Displaying 20 results from an estimated 10000 matches similar to: "Looking for the first observation within the month"
2008 Mar 10
1
Error in extracting monthly observation from a daily time series data
Hi all,
Suppose I have following dataset :
library(zoo)
SD = 1
date1 = seq(as.Date("01/01/90", format = "%m/%d/%y"), as.Date("12/31/08", format = "%m/%d/%y"), by = 1)
len1 = length(date1); data1 = zoo(matrix(rnorm(len1, mean=0, sd=SD*0.5), nrow = len1), date1)
Now I want to extract monthly observation.
obs =
2008 Jul 15
8
DO NOT REPLY [Bug 5615] New: iconv conversion not applied to symlinks
https://bugzilla.samba.org/show_bug.cgi?id=5615
Summary: iconv conversion not applied to symlinks
Product: rsync
Version: 3.0.3
Platform: Other
OS/Version: SunOS
Status: NEW
Severity: normal
Priority: P3
Component: core
AssignedTo: wayned@samba.org
ReportedBy: nils.goroll@hamburg.de
2012 Aug 21
2
apply question
This works, where zz is a dataframe:
for(i in 1:nrow(zz)) {
zzz[i,1]<-paste(zz[i,1],zz[i,2],sep="_")
}
I would like to use "apply" to concatentate two columns of text along with
a separator.
How?
Chet
[[alternative HTML version deleted]]
2003 Oct 10
3
command line limit under unix?
Dear all,
I have made my testing program to run successfully under unix in the
background. However, my simulation work does not work. I read the
foo.results file, I found it only have part of my code and not any output I
want. Is there any line limit? My code is nearly 400 line. I can cut some of
them, but I want to know whether there is any limit or exactly the number of
limit is. Thanks.
2004 Oct 16
7
sapply and loop
Dear all,
I am doing 200 times simulation. For each time, I generate a matrix and
define some function on this matrix to get a 6 dimension vector as my
results.
As the loop should be slow, I generate 200 matrice first, and save them into
a list named ma,
then I define zz<-sapply(ma, myfunction)
To my surprise, It almost costs me the same time to get my results if I
directly use a loop
2004 Oct 16
7
sapply and loop
Dear all,
I am doing 200 times simulation. For each time, I generate a matrix and
define some function on this matrix to get a 6 dimension vector as my
results.
As the loop should be slow, I generate 200 matrice first, and save them into
a list named ma,
then I define zz<-sapply(ma, myfunction)
To my surprise, It almost costs me the same time to get my results if I
directly use a loop
2011 Sep 30
1
last observation carried forward +1
Hi R-helpers
I'm looking for a vectorised function which does missing value replacement
as in last observation carried forward in the zoo package but instead of a
locf, I would like the locf function to add +1 to each time a missing value
occurred. See below for an example.
> require(zoo)
> x <- 5:15
> x[4:7] <- NA
> coredata(na.locf(zoo(x)))
[1] 5 6 7 7 7 7 7 12 13
2003 Oct 21
5
run R under linux
Dear all,
Our department uses the linux system and we are not allowed to submit job
directly. We must make a batch to submit through "qmon".
so, I make a foo.sh file, which only contains one line: nohup R --vanilla <
foo.txt > foo.results
foo is all my codes. It is a simulation of 200 times. I set the seed at the
beginning. It is to estimate the success probability, which is
2003 Jun 17
3
ssh does not work
Dear all,
I got "permission denied" msg when I try to connect via SSH. The password
that I used was correct as I can establish the connection via telnet using
the same password. Any idea why this can happen??
root at kfiisdc:/sandbox/jason ssh kfiisdev
Use of this system by unauthorized persons or in an unauthorized manner is
strictly prohibited. Unauthorized access can and will be
2011 Oct 09
1
help with using last observation carried forward analysis for a clinical trial please
Hi,
I have a series of id's with multiple visits and questionnaire scores. This
is a clinical trial that will be analyzed using the last observation carried
forward method. In other words, in order to comply with intent to treat
analysis when many subjects withdraw, data points for the last visit must be
generated and filled in with the last observation. The ultimate goal is to
tabulate the
2004 Sep 30
1
Vectorising and loop (was Re: optim "a log-likelihood function")
>From: Sundar Dorai-Raj <sundar.dorai-raj at PDF.COM>
>Reply-To: sundar.dorai-raj at PDF.COM
>To: Zhen Pang <nusbj at hotmail.com>
>CC: r-help at stat.math.ethz.ch
>Subject: Vectorising and loop (was Re: [R] optim "a log-likelihood
>function")
>Date: Wed, 29 Sep 2004 18:21:17 -0700
>
>
>
>Zhen Pang wrote:
>
>>
>>I also use
2005 Jan 05
2
Status of Windows builds for libvorbis/libogg
Hi all,
I've just done a quick check of the libvorbis Visual C++ 6.0 project on
Windows, and am happy to say that both libvorbis and libogg build fine.
(Theora isn't quite so lucky -- see the theora-dev mailing list for
details on that.) There are two suggestions I can make, though:
1. To build properly, the directories must be checked out with
certain names, and in paths
2011 Jul 22
2
Picking returns from particular days of the month from a zoo object
Hello,
I would like to implement a "turn-of-the-month' trading strategy in R.
Given a daily series of stock market return data as a zoo object, the strategy
would go long (buy) four trading days before the end of the month, and sell the
third trading day of the following month.
How can I select these days, particularly the fourth day before and the third
day after the turn of the
2015 Nov 06
2
(sin asunto)
Hola a tod en s,
sigo intentando representar una variable en función de meses. En la columna
Mesos tengo los meses de la siguiente manera:
01/08/1996, 01/09/1996 etc.
He probado con el siguiente comando:
plot(Mesos, Serie01)
obteniendo
y tendría que obtener:
[image: Imágenes integradas 2]
Pero donde pone Observation Index, me gustaria tener los meses (para esta
grafica he usado
2011 May 04
1
two-way group mean prediction in survreg with three factors
I'm fitting a regression model for censored data with three categorical
predictors, say A, B, C. My final model based on the survreg function is
Surv(..) ~ A*(B+C).
I know the three-way group mean estimates can be computed using the predict
function. But is there any way to obtain two-way group mean estimates, say
estimated group mean for (A1, B1)-group? The sample group means don't
2018 Jul 13
2
Whitelist file for LDAP authentication
Hi,
The dovecot version is 2.2.33.2 and we are using LDAP to do the authentication for SMTP service.
We have the following configuration in auth-ldap.conf.ext to deny some users for LDAP auth.
passdb {
args = /etc/dovecot/deny.smtp
driver = passwd-file
deny = yes
}
passdb {
args = /etc/dovecot/dovecot-ldap.conf
driver = ldap
}
And now we want to change the mechanism and only users
2014 Jan 31
3
[LLVMdev] where to start?
Hi All,
I am an experienced compiler engineer, I want to get involved in LLVM but
don't know where I should start with. Can someone give any suggestion for
my situation? I hope can do some easy work at beginning, then do some
challenge work when I am familiar and comfortable with LLVM. I am
interested in optimizations and code generations, but I am open to other
areas either.
Any suggestion
2013 Jun 05
1
[LLVMdev] a document bug in lib/CodeGen/README.txt
I think I found a bug in lib/CodeGen/README.txt:
The register "lr" should be "r4" in instruction "str lr, [sp, #+52]" of :
and then "merge" mul and mov:
> mul r4, r4, lr
> str lr, [sp, #+52]
> ldr lr, [r1, #+32]
> sxth r3, r3
> mla r4, r3, lr, r4
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An HTML
2007 May 23
1
Catenating factors.
I was recently asked by one of new colleagues how to combine, or catentate,
or concatentate two factors. If x and y are factors, doing c(x,y) appears
to coerce x and y to numeric mode before catenating them. So what does one
do if one wants the result to be a factor whose levels are the union of the
levels of x and y? I vaguely recall seeing this discussed in r-help, but I
can't find
2007 May 02
1
how to concatinate the elements of some text vectors cat() or print() ?
I have some comment text taken from a SAS data file.
It is stored in two vectors and is difficult to read.
I would like to simply concatentate the individual
entries and end up with a character vector that give
me one line of text per comment.
I cannot see how to do this, yet it must be very easy.
I have played around with cat() and print with no
success. Would someone kindly point out where I