Hi
This I do not consider as a loop without index. AFAIK i is index and the loop
is executed twice. First with i equal to ?a? and second time with i equal to
?b?.
In that case you need to have some objects which are named ?a? or ?b? and you
can use it for selection or computing
d<-list(a=NULL, b=NULL)
for (i in c("a","b")) {
d[[i]]<-1:3
}
Cheers
Petr
From: carol white [mailto:wht_crl at yahoo.com]
Sent: Friday, June 05, 2015 11:51 AM
To: PIKAL Petr
Subject: Re: [R] building a list in a loop
for (i in c("a","b"))
best,
On Friday, June 5, 2015 11:36 AM, PIKAL Petr <petr.pikal at
precheza.cz<mailto:petr.pikal at precheza.cz>> wrote:
Hi
Can you please specify how loop without index shall be constructed? It is rather
new topic for me.
Petr
From: carol white [mailto:wht_crl at yahoo.com]
Sent: Friday, June 05, 2015 11:21 AM
To: PIKAL Petr
Subject: Re: [R] building a list in a loop
also consider a loop without index (not like for (i ...) where index could be
used for the list construction)
Cheers,
On Friday, June 5, 2015 11:13 AM, PIKAL Petr <petr.pikal at
precheza.cz<mailto:petr.pikal at precheza.cz>> wrote:
Hi
It is not clear what exactly do you want.
d<-list()
vec<-1:3
for (i in 1:2) {
vec<-vec+3*(i-1)
d[[i]]<-vec
#names(d)[i] <- paste("name",i)
}
You can add names in second loop or you can use names command in first loop.
Cheers
Petr
> -----Original Message-----
> From: R-help [mailto:r-help-bounces at
r-project.org<mailto:r-help-bounces at r-project.org>] On Behalf Of carol
> white via R-help
> Sent: Friday, June 05, 2015 10:40 AM
> To: R-help Help
> Subject: [R] building a list in a loop
>
> It might be an easy question but how to construct correctly a list in a
> loop?
>
> The following doesn't work
> before starting the loopd = NULL#in the loop, 1st iteration
> d = list(d,c(1,2,3)d[[1]]
> NULL
>
> [[2]]
> [1] 1 2 3#in the loop, 2nd iterationd=list(d,c(4,5,6)d
> [[1]]
> [[1]][[1]]
> NULL
>
> [[1]][[2]]
> [1] 1 2 3
>
>
> [[2]]
> [1] 4 5 6
> the goal is to have the result of d= list(c(1,2,3),c(4,5,6)) where the
> list components are not known out of the loop.
> d[[1]]
> [1] 1 2 3
>
> [[2]]
> [1] 4 5 6
> Moreover, how to name the components of the list in the loop while
> constructing as the names are not known out of the loop, either? note
> that the name of the component is stored in a variable in the loop
>
> d = NULL#name1 contains the name for c(1,2,3), how to give the name
> below?
> d = list(d,c(1,2,3)
> Thanks
>
> [[alternative HTML version deleted]]
>
> ______________________________________________
> R-help at r-project.org<mailto:R-help at r-project.org> mailing list
-- To UNSUBSCRIBE and more, see
> https://stat.ethz.ch/mailman/listinfo/r-help
> PLEASE do read the posting guide
http://www.R-project.org/posting-<http://www.r-project.org/posting->
> guide.html
> and provide commented, minimal, self-contained, reproducible code.
________________________________
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pouze jeho adres?t?m.
Jestli?e jste obdr?el(a) tento e-mail omylem, informujte laskav? neprodlen? jeho
odes?latele. Obsah tohoto emailu i s p??lohami a jeho kopie vyma?te ze sv?ho
syst?mu.
Nejste-li zam??len?m adres?tem tohoto emailu, nejste opr?vn?ni tento email
jakkoliv u??vat, roz?i?ovat, kop?rovat ?i zve?ej?ovat.
Odes?latel e-mailu neodpov?d? za eventu?ln? ?kodu zp?sobenou modifikacemi ?i
zpo?d?n?m p?enosu e-mailu.
V p??pad?, ?e je tento e-mail sou??st? obchodn?ho jedn?n?:
- vyhrazuje si odes?latel pr?vo ukon?it kdykoliv jedn?n? o uzav?en? smlouvy, a
to z jak?hokoliv d?vodu i bez uveden? d?vodu.
- a obsahuje-li nab?dku, je adres?t opr?vn?n nab?dku bezodkladn? p?ijmout;
Odes?latel tohoto e-mailu (nab?dky) vylu?uje p?ijet? nab?dky ze strany p??jemce
s dodatkem ?i odchylkou.
- trv? odes?latel na tom, ?e p??slu?n? smlouva je uzav?ena teprve v?slovn?m
dosa?en?m shody na v?ech jej?ch n?le?itostech.
- odes?latel tohoto emailu informuje, ?e nen? opr?vn?n uzav?rat za spole?nost
??dn? smlouvy s v?jimkou p??pad?, kdy k tomu byl p?semn? zmocn?n nebo p?semn?
pov??en a takov? pov??en? nebo pln? moc byly adres?tovi tohoto emailu p??padn?
osob?, kterou adres?t zastupuje, p?edlo?eny nebo jejich existence je adres?tovi
?i osob? j?m zastoupen? zn?m?.
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If you received this e-mail by mistake, please immediately inform its sender.
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In case that this e-mail forms part of business dealings:
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- the sender insists on that the respective contract is concluded only upon an
express mutual agreement on all its aspects.
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[[alternative HTML version deleted]]
in this example can elements of the list be accessed by their name if their name
is the value of a variable?el = "a"can the first element d[[1]] be
accessed by el instead of the list index like d$a but via el?
Thanks
On Friday, June 5, 2015 12:04 PM, PIKAL Petr <petr.pikal at
precheza.cz> wrote:
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div.yiv1728143486WordSection1 {}#yiv1728143486 Hi?This I do not consider as a
loop without index. ?AFAIK i is index and the loop is executed twice. First with
i equal to ?a? and second time with i equal to ?b?. ?In that case you need to
have some objects which are named?a? or ?b? ?and you can use it for selection or
computing?d<-list(a=NULL, b=NULL)for (i in c("a","b"))
{d[[i]]<-1:3}?CheersPetr?From: carol white [mailto:wht_crl at yahoo.com]
Sent: Friday, June 05, 2015 11:51 AM
To: PIKAL Petr
Subject: Re: [R] building a list in a loop?for (i in
c("a","b"))?best,???On Friday, June 5, 2015 11:36 AM, PIKAL
Petr <petr.pikal at precheza.cz> wrote:?Hi?Can you please specify how loop
without index shall be constructed? It is rather new topic for me.?Petr?From:
carol white [mailto:wht_crl at yahoo.com]
Sent: Friday, June 05, 2015 11:21 AM
To: PIKAL Petr
Subject: Re: [R] building a list in a loop?also consider a loop without index
(not like for (i ...) where index could be used for the list
construction)?Cheers,??On Friday, June 5, 2015 11:13 AM, PIKAL Petr
<petr.pikal at precheza.cz> wrote:?Hi
It is not clear what exactly do you want.
d<-list()
vec<-1:3
for (i in 1:2) {
vec<-vec+3*(i-1)
d[[i]]<-vec
#names(d)[i] <- paste("name",i)
}
You can add names in second loop or you can use names command in first loop.
Cheers
Petr> -----Original Message-----
> From: R-help [mailto:r-help-bounces at r-project.org] On Behalf Of carol
> white via R-help
> Sent: Friday, June 05, 2015 10:40 AM
> To: R-help Help
> Subject: [R] building a list in a loop
>
> It might be an easy question but how to construct correctly a list in a
> loop?
>
> The following doesn't work
> before starting the loopd = NULL#in the loop, 1st iteration
> d = list(d,c(1,2,3)d[[1]]
> NULL
>
> [[2]]
> [1] 1 2 3#in the loop, 2nd iterationd=list(d,c(4,5,6)d
> [[1]]
> [[1]][[1]]
> NULL
>
> [[1]][[2]]
> [1] 1 2 3
>
>
> [[2]]
> [1] 4 5 6
> the goal is to have the result of d= list(c(1,2,3),c(4,5,6)) where the
> list components are not known out of the loop.
> d[[1]]
> [1] 1 2 3
>
> [[2]]
> [1] 4 5 6
> Moreover, how to name the components of the list in the loop while
> constructing as the names are not known out of the loop, either? note
> that the name of the component is stored in a variable in the loop
>
> d = NULL#name1 contains the name for c(1,2,3), how to give the name
> below?
> d = list(d,c(1,2,3)
> Thanks
>
>? ? ? [[alternative HTML version deleted]]
>
> ______________________________________________
> R-help at r-project.org mailing list -- To UNSUBSCRIBE and more, see
> https://stat.ethz.ch/mailman/listinfo/r-help
> PLEASE do read the posting guide http://www.R-project.org/posting-
> guide.html
> and provide commented, minimal, self-contained, reproducible code.
________________________________
Tento e-mail a jak?koliv k n?mu p?ipojen? dokumenty jsou d?v?rn? a jsou ur?eny
pouze jeho adres?t?m.
Jestli?e jste obdr?el(a) tento e-mail omylem, informujte laskav? neprodlen? jeho
odes?latele. Obsah tohoto emailu i s p??lohami a jeho kopie vyma?te ze sv?ho
syst?mu.
Nejste-li zam??len?m adres?tem tohoto emailu, nejste opr?vn?ni tento email
jakkoliv u??vat, roz?i?ovat, kop?rovat ?i zve?ej?ovat.
Odes?latel e-mailu neodpov?d? za eventu?ln? ?kodu zp?sobenou modifikacemi ?i
zpo?d?n?m p?enosu e-mailu.
V p??pad?, ?e je tento e-mail sou??st? obchodn?ho jedn?n?:
- vyhrazuje si odes?latel pr?vo ukon?it kdykoliv jedn?n? o uzav?en? smlouvy, a
to z jak?hokoliv d?vodu i bez uveden? d?vodu.
- a obsahuje-li nab?dku, je adres?t opr?vn?n nab?dku bezodkladn? p?ijmout;
Odes?latel tohoto e-mailu (nab?dky) vylu?uje p?ijet? nab?dky ze strany p??jemce
s dodatkem ?i odchylkou.
- trv? odes?latel na tom, ?e p??slu?n? smlouva je uzav?ena teprve v?slovn?m
dosa?en?m shody na v?ech jej?ch n?le?itostech.
- odes?latel tohoto emailu informuje, ?e nen? opr?vn?n uzav?rat za spole?nost
??dn? smlouvy s v?jimkou p??pad?, kdy k tomu byl p?semn? zmocn?n nebo p?semn?
pov??en a takov? pov??en? nebo pln? moc byly adres?tovi tohoto emailu p??padn?
osob?, kterou adres?t zastupuje, p?edlo?eny nebo jejich existence je adres?tovi
?i osob? j?m zastoupen? zn?m?.
This e-mail and any documents attached to it may be confidential and are
intended only for its intended recipients.
If you received this e-mail by mistake, please immediately inform its sender.
Delete the contents of this e-mail with all attachments and its copies from your
system.
If you are not the intended recipient of this e-mail, you are not authorized to
use, disseminate, copy or disclose this e-mail in any manner.
The sender of this e-mail shall not be liable for any possible damage caused by
modifications of the e-mail or by delay with transfer of the email.
In case that this e-mail forms part of business dealings:
- the sender reserves the right to end negotiations about entering into a
contract in any time, for any reason, and without stating any reasoning.
- if the e-mail contains an offer, the recipient is entitled to immediately
accept such offer; The sender of this e-mail (offer) excludes any acceptance of
the offer on the part of the recipient containing any amendment or variation.
- the sender insists on that the respective contract is concluded only upon an
express mutual agreement on all its aspects.
- the sender of this e-mail informs that he/she is not authorized to enter into
any contracts on behalf of the company except for cases in which he/she is
expressly authorized to do so in writing, and such authorization or power of
attorney is submitted to the recipient or the person represented by the
recipient, or the existence of such authorization is known to the recipient of
the person represented by the recipient.???Tento e-mail a jak?koliv k n?mu
p?ipojen? dokumenty jsou d?v?rn? a jsou ur?eny pouze jeho adres?t?m.
Jestli?e jste obdr?el(a) tento e-mail omylem, informujte laskav? neprodlen? jeho
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syst?mu.
Nejste-li zam??len?m adres?tem tohoto emailu, nejste opr?vn?ni tento email
jakkoliv u??vat, roz?i?ovat, kop?rovat ?i zve?ej?ovat.
Odes?latel e-mailu neodpov?d? za eventu?ln? ?kodu zp?sobenou modifikacemi ?i
zpo?d?n?m p?enosu e-mailu.
V p??pad?, ?e je tento e-mail sou??st? obchodn?ho jedn?n?:
- vyhrazuje si odes?latel pr?vo ukon?it kdykoliv jedn?n? o uzav?en? smlouvy, a
to z jak?hokoliv d?vodu i bez uveden? d?vodu.
- a obsahuje-li nab?dku, je adres?t opr?vn?n nab?dku bezodkladn? p?ijmout;
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pov??en a takov? pov??en? nebo pln? moc byly adres?tovi tohoto emailu p??padn?
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[[alternative HTML version deleted]]
Here is the best solution that I found as the list is built in the embedded
functions withtout using loop index, list elements' names etc
d = list()d[[length(d)+1]] = 1:3d[[length(d)+1]] = 4:6
Many thanks for your help
On Friday, June 5, 2015 12:04 PM, PIKAL Petr <petr.pikal at
precheza.cz> wrote:
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div.yiv1728143486WordSection1 {}#yiv1728143486 Hi?This I do not consider as a
loop without index. ?AFAIK i is index and the loop is executed twice. First with
i equal to ?a? and second time with i equal to ?b?. ?In that case you need to
have some objects which are named?a? or ?b? ?and you can use it for selection or
computing?d<-list(a=NULL, b=NULL)for (i in c("a","b"))
{d[[i]]<-1:3}?CheersPetr?From: carol white [mailto:wht_crl at yahoo.com]
Sent: Friday, June 05, 2015 11:51 AM
To: PIKAL Petr
Subject: Re: [R] building a list in a loop?for (i in
c("a","b"))?best,???On Friday, June 5, 2015 11:36 AM, PIKAL
Petr <petr.pikal at precheza.cz> wrote:?Hi?Can you please specify how loop
without index shall be constructed? It is rather new topic for me.?Petr?From:
carol white [mailto:wht_crl at yahoo.com]
Sent: Friday, June 05, 2015 11:21 AM
To: PIKAL Petr
Subject: Re: [R] building a list in a loop?also consider a loop without index
(not like for (i ...) where index could be used for the list
construction)?Cheers,??On Friday, June 5, 2015 11:13 AM, PIKAL Petr
<petr.pikal at precheza.cz> wrote:?Hi
It is not clear what exactly do you want.
d<-list()
vec<-1:3
for (i in 1:2) {
vec<-vec+3*(i-1)
d[[i]]<-vec
#names(d)[i] <- paste("name",i)
}
You can add names in second loop or you can use names command in first loop.
Cheers
Petr> -----Original Message-----
> From: R-help [mailto:r-help-bounces at r-project.org] On Behalf Of carol
> white via R-help
> Sent: Friday, June 05, 2015 10:40 AM
> To: R-help Help
> Subject: [R] building a list in a loop
>
> It might be an easy question but how to construct correctly a list in a
> loop?
>
> The following doesn't work
> before starting the loopd = NULL#in the loop, 1st iteration
> d = list(d,c(1,2,3)d[[1]]
> NULL
>
> [[2]]
> [1] 1 2 3#in the loop, 2nd iterationd=list(d,c(4,5,6)d
> [[1]]
> [[1]][[1]]
> NULL
>
> [[1]][[2]]
> [1] 1 2 3
>
>
> [[2]]
> [1] 4 5 6
> the goal is to have the result of d= list(c(1,2,3),c(4,5,6)) where the
> list components are not known out of the loop.
> d[[1]]
> [1] 1 2 3
>
> [[2]]
> [1] 4 5 6
> Moreover, how to name the components of the list in the loop while
> constructing as the names are not known out of the loop, either? note
> that the name of the component is stored in a variable in the loop
>
> d = NULL#name1 contains the name for c(1,2,3), how to give the name
> below?
> d = list(d,c(1,2,3)
> Thanks
>
>? ? ? [[alternative HTML version deleted]]
>
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> https://stat.ethz.ch/mailman/listinfo/r-help
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________________________________
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to z jak?hokoliv d?vodu i bez uveden? d?vodu.
- a obsahuje-li nab?dku, je adres?t opr?vn?n nab?dku bezodkladn? p?ijmout;
Odes?latel tohoto e-mailu (nab?dky) vylu?uje p?ijet? nab?dky ze strany p??jemce
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dosa?en?m shody na v?ech jej?ch n?le?itostech.
- odes?latel tohoto emailu informuje, ?e nen? opr?vn?n uzav?rat za spole?nost
??dn? smlouvy s v?jimkou p??pad?, kdy k tomu byl p?semn? zmocn?n nebo p?semn?
pov??en a takov? pov??en? nebo pln? moc byly adres?tovi tohoto emailu p??padn?
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Odes?latel e-mailu neodpov?d? za eventu?ln? ?kodu zp?sobenou modifikacemi ?i
zpo?d?n?m p?enosu e-mailu.
V p??pad?, ?e je tento e-mail sou??st? obchodn?ho jedn?n?:
- vyhrazuje si odes?latel pr?vo ukon?it kdykoliv jedn?n? o uzav?en? smlouvy, a
to z jak?hokoliv d?vodu i bez uveden? d?vodu.
- a obsahuje-li nab?dku, je adres?t opr?vn?n nab?dku bezodkladn? p?ijmout;
Odes?latel tohoto e-mailu (nab?dky) vylu?uje p?ijet? nab?dky ze strany p??jemce
s dodatkem ?i odchylkou.
- trv? odes?latel na tom, ?e p??slu?n? smlouva je uzav?ena teprve v?slovn?m
dosa?en?m shody na v?ech jej?ch n?le?itostech.
- odes?latel tohoto emailu informuje, ?e nen? opr?vn?n uzav?rat za spole?nost
??dn? smlouvy s v?jimkou p??pad?, kdy k tomu byl p?semn? zmocn?n nebo p?semn?
pov??en a takov? pov??en? nebo pln? moc byly adres?tovi tohoto emailu p??padn?
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Odes?latel e-mailu neodpov?d? za eventu?ln? ?kodu zp?sobenou modifikacemi ?i
zpo?d?n?m p?enosu e-mailu.
V p??pad?, ?e je tento e-mail sou??st? obchodn?ho jedn?n?:
- vyhrazuje si odes?latel pr?vo ukon?it kdykoliv jedn?n? o uzav?en? smlouvy, a
to z jak?hokoliv d?vodu i bez uveden? d?vodu.
- a obsahuje-li nab?dku, je adres?t opr?vn?n nab?dku bezodkladn? p?ijmout;
Odes?latel tohoto e-mailu (nab?dky) vylu?uje p?ijet? nab?dky ze strany p??jemce
s dodatkem ?i odchylkou.
- trv? odes?latel na tom, ?e p??slu?n? smlouva je uzav?ena teprve v?slovn?m
dosa?en?m shody na v?ech jej?ch n?le?itostech.
- odes?latel tohoto emailu informuje, ?e nen? opr?vn?n uzav?rat za spole?nost
??dn? smlouvy s v?jimkou p??pad?, kdy k tomu byl p?semn? zmocn?n nebo p?semn?
pov??en a takov? pov??en? nebo pln? moc byly adres?tovi tohoto emailu p??padn?
osob?, kterou adres?t zastupuje, p?edlo?eny nebo jejich existence je adres?tovi
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[[alternative HTML version deleted]]
Hi I do not understand. ?i? is variable and list elements are called by this variable #constructing list> d<-as.list(sample(letters[1:5], 5, replace=F)) > names(d) <- letters[1:5] > d$a [1] "c" $b [1] "a" $c [1] "e" $d [1] "b" $e [1] "d" #variable el> el<-"a"#result> d[[el]]<-"whatever I want to put under name a" > d$a [1] "whatever I want to put under name a" $b [1] "a" $c [1] "e" $d [1] "b" $e [1] "d" Cheers Petr From: carol white [mailto:wht_crl at yahoo.com] Sent: Friday, June 05, 2015 1:31 PM To: PIKAL Petr Cc: r-help at r-project.org Subject: Re: [R] building a list in a loop in this example can elements of the list be accessed by their name if their name is the value of a variable? el = "a" can the first element d[[1]] be accessed by el instead of the list index like d$a but via el? Thanks On Friday, June 5, 2015 12:04 PM, PIKAL Petr <petr.pikal at precheza.cz<mailto:petr.pikal at precheza.cz>> wrote: Hi This I do not consider as a loop without index. AFAIK i is index and the loop is executed twice. First with i equal to ?a? and second time with i equal to ?b?. In that case you need to have some objects which are named ?a? or ?b? and you can use it for selection or computing d<-list(a=NULL, b=NULL) for (i in c("a","b")) { d[[i]]<-1:3 } Cheers Petr From: carol white [mailto:wht_crl at yahoo.com] Sent: Friday, June 05, 2015 11:51 AM To: PIKAL Petr Subject: Re: [R] building a list in a loop for (i in c("a","b")) best, On Friday, June 5, 2015 11:36 AM, PIKAL Petr <petr.pikal at precheza.cz<mailto:petr.pikal at precheza.cz>> wrote: Hi Can you please specify how loop without index shall be constructed? It is rather new topic for me. Petr From: carol white [mailto:wht_crl at yahoo.com] Sent: Friday, June 05, 2015 11:21 AM To: PIKAL Petr Subject: Re: [R] building a list in a loop also consider a loop without index (not like for (i ...) where index could be used for the list construction) Cheers, On Friday, June 5, 2015 11:13 AM, PIKAL Petr <petr.pikal at precheza.cz<mailto:petr.pikal at precheza.cz>> wrote: Hi It is not clear what exactly do you want. d<-list() vec<-1:3 for (i in 1:2) { vec<-vec+3*(i-1) d[[i]]<-vec #names(d)[i] <- paste("name",i) } You can add names in second loop or you can use names command in first loop. Cheers Petr> -----Original Message----- > From: R-help [mailto:r-help-bounces at r-project.org<mailto:r-help-bounces at r-project.org>] On Behalf Of carol > white via R-help > Sent: Friday, June 05, 2015 10:40 AM > To: R-help Help > Subject: [R] building a list in a loop > > It might be an easy question but how to construct correctly a list in a > loop? > > The following doesn't work > before starting the loopd = NULL#in the loop, 1st iteration > d = list(d,c(1,2,3)d[[1]] > NULL > > [[2]] > [1] 1 2 3#in the loop, 2nd iterationd=list(d,c(4,5,6)d > [[1]] > [[1]][[1]] > NULL > > [[1]][[2]] > [1] 1 2 3 > > > [[2]] > [1] 4 5 6 > the goal is to have the result of d= list(c(1,2,3),c(4,5,6)) where the > list components are not known out of the loop. > d[[1]] > [1] 1 2 3 > > [[2]] > [1] 4 5 6 > Moreover, how to name the components of the list in the loop while > constructing as the names are not known out of the loop, either? note > that the name of the component is stored in a variable in the loop > > d = NULL#name1 contains the name for c(1,2,3), how to give the name > below? > d = list(d,c(1,2,3) > Thanks> > [[alternative HTML version deleted]] > > ______________________________________________ > R-help at r-project.org<mailto:R-help at r-project.org> mailing list -- To UNSUBSCRIBE and more, see > https://stat.ethz.ch/mailman/listinfo/r-help > PLEASE do read the posting guide http://www.R-project.org/posting-<http://www.r-project.org/posting-> > guide.html > and provide commented, minimal, self-contained, reproducible code.________________________________ Tento e-mail a jak?koliv k n?mu p?ipojen? dokumenty jsou d?v?rn? a jsou ur?eny pouze jeho adres?t?m. 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V p??pad?, ?e je tento e-mail sou??st? obchodn?ho jedn?n?: - vyhrazuje si odes?latel pr?vo ukon?it kdykoliv jedn?n? o uzav?en? smlouvy, a to z jak?hokoliv d?vodu i bez uveden? d?vodu. - a obsahuje-li nab?dku, je adres?t opr?vn?n nab?dku bezodkladn? p?ijmout; Odes?latel tohoto e-mailu (nab?dky) vylu?uje p?ijet? nab?dky ze strany p??jemce s dodatkem ?i odchylkou. - trv? odes?latel na tom, ?e p??slu?n? smlouva je uzav?ena teprve v?slovn?m dosa?en?m shody na v?ech jej?ch n?le?itostech. - odes?latel tohoto emailu informuje, ?e nen? opr?vn?n uzav?rat za spole?nost ??dn? smlouvy s v?jimkou p??pad?, kdy k tomu byl p?semn? zmocn?n nebo p?semn? pov??en a takov? pov??en? nebo pln? moc byly adres?tovi tohoto emailu p??padn? osob?, kterou adres?t zastupuje, p?edlo?eny nebo jejich existence je adres?tovi ?i osob? j?m zastoupen? zn?m?. This e-mail and any documents attached to it may be confidential and are intended only for its intended recipients. 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V p??pad?, ?e je tento e-mail sou??st? obchodn?ho jedn?n?: - vyhrazuje si odes?latel pr?vo ukon?it kdykoliv jedn?n? o uzav?en? smlouvy, a to z jak?hokoliv d?vodu i bez uveden? d?vodu. - a obsahuje-li nab?dku, je adres?t opr?vn?n nab?dku bezodkladn? p?ijmout; Odes?latel tohoto e-mailu (nab?dky) vylu?uje p?ijet? nab?dky ze strany p??jemce s dodatkem ?i odchylkou. - trv? odes?latel na tom, ?e p??slu?n? smlouva je uzav?ena teprve v?slovn?m dosa?en?m shody na v?ech jej?ch n?le?itostech. - odes?latel tohoto emailu informuje, ?e nen? opr?vn?n uzav?rat za spole?nost ??dn? smlouvy s v?jimkou p??pad?, kdy k tomu byl p?semn? zmocn?n nebo p?semn? pov??en a takov? pov??en? nebo pln? moc byly adres?tovi tohoto emailu p??padn? osob?, kterou adres?t zastupuje, p?edlo?eny nebo jejich existence je adres?tovi ?i osob? j?m zastoupen? zn?m?. This e-mail and any documents attached to it may be confidential and are intended only for its intended recipients. 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