similar to: plot without points overlap

Hi Duncan, Thanks for your reply. Yes, it does seem to be specific to the CTYPE setting to Chinese on Windows. If I set it to English using Sys.setlocale() there is no problem, then back to Chinese and the authors disappear: Sys.setlocale("LC_ALL","English") citation("readr") #' To cite package ?readr? in publications use: #' #' Hadley Wickham, Jim

Hi, Duncan i have forwarded this thread to Nathan, who promised to look into it. Andrie On 17 Jun 2017 17:26, "Duncan Murdoch" <murdoch.duncan at gmail.com> wrote: > On 17/06/2017 9:13 AM, Ben Marwick wrote: > >> Hi Duncan, >> >> Thanks for your reply. Yes, it does seem to be specific to the CTYPE >> setting to Chinese on Windows. If I set it to

Hi to all, Here is a question which I cannot solve. Appreciate so much for any suggestions! I have a squared region which is irregularly divided into many rectangular patches. Each patch is associated with a value, and two patches possibly share a common value. I hope to fill in each patch a pattern according to its value. For instance, if a patch has value 1, then I fill in that patch

Hi, I seek to identify those points in/outside a multidimensional convex hull (geometry::convhulln). Any suggestions? Background just in case I'm going down a really wrong road: Given an observed data set with one dependent/observed variable (Y) and multiple (3 to 10) independent/design variables (X1, X2, ...) I want to increase the number of points by interpolating. I'm using

Hi, I'm kinda new of the R world. I need to use the heatmap or heatmap.2 function to plot correlation values. 2 questions: - how can I specify a color palette? (would like to have a transition from blue(-1) to white(0) to red(1)) - how can I use heatmap.2 imposing a specific order (like hclust.order)? I mean, I don't want heatmap.2 to re-cluster/re-order my data but just to plot them

Dear useRs, I'm trying to create a 10x7 rectangular grid of individual plots, each of which is a contour plot that shows a slice from a three-dimensional matrix. How can I specify that I do not want any margin at all between the plots, nor tick marks or axis labels? I have tried setting every layout.widths$XXX to zero without success. And if someone knows of a better way to visualize a 3D

Bare test code: My simple Java test class source and R test code follow: public class RJavTest { public static void main(String[]args) { RJavTest rJavTest=new RJavTest(); } public final static String conStg="testString"; public final static double con0dbl=10000001; public final static double[]con1Arr=new double[] { 10001,10002,10003,10004,10005,10006 }; public final static

Hello again, I am simply trying to import a rectangular table of strings. The table's dimensions are 1990 x 2, yet my read.table() command can only find 362 of the rows (and they're not the first 362). I would've taken the time to figure out how to use scan, readLines, or some other tool that can read in character strings, and then parse and input to a table, but that seems like

Recently I was trying to cite a package where the authors have ? and ? in their names. I found that on Windows the citation() function did not return the authors' names at all, but on Linux there was no problem (sessionInfos at the bottom): On Windows, no author names are returned: #--------------- > citation("readr") To cite package ?readr? in publications use: (2017).

hi, did'nt see anything in the archive: map('world',pro='rectangular',para=0) yields a strange artifact (horizontal bar) extending over the whole map at a certain latitude range (approx 65 deg. north), whereas map('world',pro='rectangular',para=180) (which should be the same) does not show the artifact. the artifact shows up in other projections as well,

Suppose I have the following data I want to scatterplot: > xy [,1] [,2] [1,] 0 0 [2,] 21 4 I start up a graphics window and fire away: > plot(xy) - but because the graphics window is square, the aspect ratio is wrong. So I add: > plot(xy, asp=1) - now the aspect ratio is correct, but the Y range is about -8 to 11, whereas my data has a Y range of 0

Hi there, i´m have vector of kernels. just like: kernels = c('gauss','epan','rectangular') i know there are density.default$kernels, but thats not my question here. my own kernel functions are running and working. my problem is the following is not working: dev.off() par(mfrow=c(3,3)) for(i in 1:length(bw)) { for(j in 1:length(kernels)) {

Hello. I have another rect question. If I want to make a lot of rectangular, without borders, and without any spaces between them, how could I do it? I.e. > plot(-1:1., -1:1., type = "n") > rect(0,-1,1,1,col="red",lwd=0,border=F,xpd=T) > rect(-1,-1,0,1,col="blue",lwd=0,border=F,xpd=T) will produce two rectangular, but there is space between them. How

Hi, I run a maanova analysis and found this message error: Error in ma.svd(X, 0, 0) : 0 extent dimensions I did a google search and found this: \item ma.svd: function to compute the sigular-value decomposition of a rectangular matrix by using LAPACK routines DEGSVD AND ZGESVD. \item fdr: function to calculate the adjusted P values for FDR control. I did a search for LAPACK and

I would like to plot some lat-lon data in a filled contour, and then overlay a map of the globe on top. I am trying something like this: filled.contour(lons, lats, glb.data, plot.axes={axis(1);axis(2);map(projection='rectangular',parameters=0,add =T)} ) The filled contour plots fine, and the map shows up, but only as a very tiny little black rectangle in a small area of the

My aim is to create a figure consisting of three maps: Alaska in the upper left corner, the 48 contiguous US states in the center right, and Hawaii in the lower left corner. In some ways the figure I'm trying to create is analogous to figure 1.5 in Paul Murrell's excellent "R Graphics", which combines a map of New Zealand with a map of the world. I tried adapting the code

Hi List, here I go again. Well I need to save plotted objects as .eps using the postscript() function, well I can do that but all resulting object are perfect squared dimensions (x = y). I need a rectangular output something like x = 2y dimension. Is it possible? The I’m new to R and postscript image format! I’m doing this…

Hi Duncan, I'm guessing I'll be able to look at this over the weekend/next week (probably closer to next week). It is on my list of things to do and I've just had a few other prior commitments that I have to finish first. Sorry for the delay. I'll chime in with a status update next week. Nathan -----Original Message----- From: R-devel [mailto:r-devel-bounces at r-project.org]

Hello. I am working on an analysis involving the nonlinear mixed model function (nlme) in R. The data consist of measures of carbon fixation by leaves as a function of light intensity and the parametric function (standard in this area because it has a biological interpretation) is a non-rectangular hyperbola. I cannot get the nonlinear mixed model (nlme) function to converge cleanly. I am

Dear All, I would like to plot a scalar (e.g. a temperature) on a non-rectangular domain (or even better: I would simply like to be able to draw a contour plot on an arbitrary 2D domain). I wonder if there is any tool to achieve that with R. I did some online search in particular on the list archives, found several queries similar to this one but was not able to find any conclusive answer. I