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G.Maubach at weinwolf.de

2016-Jun-16 12:57 UTC

[R] Building a binary vector out of dichotomous variables

Hi All,

I need to build a binary vector made of a set of dichotomous variables.

What I have so far is:

-- cut --

ds_example <-
  structure(
    list(
      year2013 = c(0, 0, 0, 1, 1, 1, 1, 0),
      year2014 = c(0,
                   0, 1, 1, 0, 0, 1, 1),
      year2015 = c(0, 1, 1, 1, 0, 1, 0, 0)
    ),
    .Names = c("year2013",
               "year2014", "year2015"),
    row.names = c(NA, 8L),
    class = "data.frame"
  )

attach(ds_example)
base <- 1000
binary_vector <- base + year2013 * 100 + year2014 * 10 + year2015
detach(ds_example)

binary_vector

ds_example <- cbind(ds_example, binary_vector)

varlist <- c("year2013", "year2014",
"year2015")

base <- 10^length(varlist)

binary_vector <- NULL

for (i in 1:3) {
  binary_vector <- 
   base + 
   ds_example [[varlist[i]]] * base / (10 ^ i)
}

ds_example <- cbind(ds_example, binary_vector)

message("Wrong result!")
ds_example

-- cut --

How do I get vectors like  1000 1001 1011 1111 1100 1101 1110 1010 for 
each case?

Is there a better approach than mine?

Kind regards

Georg

Tom Wright

2016-Jun-16 14:13 UTC

head link

[R] Building a binary vector out of dichotomous variables

Does this do what you want?

as.numeric(with(ds_example,paste(1,year2013,year2014,year2015,sep='')))

On Thu, Jun 16, 2016 at 8:57 AM,  <G.Maubach at weinwolf.de>
wrote:> Hi All,
>
> I need to build a binary vector made of a set of dichotomous variables.
>
> What I have so far is:
>
> -- cut --
>
> ds_example <-
>   structure(
>     list(
>       year2013 = c(0, 0, 0, 1, 1, 1, 1, 0),
>       year2014 = c(0,
>                    0, 1, 1, 0, 0, 1, 1),
>       year2015 = c(0, 1, 1, 1, 0, 1, 0, 0)
>     ),
>     .Names = c("year2013",
>                "year2014", "year2015"),
>     row.names = c(NA, 8L),
>     class = "data.frame"
>   )
>
> attach(ds_example)
> base <- 1000
> binary_vector <- base + year2013 * 100 + year2014 * 10 + year2015
> detach(ds_example)
>
> binary_vector
>
> ds_example <- cbind(ds_example, binary_vector)
>
> varlist <- c("year2013", "year2014",
"year2015")
>
> base <- 10^length(varlist)
>
> binary_vector <- NULL
>
> for (i in 1:3) {
>   binary_vector <-
>    base +
>    ds_example [[varlist[i]]] * base / (10 ^ i)
> }
>
> ds_example <- cbind(ds_example, binary_vector)
>
> message("Wrong result!")
> ds_example
>
> -- cut --
>
> How do I get vectors like  1000 1001 1011 1111 1100 1101 1110 1010 for
> each case?
>
> Is there a better approach than mine?
>
> Kind regards
>
> Georg
>
> ______________________________________________
> R-help at r-project.org mailing list -- To UNSUBSCRIBE and more, see
> https://stat.ethz.ch/mailman/listinfo/r-help
> PLEASE do read the posting guide
http://www.R-project.org/posting-guide.html
> and provide commented, minimal, self-contained, reproducible code.

G.Maubach at gmx.de

2016-Jun-17 07:19 UTC

head link

[R] Fw: Aw: Re: Building a binary vector out of dichotomous variables

> Hi Tom,
> 
> thanks for your reply.
> 
> Yes, that's exactly what I am looking for. I did not know about the
automatic type conversion in R.
> 
> #-- cut --
> ds_example <-
>   structure(
>     list(
>       year2013 = c(0, 0, 0, 1, 1, 1, 1, 0),
>       year2014 = c(0,
>                    0, 1, 1, 0, 0, 1, 1),
>       year2015 = c(0, 1, 1, 1, 0, 1, 0, 0)
>     ),
>     .Names = c("year2013",
>                "year2014", "year2015"),
>     row.names = c(NA, 8L),
>     class = "data.frame"
>   )
> 
> #-- Proposal: works!
>
as.numeric(with(ds_example,paste(1,year2013,year2014,year2015,sep='')))
> 
> # I store my know-how about R in functions for later use.
> 
> #--? Putting it in a function - does not work!
> t_make_binary_vector <- function(dataset,
>                                  input_variables,
>                                  output_variable =
"binary_vector") {
>   dataset[output_variable] <- "1"
>   print(dataset[output_variable])
>   
>   for (variable in input_variables) {
>     print(variable)
>     dataset[output_variable] <- paste(dataset[output_variable],
>                                       dataset[variable], 
>                                       sep='')
>   }
>   
>   # print(dataset[output_variable])
> 
>   dataset[output_variable] <- as.integer(dataset[output_variable])
>   
>   return(dataset)
> }
> 
> t_make_binary_vector(dataset = ds_example,
>                      input_variables = c("year2013",
"year2014", "year2015"),
>                      output_variable = "binary_vector")
> 
> 
> #-- Doesn't work either.
> t_make_binary_vector <- function(dataset,
>                                  input_variables,
>                                  output_variable =
"binary_vector") {
>   dataset[output_variable] <- as.integer(paste(1, dataset[ ,
input_variables], sep = ''))
> 
>   return(dataset)
> }
> 
> t_make_binary_vector(dataset = ds_example,
>                      input_variables = c("year2013",
"year2014", "year2015"),
>                      output_variable = "binary_vector")
> 
> #-- cut --
> 
> Why is R taking the parameter value itself to paste it together instead of
referencing the variable within the dataset?
> 
> What did I get wrong about R? How can I fix it?
> 
> Kind regards
> 
> Georg
> 
> 
> > Gesendet: Donnerstag, 16. Juni 2016 um 16:13 Uhr
> > Von: "Tom Wright" <tom at maladmin.com>
> > An: G.Maubach at weinwolf.de
> > Cc: "R. Help" <r-help at r-project.org>
> > Betreff: Re: [R] Building a binary vector out of dichotomous variables
> >
> > Does this do what you want?
> > 
> >
as.numeric(with(ds_example,paste(1,year2013,year2014,year2015,sep='')))
> > 
> > On Thu, Jun 16, 2016 at 8:57 AM,  <G.Maubach at weinwolf.de>
wrote:
> > > Hi All,
> > >
> > > I need to build a binary vector made of a set of dichotomous
variables.
> > >
> > > What I have so far is:
> > >
> > > -- cut --
> > >
> > > ds_example <-
> > >   structure(
> > >     list(
> > >       year2013 = c(0, 0, 0, 1, 1, 1, 1, 0),
> > >       year2014 = c(0,
> > >                    0, 1, 1, 0, 0, 1, 1),
> > >       year2015 = c(0, 1, 1, 1, 0, 1, 0, 0)
> > >     ),
> > >     .Names = c("year2013",
> > >                "year2014", "year2015"),
> > >     row.names = c(NA, 8L),
> > >     class = "data.frame"
> > >   )
> > >
> > > attach(ds_example)
> > > base <- 1000
> > > binary_vector <- base + year2013 * 100 + year2014 * 10 +
year2015
> > > detach(ds_example)
> > >
> > > binary_vector
> > >
> > > ds_example <- cbind(ds_example, binary_vector)
> > >
> > > varlist <- c("year2013", "year2014",
"year2015")
> > >
> > > base <- 10^length(varlist)
> > >
> > > binary_vector <- NULL
> > >
> > > for (i in 1:3) {
> > >   binary_vector <-
> > >    base +
> > >    ds_example [[varlist[i]]] * base / (10 ^ i)
> > > }
> > >
> > > ds_example <- cbind(ds_example, binary_vector)
> > >
> > > message("Wrong result!")
> > > ds_example
> > >
> > > -- cut --
> > >
> > > How do I get vectors like  1000 1001 1011 1111 1100 1101 1110
1010 for
> > > each case?
> > >
> > > Is there a better approach than mine?
> > >
> > > Kind regards
> > >
> > > Georg
> > >
> > > ______________________________________________
> > > R-help at r-project.org mailing list -- To UNSUBSCRIBE and more,
see
> > > https://stat.ethz.ch/mailman/listinfo/r-help
> > > PLEASE do read the posting guide
http://www.R-project.org/posting-guide.html
> > > and provide commented, minimal, self-contained, reproducible
code.
> > 
> > ______________________________________________
> > R-help at r-project.org mailing list -- To UNSUBSCRIBE and more, see
> > https://stat.ethz.ch/mailman/listinfo/r-help
> > PLEASE do read the posting guide
http://www.R-project.org/posting-guide.html
> > and provide commented, minimal, self-contained, reproducible code.
> >

PIKAL Petr

2016-Jun-17 08:34 UTC

head link

[R] Fw: Aw: Re: Building a binary vector out of dichotomous variables

Hi

Your approach seems to me rather tricky

This should work

make_bv <- function(dataset,  input_variables) {

dd <- which(names(dataset) %in% input_variables)
dat<-dataset[,dd]
x <- 10^(ncol(dat):0)
result <- cbind(dataset, binary_vec=x[1]+rowSums(sweep(dat, 2, x[-1],
"*")))
result}

make_bv(dataset = ds_example,  input_variables = c("year2013",
"year2015"))

Cheers
Petr
> -----Original Message-----
> From: R-help [mailto:r-help-bounces at r-project.org] On Behalf Of
> G.Maubach at gmx.de
> Sent: Friday, June 17, 2016 9:19 AM
> To: r-help at r-project.org
> Subject: [R] Fw: Aw: Re: Building a binary vector out of dichotomous
variables
>
> > Hi Tom,
> >
> > thanks for your reply.
> >
> > Yes, that's exactly what I am looking for. I did not know about
the
> automatic type conversion in R.
> >
> > #-- cut --
> > ds_example <-
> >   structure(
> >     list(
> >       year2013 = c(0, 0, 0, 1, 1, 1, 1, 0),
> >       year2014 = c(0,
> >                    0, 1, 1, 0, 0, 1, 1),
> >       year2015 = c(0, 1, 1, 1, 0, 1, 0, 0)
> >     ),
> >     .Names = c("year2013",
> >                "year2014", "year2015"),
> >     row.names = c(NA, 8L),
> >     class = "data.frame"
> >   )
> >
> > #-- Proposal: works!
> >
as.numeric(with(ds_example,paste(1,year2013,year2014,year2015,sep=''))
> > )
> >
> > # I store my know-how about R in functions for later use.
> >
> > #--? Putting it in a function - does not work!
> > t_make_binary_vector <- function(dataset,
> >                                  input_variables,
> >                                  output_variable =
"binary_vector") {
> >   dataset[output_variable] <- "1"
> >   print(dataset[output_variable])
> >
> >   for (variable in input_variables) {
> >     print(variable)
> >     dataset[output_variable] <- paste(dataset[output_variable],
> >                                       dataset[variable],
> >                                       sep='')
> >   }
> >
> >   # print(dataset[output_variable])
> >
> >   dataset[output_variable] <- as.integer(dataset[output_variable])
> >
> >   return(dataset)
> > }
> >
> > t_make_binary_vector(dataset = ds_example,
> >                      input_variables = c("year2013",
"year2014", "year2015"),
> >                      output_variable = "binary_vector")
> >
> >
> > #-- Doesn't work either.
> > t_make_binary_vector <- function(dataset,
> >                                  input_variables,
> >                                  output_variable =
"binary_vector") {
> >   dataset[output_variable] <- as.integer(paste(1, dataset[ ,
> > input_variables], sep = ''))
> >
> >   return(dataset)
> > }
> >
> > t_make_binary_vector(dataset = ds_example,
> >                      input_variables = c("year2013",
"year2014", "year2015"),
> >                      output_variable = "binary_vector")
> >
> > #-- cut --
> >
> > Why is R taking the parameter value itself to paste it together
instead of
> referencing the variable within the dataset?
> >
> > What did I get wrong about R? How can I fix it?
> >
> > Kind regards
> >
> > Georg
> >
> >
> > > Gesendet: Donnerstag, 16. Juni 2016 um 16:13 Uhr
> > > Von: "Tom Wright" <tom at maladmin.com>
> > > An: G.Maubach at weinwolf.de
> > > Cc: "R. Help" <r-help at r-project.org>
> > > Betreff: Re: [R] Building a binary vector out of dichotomous
> > > variables
> > >
> > > Does this do what you want?
> > >
> > >
as.numeric(with(ds_example,paste(1,year2013,year2014,year2015,sep=''
> > > )))
> > >
> > > On Thu, Jun 16, 2016 at 8:57 AM,  <G.Maubach at
weinwolf.de> wrote:
> > > > Hi All,
> > > >
> > > > I need to build a binary vector made of a set of dichotomous
variables.
> > > >
> > > > What I have so far is:
> > > >
> > > > -- cut --
> > > >
> > > > ds_example <-
> > > >   structure(
> > > >     list(
> > > >       year2013 = c(0, 0, 0, 1, 1, 1, 1, 0),
> > > >       year2014 = c(0,
> > > >                    0, 1, 1, 0, 0, 1, 1),
> > > >       year2015 = c(0, 1, 1, 1, 0, 1, 0, 0)
> > > >     ),
> > > >     .Names = c("year2013",
> > > >                "year2014", "year2015"),
> > > >     row.names = c(NA, 8L),
> > > >     class = "data.frame"
> > > >   )
> > > >
> > > > attach(ds_example)
> > > > base <- 1000
> > > > binary_vector <- base + year2013 * 100 + year2014 * 10 +
year2015
> > > > detach(ds_example)
> > > >
> > > > binary_vector
> > > >
> > > > ds_example <- cbind(ds_example, binary_vector)
> > > >
> > > > varlist <- c("year2013", "year2014",
"year2015")
> > > >
> > > > base <- 10^length(varlist)
> > > >
> > > > binary_vector <- NULL
> > > >
> > > > for (i in 1:3) {
> > > >   binary_vector <-
> > > >    base +
> > > >    ds_example [[varlist[i]]] * base / (10 ^ i) }
> > > >
> > > > ds_example <- cbind(ds_example, binary_vector)
> > > >
> > > > message("Wrong result!")
> > > > ds_example
> > > >
> > > > -- cut --
> > > >
> > > > How do I get vectors like  1000 1001 1011 1111 1100 1101
1110 1010
> > > > for each case?
> > > >
> > > > Is there a better approach than mine?
> > > >
> > > > Kind regards
> > > >
> > > > Georg
> > > >
> > > > ______________________________________________
> > > > R-help at r-project.org mailing list -- To UNSUBSCRIBE and
more, see
> > > > https://stat.ethz.ch/mailman/listinfo/r-help
> > > > PLEASE do read the posting guide
> > > > http://www.R-project.org/posting-guide.html
> > > > and provide commented, minimal, self-contained, reproducible
code.
> > >
> > > ______________________________________________
> > > R-help at r-project.org mailing list -- To UNSUBSCRIBE and more,
see
> > > https://stat.ethz.ch/mailman/listinfo/r-help
> > > PLEASE do read the posting guide
> > > http://www.R-project.org/posting-guide.html
> > > and provide commented, minimal, self-contained, reproducible
code.
> > >
>
> ______________________________________________
> R-help at r-project.org mailing list -- To UNSUBSCRIBE and more, see
> https://stat.ethz.ch/mailman/listinfo/r-help
> PLEASE do read the posting guide http://www.R-project.org/posting-
> guide.html
> and provide commented, minimal, self-contained, reproducible code.
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R help - Jun 2016 - Building a binary vector out of dichotomous variables

[R] Building a binary vector out of dichotomous variables

[R] Building a binary vector out of dichotomous variables

[R] Fw: Aw: Re: Building a binary vector out of dichotomous variables

[R] Fw: Aw: Re: Building a binary vector out of dichotomous variables