R help - Oct 2019 - using a variable and a superscript in a legend

Dear listers,

I am trying to pass an expression inlcuding a variable and a 
superpscript to a legend. What I want to obtain is e.g. with densren = 1.25

1.25 ind./km^2

I have tried many variants of the following:

legend=bquote(.(densren) (ind./km)^2)

but if not errors, do obtain

1.25 (ind./km^2)

hence not what I want (no parenthesis, 2 in superscript...)

Any idea about a correct syntax to get what I need ?

Best,

Patrick


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I did a Google search on

R plot superscript in legend

and the first search result was
https://stackoverflow.com/questions/20453408/superscript-r-squared-for-legend

 which looks like it might address your question.

On Sun, Oct 20, 2019 at 3:30 PM Patrick Giraudoux <
patrick.giraudoux at univ-fcomte.fr> wrote:
> Dear listers,
>
> I am trying to pass an expression inlcuding a variable and a
> superpscript to a legend. What I want to obtain is e.g. with densren = 1.25
>
> 1.25 ind./km^2
>
> I have tried many variants of the following:
>
> legend=bquote(.(densren) (ind./km)^2)
>
> but if not errors, do obtain
>
> 1.25 (ind./km^2)
>
> hence not what I want (no parenthesis, 2 in superscript...)
>
> Any idea about a correct syntax to get what I need ?
>
> Best,
>
> Patrick
>
>
>         [[alternative HTML version deleted]]
>
> ______________________________________________
> R-help at r-project.org mailing list -- To UNSUBSCRIBE and more, see
> https://stat.ethz.ch/mailman/listinfo/r-help
> PLEASE do read the posting guide
> http://www.R-project.org/posting-guide.html
> and provide commented, minimal, self-contained, reproducible code.
>
	[[alternative HTML version deleted]]

Thanks Eric. I got it too already (and already tried some variations 
based on it), but to my understanding it does not include a variable 
whose contents is used in the expression as in the case submitted...


Le 20/10/2019 ? 14:56, Eric Berger a ?crit?:
> I did a Google search on
>
> R plot superscript in legend
>
> and the first search result was
>
https://stackoverflow.com/questions/20453408/superscript-r-squared-for-legend
>
> ?which looks like it might address your question.
>
> On Sun, Oct 20, 2019 at 3:30 PM Patrick Giraudoux 
> <patrick.giraudoux at univ-fcomte.fr 
> <mailto:patrick.giraudoux at univ-fcomte.fr>> wrote:
>
>     Dear listers,
>
>     I am trying to pass an expression inlcuding a variable and a
>     superpscript to a legend. What I want to obtain is e.g. with
>     densren = 1.25
>
>     1.25 ind./km^2
>
>     I have tried many variants of the following:
>
>     legend=bquote(.(densren) (ind./km)^2)
>
>     but if not errors, do obtain
>
>     1.25 (ind./km^2)
>
>     hence not what I want (no parenthesis, 2 in superscript...)
>
>     Any idea about a correct syntax to get what I need ?
>
>     Best,
>
>     Patrick
>
>
>     ? ? ? ? [[alternative HTML version deleted]]
>
>     ______________________________________________
>     R-help at r-project.org <mailto:R-help at r-project.org> mailing
list --
>     To UNSUBSCRIBE and more, see
>     https://stat.ethz.ch/mailman/listinfo/r-help
>     PLEASE do read the posting guide
>     http://www.R-project.org/posting-guide.html
>     and provide commented, minimal, self-contained, reproducible code.
>

	[[alternative HTML version deleted]]

Assuming you are using base graphics, your syntax for adding the legend
appears to be wrong.
legend() is a separate function, not a parameter of plot.default afaics.

The following works for me:
> densren <- 1.25
> plot(1:10)
> legend (x="center", legend =bquote(.(densren) (ind./km)^2))
See ?legend

Bert Gunter

"The trouble with having an open mind is that people keep coming along and
sticking things into it."
-- Opus (aka Berkeley Breathed in his "Bloom County" comic strip )


On Sun, Oct 20, 2019 at 5:30 AM Patrick Giraudoux <
patrick.giraudoux at univ-fcomte.fr> wrote:
> Dear listers,
>
> I am trying to pass an expression inlcuding a variable and a
> superpscript to a legend. What I want to obtain is e.g. with densren = 1.25
>
> 1.25 ind./km^2
>
> I have tried many variants of the following:
>
> legend=bquote(.(densren) (ind./km)^2)
>
> but if not errors, do obtain
>
> 1.25 (ind./km^2)
>
> hence not what I want (no parenthesis, 2 in superscript...)
>
> Any idea about a correct syntax to get what I need ?
>
> Best,
>
> Patrick
>
>
>         [[alternative HTML version deleted]]
>
> ______________________________________________
> R-help at r-project.org mailing list -- To UNSUBSCRIBE and more, see
> https://stat.ethz.ch/mailman/listinfo/r-help
> PLEASE do read the posting guide
> http://www.R-project.org/posting-guide.html
> and provide commented, minimal, self-contained, reproducible code.
>
	[[alternative HTML version deleted]]

Thanks Bert and Peter,

Yes Bert, I was aware of the legend() function syntax, and just quoting 
the legend argument within the function.

However, Bert and Peter, I do not understand why it works with your 
absolutely reproducible examples and not in the slightly (not so 
slightly apparently) different context where I used it...

densren=1.25
plot(1:100,1:100,type="n")
legend(list(x=0,y=100),legend=c("Sans renard",bquote(.(densren) 
(ind./km)^2)),lty=c(1,2),col=c("black","red"),bty="n")

densren=1.25
plot(1:100,1:100,type="n")
legend(list(x=0,y=100),legend=c("Sans renard",bquote(.(densren) *
"
ind."/"km"^2)),lty=c(1,2),col=c("black","red"),bty="n"

Probably because the result of bquote() is concatenated in a character 
vector, but how to deal with this ?

Best,

Patrick



Le 20/10/2019 ? 16:42, Bert Gunter a ?crit?:
> Assuming you are using base graphics, your syntax for adding the 
> legend appears to be wrong.
> legend() is a separate function, not a parameter of plot.default afaics.
>
> The following works for me:
>
> > densren <- 1.25
> > plot(1:10)
> > legend (x="center", legend =bquote(.(densren) (ind./km)^2))
>
> See ?legend
>
> Bert Gunter
>
> "The trouble with having an open mind is that people keep coming along
> and sticking things into it."
> -- Opus (aka Berkeley Breathed in his "Bloom County" comic strip
)
>
>
> On Sun, Oct 20, 2019 at 5:30 AM Patrick Giraudoux 
> <patrick.giraudoux at univ-fcomte.fr 
> <mailto:patrick.giraudoux at univ-fcomte.fr>> wrote:
>
>     Dear listers,
>
>     I am trying to pass an expression inlcuding a variable and a
>     superpscript to a legend. What I want to obtain is e.g. with
>     densren = 1.25
>
>     1.25 ind./km^2
>
>     I have tried many variants of the following:
>
>     legend=bquote(.(densren) (ind./km)^2)
>
>     but if not errors, do obtain
>
>     1.25 (ind./km^2)
>
>     hence not what I want (no parenthesis, 2 in superscript...)
>
>     Any idea about a correct syntax to get what I need ?
>
>     Best,
>
>     Patrick
>
>
>     ? ? ? ? [[alternative HTML version deleted]]
>
>     ______________________________________________
>     R-help at r-project.org <mailto:R-help at r-project.org> mailing
list --
>     To UNSUBSCRIBE and more, see
>     https://stat.ethz.ch/mailman/listinfo/r-help
>     PLEASE do read the posting guide
>     http://www.R-project.org/posting-guide.html
>     and provide commented, minimal, self-contained, reproducible code.
>

	[[alternative HTML version deleted]]