similar to: error message fitting tcopula

Displaying 20 results from an estimated 100 matches similar to: "error message fitting tcopula"

2010 Jun 10
0
error message in fitting tcopula
Hi r-users, I really need help in fitting the t-copula. I try to reproduce the example given by Jun Yan in "Enjoy the joy of copula" but I'm not sure how to correct the error based on the error message. I tried so many ways but still could not get it working. loglik.marg <- function(b, x) sum(dgamma(x, shape = b[1], scale = b[2], log = TRUE)) ctrl <- list(fnscale
2010 Jun 09
0
fitting t copula
Hi r-users, I try to fit the t copula using the gamma marginals.  But I got error message which I don't really understand. Thank you for any help given. myCop.t <- ellipCopula(family = "t", dim = 2, dispstr = "toep", param = 0.5, df = 8) myCop.t myMvd <- mvdc(copula = myCop.t, margins = c("gamma", "gamma"), paramMargins = list(list(mean = 0, sd
2007 Jun 22
2
fitCopula
I am using R 2.5.0 on windows XP and trying to fit copula. I see the following code works for some users, however my code crashes on the chol. Any suggestions? > mycop <- tCopula(param=0.5, dim=8, dispstr="ex", df=5) > x <- rcopula(mycop, 1000) > myfit <- fitCopula(x, mycop, c(0.6, 10), optim.control=list(trace=1), method="Nelder-Mead")
2006 Apr 24
3
the 'copula' package
Is anybody using the Copula package in R? The particular problem I'm facing is that R is not acknowledging the fitCopula command/function when I load the package and (try to) run something very simple: fit1 <- fitCopula(x1 = list(u11,u12,u13,u14,u15,u16,u17,u18), tCopula, optim.control = list(NULL), method = "BFGS") Anybody also using it, successfully or unsuccessfully?
2011 Jun 01
0
problems with copula
Hi, I'd like to know why using the program "R" I can't add a number of margins> 3, I have a problem with the graphics. Post here my script: > myCop.norm <- ellipCopula(family = "normal", dim = 3, param = 0.4) > myMvd <- mvdc(copula = myCop.norm, margins = c("norm", "norm","norm"), > paramMargins = list(list(mean = 0, sd
2018 Apr 21
0
Error : 'start' contains NA values when fitting frank copula
>>>>> Soumen Banerjee <soumen08 at gmail.com> >>>>> on Sat, 21 Apr 2018 17:22:56 +0800 writes: > Hello! I am trying to fit a copula to some data in R and > I get the error mentioned above. This is the code for a > reproducible example - (not really reproducible: You did not set the random seed, so the data is different every time;
2012 Oct 19
1
quantile regression using copulas
Hi all, Has anyone used the qua.regressCOP2 function from the copBasic package??? The default copula function used in this function is plackett copula and I wanted to use archimedean copula. Attached below is my code: mycop<-frankCopula V=seq(0.001,0.99,by=0.000217) R<-qua.regressCOP2(0.25,V,cop=mycop,para=c(3.504)) And this is the error I get: Warning messages: 1: In
2018 Apr 21
2
Error : 'start' contains NA values when fitting frank copula
Hello! I am trying to fit a copula to some data in R and I get the error mentioned above. This is the code for a reproducible example - library(copula) data = matrix(data=runif(600),nrow=200,ncol=3) data[,2] = 2*data[,1] data[,3] = 3*data[,1] fr_cop = frankCopula(dim=3) fit_fr_cop = fitCopula(fr_cop,pobs(data),method = "mpl") #Error Here The error says : Error in fitCopula.ml(copula, u
2007 Jan 21
1
for loop problem
Hello R users, A beginners question which I could not find the answer to in earler posts. My thought process: Here "z" is a 119 x 15 data matrix Step 1: start at column one, bind every column with column 1 Step2: use the new matrix, "test", in the fitCopula package Step3: store each result in myfit, bind each result to "answer" Step4: return "answer"
2007 Jun 24
2
matlab/gauss code in R
Hi all! I would like to import a matlab or gauss code to R. Could you help me? Bye, Sebasti?n. 2007/6/23, r-help-request en stat.math.ethz.ch <r-help-request en stat.math.ethz.ch>: > Send R-help mailing list submissions to > r-help en stat.math.ethz.ch > > To subscribe or unsubscribe via the World Wide Web, visit >
2007 Jan 18
0
fitCopula method in R
-- Hello, I am attempting to fit monthly stock returns to possible copula functions using the copula package in R. Below is my code (mat2 is a 2x119 matrix of the two stock returns): my.cop <- normalCopula(param=.3, dim = 2, dispstr = "un") myfit <- fitCopula(mat2,my.cop, start=.65, optim.control= list(NULL), method = "BFGS") myfit Unfortunately, I continue to receive
2007 Feb 01
0
traverse through many columns of a matrix in a function
Hello everyone, Here is the setup. z is a 119 x 15 matrix, m_index is a 119 x 5 matrix What I am trying to do is return the results from fitCopula by sequentially binding all 15 columns of z to the first column of m_index, (cbind(z[,1],m_index[,1]),(cbind(z[,2],m_index[,1]), etc. Unfortunately, my code below only binds z[,1] and m_index[,1] and return the same result 14 times. Any ideas on
2007 Mar 01
1
Fit Student Copula
Hello everybody, I have a big problem that I do not manage to solve ! I will be very grateful if you can solve this ! I want to fit a t Copula with the copula package : > student.cop <- ellipCopula("t", param = c(0.5, 0.6, 0.7), dim = 3, dispstr = "un",df=5) > x<-rcopula(student.cop,1000) > fit <- fitCopula(x, student.cop, c(0.5,0.5,0.5,5)) And there is an
2009 Apr 22
1
Copula package
Hi R-users, I would like to use the copula package.? I? the package plus the mvtnorm and try to run the example given, but I got the following message: install.packages(repos=NULL,pkgs="c:\\Tinn-R\\copula_0.8-3.zip") norm.cop <- normalCopula(c(0.5, 0.6, 0.7), dim = 3, dispstr = "un") t.cop <- tCopula(c(0.5, 0.3), dim = 3, dispstr = "toep", df = 2, df.fixed =
2023 Nov 07
1
Concordance and Kendall's tau in copula
Dear I estimate a sample selection model using the Clayton copula and Burr and Gaussian marginal. I need to derive ther Kendall'sw tau from the concordance coefficient by integration. I came across a way to do that in R long time ago but cannot find it again. Can somewone tell me what to read and what to use? Thank you. Steven Yen
2007 Jul 26
0
Fit t Copula
Hi, I am trying to fit t copula to some data, and I am using the following function in the library(QRMlib). Udatac <- apply(datac, 2, edf,adjust=1) tcopulac <- fit.tcopula.rank(Udatac) But the error message come out "Error in fit.tcopula.rank(Udatac) : Non p.s.d. covariance matrix" Could anyone give me some advice? In fact, I am not sure what the "adjust=1" is used for.
2006 May 12
3
Maximum likelihood estimate of bivariate vonmises-weibulldistribution
Thanks Dimitris!!! That's much clearer now. Still have a lot of work to do this weekend to understand every bit but your code will prove very useful. Cheers, Aziz -----Original Message----- From: Dimitrios Rizopoulos [mailto:Dimitris.Rizopoulos at med.kuleuven.be] Sent: May 12, 2006 4:35 PM To: Chaouch, Aziz Subject: RE: [R] Maximum likelihood estimate of bivariate
2011 Aug 25
2
axes start at end of plot
Hello all, I used the following script to generate a plot, but when I try to place axes, the axes start at the end of my plot and continue off the plot; the attached image shows what happens when I try to generate axes. library(fields) as.matrix(read.table("Matrix.txt", sep="\t"))->x #the matrix is a square matrix measuring 104x104; it was too large to attach #on left:
2012 May 21
1
problem with data frame to numeric transformation
http://r.789695.n4.nabble.com/file/n4630788/GOF_CGIK.R GOF_CGIK.R http://r.789695.n4.nabble.com/file/n4630788/RESIDSNEWr.csv RESIDSNEWr.csv In order to save place, I attach the data and the R code, for which I have 2 questions. 1/ I cannot convert successfully the data frames with names "first" and "second" in numeric format. They participate here:
2011 Aug 07
0
Fitting t copula
I'm a new user of R and a novice user in copula R package. I want to fit 3-dimensional t copula for my trivariate data. So I used the command t.cop <- tCopula(c(0.785,0.283,0.613),dim=3,dispstr="un",df=6,df.fixed = TRUE) where c(0.785,0.283,0.613) is the correlation pattern of my data with 0.785 pearson correlation between variable 1-2, 0.283 correlation between 1-3 and 0.613