similar to: ggplot, qplot: alpha channel for colors corresponding to factor

Hi, I'm having problems with qplot and the order of numeric factor levels. Factors with numeric levels show up in the order in which they appear in the data, not in the order of the levels (as far as I understand factors!) Here is a minimal example: library(ggplot2) y <- c(-1,2,0,0,-2,-1) z <- factor(y,levels=c(-2,-1,0,1,2)) qplot(z) For me, the resulting plot is ordered: -1,2,0,-2

Hi list, I have data in a dataframe t1, with a column for different amounts spent, a column what it was spent on, and a column with dates, from which I create a new column with months. Example: amount <- rep(c(10,20,30),3) what <- rep(c("food","books","cycling"),3) when <- c(rep("2008-09-05",5),rep("2008-10-07",4)) t1 <-

Hi, I have a 5-paneled figure that i made using the facet function in qplot (ggplot). I've managed to arrange the panels into two rows/ three columns, but for the sake of easy visual comparisons between panels in my particular dataset, I want to have the two plots on the bottom align on the right hand side of the figure instead of the left. Here's an example: m <-

Dear list, I've written a function that plots subjects. Something like: myplot <- function(subject) { plot(subject) } Subjects are vectors, e.g. ... s1 <- c(200,200,190,180) ... and plotting them works fine, e.g. ... myplot(s1) Now I want to have "s1" etc appear in the plot title, but I don't know how to refer to this generically (the object "name"? I tried

Please help: I am using qplot as below and want to specify a different color scheme for race but dont know how, can someone show me. Thanks in advance Code and input file below: library(ggplot2) library(gridExtra) d<-read.table("results", header=TRUE, fill=TRUE) plot2<-qplot(X,Y,data=d,color=race,facets=TYPE~., xlab="X", ylab="Y") + theme_bw()

Dear list,   Using ggplot2 I could produce both boxplot and points in the same plot but instead of points I would like to label the different subjects with different colors or their idnumbers. Is there away to do it? Also how can I put three plots on the same graph with ggplot2? mfrow=c(3,1) did not do the job.   > dat    group time   id  freq 1      1   00 0018  5.21 2      1   00 3026  3.13

I get the following error when I run qplot() qplot(grade, read,data = hhm.long.m, geom = c("point", "smooth")) Error in smooth.construct.cr.smooth.spec(object, data, knots) : x has insufficient unique values to support 10 knots: reduce k. I am not sure how to tackle this problem. When I take a subsample (< 1000) than I am able to run that function but with my sample

Hi, I've run into a difficulty with qplot function (in the ggplot2 package). I can facet histograms even when the faceting variable contains missing values, but only so long as the faceting variable is not a factor. Example: y1 <- rnorm(10) x1 <- c(rep(1,5), rep(2,4), NA) x2 <- factor(c(rep(1,5), rep(2,4), NA)) library(ggplot2) qplot(y1, geom = "histogram", facets =

I have the following Data structure $ step45 : Factor w/ 2 levels $ obserror : num 6.2 6.2 5.6 6.6 6.6 ... $ Mon : num 2.2 2.0 1.0 3.2 2.0 ... $ inc.comp : num 4 5 2 5 5 5 5 5 4 4 ... all I wanted to do is plotting Mon against obserror, the colors should be by step45 and the size of the symbol should be according to inc.comp so I did this:

Playing with ggplot, something I'd promised myself I'd get around to. I've the following scenario: library(lattice) library(ggplot2) myData <- data.frame( x = rnorm(100), y = rnorm(100), group = 1:4 ) xyplot(y ~ x | factor(group), data = myData, layout = c(2, 2)) qplot(x, y, facets = ~ group, data = myData) In this code the lattice example gives me a 2x2 layout, whereas

Dear list, I have two vectors: x <- c("one","two") y <- paste(rep(x,2),"blah") I want to replace all occurrences of each element of x in y with something else, so that y looks like this: y [1] "something else blah" "something else blah" "something else blah" [4] "something else blah" I can do this using a loop: for (

Dear list, I have data like this: dat1 <- data.frame(subject=rep(1:10,2), cond1=rep(c("A","B"),each=5), cond2=rep(c("C","D"),each=10), choice=sample(0:1,10,replace=TRUE)) I would like to compare subjects' "choice" for (cond1=="A" & cond2=="C") vs

Dear List, yes, me again trying to work with qplot ;-) I would like to make several single plots within a loop, like this (simplified and so on...): trials <- c("A","B","C") mycolours <- ("wheat","darkolivegreen","lightgreen",

I have two lists of the same shape, like this: x <- list() x[[1]] <- c("one","two") x[[2]] <- c("three","four","five") y <- list() y[[1]] <- c(TRUE,FALSE) y[[2]] <- c(FALSE,TRUE,TRUE) I would like to index x "by" y, that is, the result in this case should be: z [[1]] [1] "one" [[2]] [1] "four"

Dear Rers, I have a function to barplot() a matrix, eg myfun <- function(x, ...) { barplot(x , ... )} (The real function is more complicated, it does things to the matrix first.) So I can do: m1 <- matrix(1:20,4) myfun(m1) myfun(m1, main="My title") I'd like to be able to add the number of rows of the matrix passed to the function to the "..." argument, eg

I'd like to generate a boxplot that has BOTH the overall distribution of a continuous variable (say age), and then a boxplot for each level of a stratifying variable (e.g. site). Does anyone have prototype code for this? Thanks, -- View this message in context: http://www.nabble.com/GGPLOT-QPLOT-Boxplot-with-summary-tp20095591p20095591.html Sent from the R help mailing list archive at

Dear list, I have a file that is comma delimited but contains some erroneous non-delimiter commas. I would like to replace these commas with semicolons and then read the correct file into R as a data frame. I want to do this from within R, without changing the original data file. My current idea of how to do this would be to use system("sed ...") and feed the result to read.csv(), but

Dear R users, I create a graphic with two plots side by side using layout(), like this: layout(matrix(c(1,2),1)) plot(1:10,main="left plot") lines(c(3:7,7:3),col="red") plot(10:1,main="right plot") The lines() obivously get added to the "left plot" plot. Now, I'm trying to write a function that builds up a plot bit by bit to then include it in a

Dear list, I would like to start some R workshops at King's College London, and to do so, I would like to use the "Use R!" logo at http://www.agrocampus-ouest.fr/math/useR-2009//useR%21%202008_fichiers/useR-middle.png Since it seems to be difficult to get a shell account at KCL, I also went ahead and registered use-r.org.uk and am starting to put together a website at

I'm having problems with this example, it is posted with reproduceable code below, both with the normal 0-6 scale and the desired 3-6 scale (with bars removed). How can I get the graph to have the desired 3-6 scale without removing the bars. Thanks! #Data