2.5, 5.5, 8.5, 10.5) > > So that the right answer will look like: > [,1] [,2] [,3] [,4] > [1,] 1 5.5 8.5 7 > [2,] 2.5 3 8 10.5 > [3,] 2.5 5.5 5 10.5 > > I've tried a few things, like: > newmatrix <- apply(somematrix,c(1,2),function(x) min(UB,x)) > > but I can't figure out to apply the relevant element of the UB list to the right element of the matrix. When I run the above, for example, it takes min(UB,x) over all UB, so I get: > > newmatrix > [,1] [,2] [,3] [,4] > [1,] 1.0 2.5 2.5 2.5 > [2,] 2.5 2.5 2.5 2.5 > [3,] 2.5 2.5 2.5 2.5 > > I'm sure there's a simple and elegant solution but I don't know what it is! > > Thanks in advance, > > Mike > > Michael Ashton, CFA > Managing Principal > > Enduring Investments LLC > W: 973.457.4602 > C: 551.655.8006 > Schedule a Call: https://calendly.com/m-ashton > > > [[alternative HTML version deleted]] > > ______________________________________________ > R-help at r-project.org<mailto:R-help at r-project.org> mailing list -- To UNSUBSCRIBE and more, see > https://stat.ethz.ch/mailman/listinfo/r-help > PLEASE do read the posting guide http://www.R-project.org/posting-guide.html > and provide commented, minimal, self-contained, reproducible code. >______________________________________________ R-help at r-project.org<mailto:R-help at r-project.org> mailing list -- To UNSUBSCRIBE and more, see https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code. [[alternative HTML version deleted]]
Sigh. Transpose? apply( somematrix, 2, function( x ) pmin( x, UB ) ) On May 27, 2020 11:22:06 AM PDT, Bert Gunter <bgunter.4567 at gmail.com> wrote:>Better, I think (no indexing): > >t(apply(somematrix,1,function(x)pmin(x,UB))) > > >Bert Gunter > >"The trouble with having an open mind is that people keep coming along >and >sticking things into it." >-- Opus (aka Berkeley Breathed in his "Bloom County" comic strip ) > > >On Wed, May 27, 2020 at 10:56 AM Rui Barradas <ruipbarradas at sapo.pt> >wrote: > >> Hello, >> >> Try pmin. And loop by column/UB index with sapply/seq_along. >> >> >> sapply(seq_along(UB), function(i) pmin(UB[i], somematrix[,i])) >> # [,1] [,2] [,3] [,4] >> #[1,] 1.0 5.5 8.5 7.0 >> #[2,] 2.5 3.0 8.0 10.5 >> #[3,] 2.5 5.5 5.0 10.5 >> >> >> Hope this helps, >> >> Rui Barradas >> >> >> ?s 18:46 de 27/05/20, Michael Ashton escreveu: >> > Hi - >> > >> > I have a matrix of n rows and 4 columns. >> > >> > I want to cap the value in each column by a different upper bound. >So, >> suppose my matrix is >> > >> > somematrix <- matrix(c(1,4,3,6,3,9,12,8,5,7,11,11),nrow=3,ncol=4) >> >> somematrix >> > [,1] [,2] [,3] [,4] >> > [1,] 1 6 12 7 >> > [2,] 4 3 8 11 >> > [3,] 3 9 5 11 >> > >> > Now I want to have the maximum value in each column described by >> > UB=c(2.5, 5.5, 8.5, 10.5) >> > >> > So that the right answer will look like: >> > [,1] [,2] [,3] [,4] >> > [1,] 1 5.5 8.5 7 >> > [2,] 2.5 3 8 10.5 >> > [3,] 2.5 5.5 5 10.5 >> > >> > I've tried a few things, like: >> > newmatrix <- apply(somematrix,c(1,2),function(x) min(UB,x)) >> > >> > but I can't figure out to apply the relevant element of the UB list >to >> the right element of the matrix. When I run the above, for example, >it >> takes min(UB,x) over all UB, so I get: >> > >> > newmatrix >> > [,1] [,2] [,3] [,4] >> > [1,] 1.0 2.5 2.5 2.5 >> > [2,] 2.5 2.5 2.5 2.5 >> > [3,] 2.5 2.5 2.5 2.5 >> > >> > I'm sure there's a simple and elegant solution but I don't know >what it >> is! >> > >> > Thanks in advance, >> > >> > Mike >> > >> > Michael Ashton, CFA >> > Managing Principal >> > >> > Enduring Investments LLC >> > W: 973.457.4602 >> > C: 551.655.8006 >> > Schedule a Call: https://calendly.com/m-ashton >> > >> > >> > [[alternative HTML version deleted]] >> > >> > ______________________________________________ >> > R-help at r-project.org mailing list -- To UNSUBSCRIBE and more, see >> > https://stat.ethz.ch/mailman/listinfo/r-help >> > PLEASE do read the posting guide >> http://www.R-project.org/posting-guide.html >> > and provide commented, minimal, self-contained, reproducible code. >> > >> >> ______________________________________________ >> R-help at r-project.org mailing list -- To UNSUBSCRIBE and more, see >> https://stat.ethz.ch/mailman/listinfo/r-help >> PLEASE do read the posting guide >> http://www.R-project.org/posting-guide.html >> and provide commented, minimal, self-contained, reproducible code. >> > > [[alternative HTML version deleted]] > >______________________________________________ >R-help at r-project.org mailing list -- To UNSUBSCRIBE and more, see >https://stat.ethz.ch/mailman/listinfo/r-help >PLEASE do read the posting guide >http://www.R-project.org/posting-guide.html >and provide commented, minimal, self-contained, reproducible code.-- Sent from my phone. Please excuse my brevity.
Jeff: Check it!> somematrix <- matrix(c(1,4,3,6,3,9,12,8,5,7,11,11),nrow=3,ncol=4) > UB=c(2.5, 5.5, 8.5, 10.5) > apply( somematrix, 2, function( x ) pmin( x, UB ) )[,1] [,2] [,3] [,4] [1,] 1 2.5 2.5 2.5 [2,] 4 3.0 5.5 5.5 [3,] 3 8.5 5.0 8.5 [4,] 1 6.0 10.5 7.0 Not what was wanted. Am I missing something? Bert Gunter "The trouble with having an open mind is that people keep coming along and sticking things into it." -- Opus (aka Berkeley Breathed in his "Bloom County" comic strip ) On Wed, May 27, 2020 at 12:38 PM Jeff Newmiller <jdnewmil at dcn.davis.ca.us> wrote:> Sigh. Transpose? > > apply( somematrix, 2, function( x ) pmin( x, UB ) ) > > On May 27, 2020 11:22:06 AM PDT, Bert Gunter <bgunter.4567 at gmail.com> > wrote: > >Better, I think (no indexing): > > > >t(apply(somematrix,1,function(x)pmin(x,UB))) > > > > > >Bert Gunter > > > >"The trouble with having an open mind is that people keep coming along > >and > >sticking things into it." > >-- Opus (aka Berkeley Breathed in his "Bloom County" comic strip ) > > > > > >On Wed, May 27, 2020 at 10:56 AM Rui Barradas <ruipbarradas at sapo.pt> > >wrote: > > > >> Hello, > >> > >> Try pmin. And loop by column/UB index with sapply/seq_along. > >> > >> > >> sapply(seq_along(UB), function(i) pmin(UB[i], somematrix[,i])) > >> # [,1] [,2] [,3] [,4] > >> #[1,] 1.0 5.5 8.5 7.0 > >> #[2,] 2.5 3.0 8.0 10.5 > >> #[3,] 2.5 5.5 5.0 10.5 > >> > >> > >> Hope this helps, > >> > >> Rui Barradas > >> > >> > >> ?s 18:46 de 27/05/20, Michael Ashton escreveu: > >> > Hi - > >> > > >> > I have a matrix of n rows and 4 columns. > >> > > >> > I want to cap the value in each column by a different upper bound. > >So, > >> suppose my matrix is > >> > > >> > somematrix <- matrix(c(1,4,3,6,3,9,12,8,5,7,11,11),nrow=3,ncol=4) > >> >> somematrix > >> > [,1] [,2] [,3] [,4] > >> > [1,] 1 6 12 7 > >> > [2,] 4 3 8 11 > >> > [3,] 3 9 5 11 > >> > > >> > Now I want to have the maximum value in each column described by > >> > UB=c(2.5, 5.5, 8.5, 10.5) > >> > > >> > So that the right answer will look like: > >> > [,1] [,2] [,3] [,4] > >> > [1,] 1 5.5 8.5 7 > >> > [2,] 2.5 3 8 10.5 > >> > [3,] 2.5 5.5 5 10.5 > >> > > >> > I've tried a few things, like: > >> > newmatrix <- apply(somematrix,c(1,2),function(x) min(UB,x)) > >> > > >> > but I can't figure out to apply the relevant element of the UB list > >to > >> the right element of the matrix. When I run the above, for example, > >it > >> takes min(UB,x) over all UB, so I get: > >> > > >> > newmatrix > >> > [,1] [,2] [,3] [,4] > >> > [1,] 1.0 2.5 2.5 2.5 > >> > [2,] 2.5 2.5 2.5 2.5 > >> > [3,] 2.5 2.5 2.5 2.5 > >> > > >> > I'm sure there's a simple and elegant solution but I don't know > >what it > >> is! > >> > > >> > Thanks in advance, > >> > > >> > Mike > >> > > >> > Michael Ashton, CFA > >> > Managing Principal > >> > > >> > Enduring Investments LLC > >> > W: 973.457.4602 > >> > C: 551.655.8006 > >> > Schedule a Call: https://calendly.com/m-ashton > >> > > >> > > >> > [[alternative HTML version deleted]] > >> > > >> > ______________________________________________ > >> > R-help at r-project.org mailing list -- To UNSUBSCRIBE and more, see > >> > https://stat.ethz.ch/mailman/listinfo/r-help > >> > PLEASE do read the posting guide > >> http://www.R-project.org/posting-guide.html > >> > and provide commented, minimal, self-contained, reproducible code. > >> > > >> > >> ______________________________________________ > >> R-help at r-project.org mailing list -- To UNSUBSCRIBE and more, see > >> https://stat.ethz.ch/mailman/listinfo/r-help > >> PLEASE do read the posting guide > >> http://www.R-project.org/posting-guide.html > >> and provide commented, minimal, self-contained, reproducible code. > >> > > > > [[alternative HTML version deleted]] > > > >______________________________________________ > >R-help at r-project.org mailing list -- To UNSUBSCRIBE and more, see > >https://stat.ethz.ch/mailman/listinfo/r-help > >PLEASE do read the posting guide > >http://www.R-project.org/posting-guide.html > >and provide commented, minimal, self-contained, reproducible code. > > -- > Sent from my phone. Please excuse my brevity. >[[alternative HTML version deleted]]