similar to: lorena

Hi, I tried to use the Croston function from the forecasting package 1.24<http://robjhyndman.com/software/forecasting> with the code below, but I get in return this message "*Error in decompose(ts(x[1L:wind], start = start(x), frequency = f), seasonal) : time series has no or less than 2 periods*". histValues

Hi, I'm currently working with a SARIMA model from which I want to make simulations. As I understand, neither sarima.Sim nor the functions in the gsarima package use historic realizations of the time series to simulate future values. However, I want to use historic values as input and simulate future values based on the history. Anyone who know whether such a function is available

If we drag a file from a Windows directory - say autoexec.bat and drop it onto a samba mapped Unix drive, when we then go to the Unix box and vi the file all the lines end in the DOS EOL character (^M) is there any option/configuration in samba to make it convert DOS text files to UNIX format? Brendan Flanagan Leyland Trucks Ltd, Croston Road, Leyland, PR26 6LZ Phone: 01772 625715 Email:

I would like to simulate some SARIMA models, e.g. a SARIMA (1,0,1)(1,0,1)[4] process. I installed the package 'forecast', where the function simulate.Arima should do what I am trying to do. I am not able to understand how it works Could somebody help me with an example? thank you Stefano Sofia AVVISO IMPORTANTE: Questo messaggio di posta elettronica pu? contenere informazioni

i am using sarima() function as below ___________________________________________________________________________________________ sarima=function(data,p,d,q,P=0,D=0,Q=0,S=-1,tol=.001){ n=length(data) constant=1:n xmean=matrix(1,n,1) if (d>0 & D>0) fitit=arima(data, order=c(p,d,q), seasonal=list(order=c(P,D,Q), period=S),

Does anyone have an exemple of how to fit a SARIMA model , with a MA part, with the package dynlm? Best regards. --------------------------------- [[alternative HTML version deleted]]

I'm trying to fit a SARIMA(p,d,q)x(P,D,Q) with seasonal period s to some data. When dealing with these types of models one often looks at the ACF and PACF of the time series at lags that are multiples of s, to identify potential values of P, Q. How would I do this in R given the original time series? Secondly given a time series x acf(x) just gives me the plot of the acf. How would I actually

Hi, I have a problem with the ARIMA function, occuring when I set the parameter per (the period of SARIMA model) to a high value (see the exemple bellow). It seems that when per is high it takes a too large amount of memory to calculate the model and I have a memory storage error. But I don't really understand why it takes more memory when per is high, as there is the same number of

Hi..   R Program is shown ARIMA output as below then SARIMA equation is be   (1 - 0.991B^{12})z_t + 43.557 = (1+0.37B)(1-0,915B^{12})a_t    But I try to calculate it by manual . It look like it 's big different from R sofeware,   I am not sure this equation is correct or not . PLS supoort me to confirm it   Arima Model ( 0,0,1)(1,0,1)   No Transformation Constant   >> 43.557 , t = 10.09

Hi, My query is related to ARIMA function in stats package. While looking for the time series literature I found following link which highlights discrepancy in "arima" function while dealing with differenced time series. Is there a substitute function similar to "sarima" mentioned in the following website implemened in R? Any pointers would be of great help.

Hello , I have estimated the following model, a sarima: p=9 d=1 q=2 P=0 D=1 Q=1 S=12 In R 2.12.2 Call: arima(x = xdata, order = c(p, d, q), seasonal = list(order = c(P, D, Q), period = S), optim.control = list(reltol = tol)) Coefficients: ar1 ar2 ar3 ar4 ar5 ar6 ar7 ar8 ar9 0.3152 0.8762 -0.4413 0.0152 0.1500 0.0001 -0.0413 -0.1811

Hello , I have estimated the following model, a sarima: p=9 d=1 q=2 P=0 D=1 Q=1 S=12 In R 2.12.2 Call: arima(x = xdata, order = c(p, d, q), seasonal = list(order = c(P, D, Q), period = S), optim.control = list(reltol = tol)) Coefficients: ar1 ar2 ar3 ar4 ar5 ar6 ar7 ar8 ar9 0.3152 0.8762 -0.4413 0.0152 0.1500 0.0001 -0.0413 -0.1811

Hi, I saw that tsdiag function doesn't provide a correct result for Ljung-Box test. I want to use Box.test function for this, but I don't know how to determine lag parameter for this function. For fitdf, as I'm using a SARIMA model (0,1,1)(0,1,1)12, I decided to set it to 2. Can you confirm me the value for fitdf and give me a way to determine the lag value? Thanks Myriam -- View

Dear all, I'm trying to understand how the strucchange package is working and I have been looking at the examples given for the Fstats() function. The first example (Nile), shows one peak in the F-stats and one breakpoint is estimated, that can be plotted using the following code ## Nile data with one breakpoint: the annual flows drop in 1898 ## because the first Ashwan dam was built

Hi, the function makeARIMA(), designed to construct some state space representation of an ARIMA model, uses a C function called getQ0, which can be found at the end of arima.c in R source files (library stats). getQ0 takes two arguments, phi and theta, and returns the covariance matrix of the state prediction error at time zero. The reference for getQ0 (cited by help(arima)) is:

Hola, a lo mejor es una tontería, pero el paquete ha tenido actualizaciones? No conozco que paquetes usas pero recuerdo un script de text minig con el paquete tm que me daba error tras unos meses guardado por una actualización. un saludo El día 9 de abril de 2015, 13:26, Marcelino de la Cruz <marcelino.delacruz en upm.es> escribió: > puedes comprobar esto: > >

Does anyone have some a nice simple example of how this function is used? Thanks, Jason

Hi, Is R's implementation of Seasonal ARIMA in the arima() function a multiplicative or an additive model? e.g., is an ARIMA(0,1,1)(0,1,1)[12] from arima() the same as Box et al's ARIMA(0,1,1)x(0,1,1)[12] (from Time Series Analysis 1994, p.333). From another post http://tolstoy.newcastle.edu.au/R/help/04/07/0117.html I suspect it's additive but I'm not sure. Thanks, Gad --

Hola Javier, Si, cuando hablo de valor observado me refiero al valor real en campo y el predicho al que estiman los modelos. Disculpa, que no lo detallase así desde el principio. En mi caso trabajo con dos diferentes: Zero inflated y Binomial Negativo y me gustaría comprobar que diferencia (distancia) existe entre cada uno de ellos y la realidad. Estoy trabajando con los siguientes paquetes:

Buenos días, Me gustaría aplicar una regresión múltiple a los datos con los que trabajo pero no se como introducir los datos en R. He probado introducir el siguiente comando: modeloM<-lm(AVE.~ d1 + as.factor(d1T)*Tariff) summary(modeloM) Pero me da el siguiente error: > summary(modeloM) Error in if (attr(z$terms, "intercept")) sum((f - mean(f))^2) else sum(f^2) : argument is