i am a beginner regarding R but i am trying to do a simple thing, but it is
taking too much time and i am asking if there is any way to achieve what i
need, i have a time series data set with 730 data points, i detected 7, 354
and 365 seasonality periods. i am trying to use Fourier terms for
seasonality and for loop to get the K value for each while minimizing AICc,
my code is
AICc<- data.table(matrix(nrow = 96642, ncol = 4))for (i in 1:3) {
for (j in 1:177) {
for (k in 182) { #i,j and k values are choosen
with regad that K cannot exceed seasonality period/2
z1 <- fourier(ts(demand,frequency = 7), K=i)
z2 <- fourier(ts(demand,frequency=354), K=j)
z3 <- fourier(ts(demand,frequency = 365),K=k)
fit <- auto.arima(demand, xreg =cbind(z1,z2,z3),
seasonal = FALSE)
fit$aicc
AICc[,1]<-i
AICc[,2]<-j
AICc[,3]<-k
AICc[,4]<-fit$aicc
}
}
}
AICc
i have created a data table to store AICc values from all possible i,j,k
combinations so that i can find later the minimum AICc value. the problem
now is that it is taking forever to do so not only to iterate all
combinations but also due to the large K values.
, is there any possible solution for this? thank you in advance
[[alternative HTML version deleted]]
This is not an answer to your speed problem but are your assignments to AICc[,1] and so on doing what you hope they are doing? Michael On 06/02/2019 12:03, salah maadawy wrote:> i am a beginner regarding R but i am trying to do a simple thing, but it is > taking too much time and i am asking if there is any way to achieve what i > need, i have a time series data set with 730 data points, i detected 7, 354 > and 365 seasonality periods. i am trying to use Fourier terms for > seasonality and for loop to get the K value for each while minimizing AICc, > my code is > > AICc<- data.table(matrix(nrow = 96642, ncol = 4))for (i in 1:3) { > for (j in 1:177) { > for (k in 182) { #i,j and k values are choosen > with regad that K cannot exceed seasonality period/2 > z1 <- fourier(ts(demand,frequency = 7), K=i) > z2 <- fourier(ts(demand,frequency=354), K=j) > z3 <- fourier(ts(demand,frequency = 365),K=k) > fit <- auto.arima(demand, xreg =cbind(z1,z2,z3), > seasonal = FALSE) > fit$aicc > AICc[,1]<-i > AICc[,2]<-j > AICc[,3]<-k > AICc[,4]<-fit$aicc > } > > } > } > AICc > > i have created a data table to store AICc values from all possible i,j,k > combinations so that i can find later the minimum AICc value. the problem > now is that it is taking forever to do so not only to iterate all > combinations but also due to the large K values. > > , is there any possible solution for this? thank you in advance > > [[alternative HTML version deleted]] > > ______________________________________________ > R-help at r-project.org mailing list -- To UNSUBSCRIBE and more, see > https://stat.ethz.ch/mailman/listinfo/r-help > PLEASE do read the posting guide http://www.R-project.org/posting-guide.html > and provide commented, minimal, self-contained, reproducible code. >-- Michael http://www.dewey.myzen.co.uk/home.html
Hi Micheal, Maybe there is a simple way but i wanted to get the lowest aicc ana i could not find a way to do so, that's why i created the table to store all possible outcomes and then i can easily get the minimum value and the values of (i,j and k) used for that minimum value. The first column in the table is AICc[,1] to store i and second column for j and so on. Maybe i am mistaken and this won't give me what i want, the code been running for 5 hours now. So i am waiting On Wed, Feb 6, 2019 at 4:59 PM Michael Dewey <lists at dewey.myzen.co.uk> wrote:> This is not an answer to your speed problem but are your assignments to > AICc[,1] and so on doing what you hope they are doing? > > Michael > > On 06/02/2019 12:03, salah maadawy wrote: > > i am a beginner regarding R but i am trying to do a simple thing, but it > is > > taking too much time and i am asking if there is any way to achieve what > i > > need, i have a time series data set with 730 data points, i detected 7, > 354 > > and 365 seasonality periods. i am trying to use Fourier terms for > > seasonality and for loop to get the K value for each while minimizing > AICc, > > my code is > > > > AICc<- data.table(matrix(nrow = 96642, ncol = 4))for (i in 1:3) { > > for (j in 1:177) { > > for (k in 182) { #i,j and k values are choosen > > with regad that K cannot exceed seasonality period/2 > > z1 <- fourier(ts(demand,frequency = 7), K=i) > > z2 <- fourier(ts(demand,frequency=354), K=j) > > z3 <- fourier(ts(demand,frequency = 365),K=k) > > fit <- auto.arima(demand, xreg =cbind(z1,z2,z3), > > seasonal = FALSE) > > fit$aicc > > AICc[,1]<-i > > AICc[,2]<-j > > AICc[,3]<-k > > AICc[,4]<-fit$aicc > > } > > > > } > > } > > AICc > > > > i have created a data table to store AICc values from all possible i,j,k > > combinations so that i can find later the minimum AICc value. the problem > > now is that it is taking forever to do so not only to iterate all > > combinations but also due to the large K values. > > > > , is there any possible solution for this? thank you in advance > > > > [[alternative HTML version deleted]] > > > > ______________________________________________ > > R-help at r-project.org mailing list -- To UNSUBSCRIBE and more, see > > https://stat.ethz.ch/mailman/listinfo/r-help > > PLEASE do read the posting guide > http://www.R-project.org/posting-guide.html > > and provide commented, minimal, self-contained, reproducible code. > > > > -- > Michael > http://www.dewey.myzen.co.uk/home.html >[[alternative HTML version deleted]]
This seems like an odd analysis to me, but I don't have time to look
closer at it. It certainly doesn't look simple to me... I hope you have
some good theoretical guidance in tackling this (which this mailing list
is not).
One obvious thing is that z1 only depends on i, so you should only have to
compute z1 3 times... but you are computing it 177*182*3 times. Make three
lists of fourier results using three separate preparation loops before
diving into your triple loop. Then just retrieve the relevant z1, z2 and
z3 from these lists when you run the auto.arima calculation.
The easy way to make lists is to use lapply rather than a for loop:
demand7 <- ts( demand, frequency = 7 ) # don't repeat the ts conversion
z1List <- lapply( 1:3, function(i) { fourier( demand7, K = i ) } )
then you can retrieve whichever z1 you want with
z1 <- z1List[[ i ]]
rather than recalculating it.
Also, data.table is implemented by a contributed package. It is a special
type of data frame. It is not at all clear that you need its special
properties here, but most people who create a matrix and then immediately
converts the matrix to a (type of) data frame aren't using the data frame
properly anyway. Here is one way to assemble your results:
AICc <- expand.grid( k = 1:181, j = 1:177, i = 1:3 )
AICc$fit <- NA
idx <- 1
for ( i in 1:3 ) {
for ( j in 1:177 ) {
for ( k in 1:181 ) {
# compute fit
AICc$fit[ idx ] <- fit$aicc
idx <- idx + 1
}
}
}
On Wed, 6 Feb 2019, salah maadawy wrote:
> i am a beginner regarding R but i am trying to do a simple thing, but it is
> taking too much time and i am asking if there is any way to achieve what i
> need, i have a time series data set with 730 data points, i detected 7, 354
> and 365 seasonality periods. i am trying to use Fourier terms for
> seasonality and for loop to get the K value for each while minimizing AICc,
> my code is
>
> AICc<- data.table(matrix(nrow = 96642, ncol = 4))for (i in 1:3) {
> for (j in 1:177) {
> for (k in 182) { #i,j and k values are choosen
> with regad that K cannot exceed seasonality period/2
> z1 <- fourier(ts(demand,frequency = 7), K=i)
> z2 <- fourier(ts(demand,frequency=354), K=j)
> z3 <- fourier(ts(demand,frequency = 365),K=k)
> fit <- auto.arima(demand, xreg =cbind(z1,z2,z3),
> seasonal = FALSE)
> fit$aicc
> AICc[,1]<-i
> AICc[,2]<-j
> AICc[,3]<-k
> AICc[,4]<-fit$aicc
> }
>
> }
> }
> AICc
>
> i have created a data table to store AICc values from all possible i,j,k
> combinations so that i can find later the minimum AICc value. the problem
> now is that it is taking forever to do so not only to iterate all
> combinations but also due to the large K values.
>
> , is there any possible solution for this? thank you in advance
>
> [[alternative HTML version deleted]]
>
> ______________________________________________
> R-help at r-project.org mailing list -- To UNSUBSCRIBE and more, see
> https://stat.ethz.ch/mailman/listinfo/r-help
> PLEASE do read the posting guide
http://www.R-project.org/posting-guide.html
> and provide commented, minimal, self-contained, reproducible code.
>
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