similar to: Extending each element in a list, or rbind()-ing arrays of different length without recycling

Without recycling you would get: u <- c(10, 20, 30) u + 1 #[1] 11 20 30 which would be pretty inconvenient. (Note that the recycling rule has to make a special case for when one argument has length zero - the output then has length zero as well.) Bill Dunlap TIBCO Software wdunlap tibco.com On Tue, Dec 12, 2017 at 9:41 PM, Maingo via R-help <r-help at r-project.org> wrote:

I'm a newbie for R lang. And I recently came across the "Recycling Rule" when adding two vectors of unequal length. I learned from this tutor [ http://www.r-tutor.com/r-introduction/vector/vector-arithmetics ] that: """""" If two vectors are of unequal length, the shorter one will be recycled in order to match the longer vector. For example, the

"Not that it really matters, but" Can someone explain how the row numbers get assigned in the following sequence? It looks like something funky happens when rbind() coerces 'bar' into a dataframe. In either sequence of rbind below, once you get past the first two rows, the row numbers count normally. Rgames> (foo<-data.frame(x=5,y=4,r=3)) x y r 1 5 4 3 Rgames>

hi, i have a list of data.frame that has same structure. i would like to know a efficient way of rbind-ing it. right now, i write: n = length(temp) # 'temp' is a list of data.frames temp2 = data.frame() for (i in 1:n) temp2 = rbind( temp2, temp[[i]]) return(temp2) but this is not an efficient way since we keeping overwriting temp2. i wonder if there's faster way. thanks --

Good morning, I'm running into trouble rbind-ing numeric matrices with differing numbers of rows. In particular, there seem to be issues whenever a one-row numeric matrix is involved. Assume A is a numeric matrix with 1 row and Y columns and B is a numeric matrix with X rows and Y columns. Let C be the result of rbinding A and B. Then C is a numeric matrix with X + 1 rows and Y columns, only

Hello, I have a list with n numerical components of different length (3, 4 or 5 values in each component of the list); I need to export this as a text file where each component of the list will be a row and where missing values should fill in the blanks due to the different lengths of the components of the list. I think that as a first step I should convert my list to a data frame, but this is

Sorry for the verbose example. I want to row bind two matrices, and all works except I want the column labelled "row" to be sequential in the new matrix, shown as "mat3" here, i.e. needs to be 1:6 and not 1:3 repeated twice. Any suggestions? Thanks J > colnm1 <- c("row","ti","counti") > colnm2 <-

Hi all, I'm having some trouble with rbind - this may be a bug or it may be my misunderstanding. If I do fileName <- paste(tempdir(),"test.txt",sep="/") file.create(fileName) x <- read.table(fileName, col.names=c("one","two","three")) I get a data frame with no rows, as documented. If I then try to rbind this with another data frame

Hi, I am doing the following: 1. I have a list of files.. Files1=list.files("some directory",pattern="some pattern") 2. I define a list as res=vector("list", length(files1)) 3. I read all the files into this list: res=lapply(files1, read.csv) I now want to rowbind all the items in the list into one big mass (all files have same number of columns). I tried

Hi, How to cbind or rbind different lengths vectors/arrays without repeating the elements of the shorter vectors/arrays ? > cbind(1:2, 1:10) [,1] [,2] [1,] 1 1 [2,] 2 2 [3,] 1 3 [4,] 2 4 [5,] 1 5 [6,] 2 6 [7,] 1 7 [8,] 2 8 [9,] 1 9 [10,] 2 10 [[alternative HTML version deleted]]

i have > x [1] 1 2 3 4 5 6 > y [1] 34 5 6 > z<-cbind(x,y) > z x y [1,] 1 34 [2,] 2 5 [3,] 3 6 [4,] 4 34 [5,] 5 5 [6,] 6 6 i don't want recycling, instead can we put NA /0 like below> z x y [1,] 1 34 [2,] 2 5 [3,] 3 6 [4,] 4 NA [5,] 5 NA [6,] 6 NA & want distance matrix -- View this message in context:

i have the following constructed and running very well,, thanks to Gabor Grothendieck for his help. >data.info <- c("station.id", "year", "date", "max.discharge") > > for(i in 1:num.files) { + station.id <- substring(data[i], 1,8) + DF <- read.table(data[i], sep=",", blank.lines.skip = TRUE) + z <- zoo(DF[,4],

Hi, According to its man page substring() "expands (its) arguments cyclically to the length of the longest _provided_ none are of zero length". So, as expected, I get an error here: > substring("abcd", first=2L, last=integer(0)) Error in substring("abcd", first = 2L, last = integer(0)) : invalid substring argument(s) But I don't get one here:

Hi, How to rbind these vectors from a list?: > l <- list(a = c(1, 2), b = c(1, 2, 3)) > l $a [1] 1 2 $b [1] 1 2 3 > do.call(rbind, l) [,1] [,2] [,3] a 1 2 1 b 1 2 3 Warning message: In function (..., deparse.level = 1) : number of columns of result is not a multiple of vector length (arg 1) > -J

Hi, I have several matrix in a list, for example: e [[1]] [,1] [,2] [1,] 1 3 [2,] 2 4 [[2]] [,1] [,2] [1,] 1 4 [2,] 2 5 [3,] 3 6 [[3]] [,1] [,2] [1,] 2 1 I would like to join them by column i.e. [,1] [,2] [,3] [,4][,5] [,6] [1,] 1 3 1 4 2 1 [2,] 2 4 2 5 NA NA [3,] NA NA 3 6 NA NA I have tried

Hi Everyone, I'm new to programming R and have accomplished my goal, but feel that there is probably a more efficient way of coding this. I'd appreciate any guidance that a more advanced programmer can provide. My goal -- I would like to find the length of the longest word in a string containing many words separated by spaces. How I did it -- I was able to find the length of the

Dear R users,I'm facing a trivial problem, but I really can't solve it. I've tried a dozen of codes, but I can't get the result I want. The question is: I have a dataframe like this one [,1] [,2] [,3] [,4] [,5] [1,] 1 2 3 4 5 [2,] 2 5 5 4 9 [3,] 1 6 8 1 2 [4,] 8 6 4 1 5 made up of decimal numbers, of course. I want to

Sorry if this has been covered here somewhere in the past, but ... Does anyone know why logical vectors are *silently* recycled, even when they are incommensurate lengths, when doing logical indexing? This is as documented: For ?[?-indexing only: ?i?, ?j?, ?...? can be logical vectors, indicating elements/slices to select. Such vectors are recycled if necessary to match

Hi all, Apologies if this has been asked before (a quick google didn't find it for me),and I know this is a case of behaving as documented but its so unintuitive (to me at least) that I figured I'd bring it up here anyway. I figure its probably going to not be changed, but I'm happy to submit a patch if this is something R-core feels can/should change. So I recently got bitten by

In the new version 0.90.0, rbind won't take a vector and a matrix from me, but works OK if I coerce the vector to a matrix. The following was run on a new session (i.e., no prior work), and has been duplicated on 2 machines: an SGI running Irix 6.5, and an Intel box running Red Hat Linux 6.0. Either case works fine in version 0.65.1. > t3 <- c(.5, .5) > t4 <-