similar to: data frame manipulation with zero rows

Displaying 20 results from an estimated 700 matches similar to: "data frame manipulation with zero rows"

2010 Jun 01
1
data frame manipulation ddply
Dear group, Here is my data frame: futures <- structure(list(DESCRIPTION = c("CORN Jul/10", "CORN Jul/10", "CORN Jul/10", "CORN Jul/10", "CORN Jul/10", "LIVE CATTLE Aug/10", "LIVE CATTLE Aug/10", "SUGAR NO.11 Jul/10", "SUGAR NO.11 Jul/10", "SUGAR NO.11 Jul/10", "SUGAR NO.11
2010 Aug 04
3
merge two data frames
Dear list, here are my two data frames: av <- structure(list(DESCRIPTION = c("COFFEE C Sep/10", "COPPER Sep/10", "CORN Dec/10", "CRUDE OIL miNY Sep/10", "GOLD Aug/10", "HENRY HUB NATURAL GAS Sep/10", "PALLADIUM Sep/10", "SILVER Sep/10", "SOYBEANS Nov/10", "SPCL HIGH GRADE ZINC USD", "SUGAR
2010 May 11
1
merge two data frames
Dear group, I have these 2 following data frame: allcon <- structure(list(DESCRIPTION = structure(1:17, .Label = c("COFFEE C Jul/10", "COPPER May/10", "CORN Jul/10", "CORN May/10", "COTTON NO.2 Jul/10", "CRUDE OIL miNY May/10", "GOLD Jun/10", "HENRY HUB NATURAL GAS May/10", "ROBUSTA COFFEE (10)
2010 Apr 30
1
read.csv and blank character in object name of my data.frame
Dear group, Here is my data frame: position100415 <- structure(list(DESCRIPTION = structure(1:9, .Label = c(" SUGAR NO.11 Jul/10 ", " SUGAR NO.11 May/10 ", "CORN May/10 ", "COTTON NO.2 Jul/10 ", "CRUDE OIL miNY May/10 ", "ROBUSTA COFFEE (10) Jul/10 ", "SILVER May/10 ", "SOYBEANS Jul/10 ", "WHEAT May/10
2010 Apr 27
1
save a data frame in environment
Dear group, Here is my function : position<-function(x) { pose<-read.csv2((paste(c("LSCPos",x,".csv"),collapse="")),dec=".",sep=",",as .is=T,h=T,skip=1)[,c(4,8,14,15)] pose$CREATED.DATE<-as.Date(pose$CREATED.DATE,"%d/%m/%y") futures<-pose[-grep("USD",pose[,1]),]
2011 Feb 08
4
Interactions in a nls model
I am interested in testing two similar nls models to determine if the lines are statistically different when fitted with two different data sets; one corn, another soybean. I know I can do this in linear models by testing for interactions. See Introductory Statistics with R by Dallgaard p212-218 for an example. I have two different data sets I am comparing to lai. ci.re should have very
2012 Aug 01
4
as.date: do not know how to convert 'test[1]' to class "Date"
I have an object, which I pull in from a csv file here http://r.789695.n4.nabble.com/file/n4638691/jan_2011.csv jan_2011.csv mydata <- read.csv("jan_2011.csv", header=TRUE, sep=",") > head(mydata) Delivery.Date Hour.Ending Repeated.Hour.Flag Settlement.Point Settlement.Point.Price 1 01/01/2011 01:00 N HB_BUSAVG
2010 Apr 23
2
read.csv data frame thousands separator
Dear group, Here is my df, trades1 : trades1 <- structure(list(Instrument.Long.Name = c("CORN", "CORN", "CORN", "CORN", "CORN", "SOYBEANS", "SOYBEANS", "SOYBEANS", "SOYBEANS", "SOYBEANS", "SOYBEANS", "STANDARD LEAD USD", "STANDARD LEAD USD", "SPCL
2010 May 26
2
writing function : can't find an object
Dear group, Here is my function: #return the daily PL for day y PLDaily<-function(x,y) { #find elements in my directory with "LSCPos" in the name, keep the numeric part in the name and #create a list l<-gsub("\\D","",dir()[grep("LSCPos",dir())]) #select in the list the desired elements
2010 Apr 29
3
convert Factor as numeric
Dear group, I know this issue has been already covered, and before you reply I must say I have read the R-FAQ and search the mailing list archive. I still can't manage to change my factor to numeric as I couldn't find any clear answer. Here is my df : Pose1 <- structure(list(DESCRIPTION = structure(c(1L, 2L, 3L, 4L, 5L, 8L), .Label = c(" SUGAR NO.11 May/10 ", "COTTON
2010 Apr 28
1
gsub,regex and replacing
Dear group, I need to modify some characters in a data frame. I want to use gsub and the regex functionalities to do this. Here is the data frame (df): DESCRIPTION prix quantity 1 CORN Jul/10 -1.5 0 2 CORN May/10 -1082.0 -3 3 ROBUSTA COFFEE (10) Jul/10 11084.0 8 4 SOYBEANS Jul/10 1983.5
2010 May 12
1
data frame subscription
Dear group, Here is my df : pose16 <- structure(list(DESCRIPTION = structure(c(1L, 2L, 3L, 4L, 5L, 6L, 7L, 8L, 9L, 12L), .Label = c("COPPER May/10", "COTTON NO.2 Jul/10", "CRUDE OIL miNY May/10", "GOLD Jun/10", "ROBUSTA COFFEE (10) Jul/10", "SOYBEANS Jul/10", "SUGAR NO.11 Jul/10", "SUGAR NO.11 May/10",
2010 May 27
1
switch function
Dear group, Here is my df : trades <- structure(list(Trade.Status = c("DEL", "INS", "INS"), Instrument.Long.Name = c("SUGAR NO.11", "CORN", "CORN"), Delivery.Prompt.Date = c("Jul/10", "Jul/10", "Jul/10"), Buy.Sell..Cleared. = c("Sell", "Buy", "Buy"), Volume = c(1L, 2L, 1L),
2010 May 11
1
merging data frame
Dear group, I have 3 data frames I would like to merge. Here they are: pose16 <- structure(list(DESCRIPTION = structure(c(1L, 2L, 3L, 4L, 5L, 6L, 7L, 8L, 9L, 12L), .Label = c("COPPER May/10", "COTTON NO.2 Jul/10", "CRUDE OIL miNY May/10", "GOLD Jun/10", "ROBUSTA COFFEE (10) Jul/10", "SOYBEANS Jul/10", "SUGAR NO.11
2010 Apr 28
3
data frame move columns
Dear group, Here is my df: avprix <- structure(list(DESCRIPTION = c("CORN Jul/10", "CORN May/10", "ROBUSTA COFFEE (10) Jul/10", "SOYBEANS Jul/10", "SPCL HIGH GRADE ZINC USD", "STANDARD LEAD USD"), prix = c(-1.5, -1082, 11084, 1983.5, -2464, -118), quantity = c(0, -3, 8, 2, -1, 0), fees = c(-8.64, -30.24, -26.4, -25.92, -37.5,
2009 May 01
2
combine column names
Dear R-list, Is there any way I can extract part or whole column name from two variables and combine them? Not values, but column names. For example, I have data set with 70 variables. The column names are "Alfalfa", "Corn","Soybean",..."Sunflower". After I combine the two variable (say Alfalfa and Corn), I want to rename it as "AlfCor" or
2013 Jun 15
1
Downloading CSV file - RCurl help
There are some CSV file from the link below. I'm having trouble installing the package. Is this the package I have to use or is there another one I need to use? If so how do I get this one loaded. https://www.enmax.com/Power/Energy+Retailers/Settlement+Reports/Profile+settlement+report.htm install.packages("RCurl", repos =
2010 May 11
2
Regex and gsub
Dear group, Here is my df : df3 <- structure(list(DESCRIPTION = c("COPPER May/10", "COTTON NO.2 Jul/10", "CRUDE OIL miNY May/10", "GOLD Jun/10", "ROBUSTA COFFEE (10) Jul/10", "SOYBEANS Jul/10", "SUGAR NO.11 Jul/10", "SUGAR NO.11 May/10", "WHEAT Jul/10", "SPCL HIGH GRADE ZINC USD",
2012 Mar 22
1
Simalteneous Equation Doubt in R
Hi List l am interested in developing price model. I have found a research paper related to price model of corn in US market where it has taken demand & supply forces into consideration. Following are the equation: Supply equation: St= a0+a1Pt-1+a2Rt-1+a3St-1+a5D1+a6D2+a7D3+U1 -(1) Where D1,D2,D3=Quarterly Dummy Variables(Since quarterly data are considered) Here, Supply
2010 May 26
5
(no subject)
Dear group, Here is my data frame: > dput(u) structure(list(DESCRIPTION = structure(c(2L, 5L, 6L, 7L, 9L, 11L, 12L, 15L, 14L, 16L, 1L, 10L, 3L, 4L, 13L, 8L, 17L), .Label = c("COFFEE C Jul/10", "COPPER May/10", "CORN Jul/10", "CORN May/10", "COTTON NO.2 Jul/10", "CRUDE OIL miNY May/10", "GOLD Jun/10", "HENRY HUB