similar to: hist densities

Hi there, I was wondering why x<-rnorm(n=5000,mean=1.5,sd=0.25) h<-hist(x) sum(h$density) [1] 10 I thought the integral of the histogram should be one? These seems strange to me, or am I being silly... Regards Luke Spadavecchia PS. I'm using R 2.5.1 on Mac OSX

Today I wanted to experiment with different distributions an to see the hazard rates they imply. So I eventually ended up with this, which uses the hist object's handy $density and the cumsum function in R: x <- c(rweibull(21000,0.5,0.7)) #create "breaks" vector to go into histogram #need last break bigger than max(x) y <- seq(0,max(x)+2) histx <-

The following code is giving me problems. I want to export densities of a distribution to a csv file. At the bottom of the code I use the hist function to generate the densities. But hist is returning values greater than 1. I don't understand, why. Any help you can supply is greatly appreciated. # Set word path dir<-"~/Research/MR Distribution Analysis/" setwd(dir)

There were some questions about hist() a couple of days ago which triggered this post. My question/suggestion is about the y-axis in hist. There are reasons to prefer making the y-axis density=relative frequency/bin width. One reason is that the height of the plot does not depend on the bin width; another is that if your histogram is in density then you can easily superimpose a smooth theoretical

Hello, I have a problem with the hist() function and showing densities. The densities sum to 50 and not to 1! I use R version 2.9.1 (2009-06-26) and I load the seqinR library. My data is the following vector: [1] 0.1400000 0.2000000 0.2200000 0.2828283 0.1600000 0.1600000 0.3600000 [8] 0.1600000 0.2200000 0.2600000 0.2000000 0.3000000 0.2200000 0.2342342 [15] 0.1800000 0.2200000 0.1600000

I discovered a bug in hist(). Try the following: x<-c(-5,-4,-4,-4,-3,-3,-3,-3,-2,-2,0,0,0,0,1,1,1,3,3,5,6) # Note that sum(x)<0: sum(x) # [1] -13 hist(x) # looks ok hist(x,freq=F) # negative bars !! # and finally this gives not 1: sum(hist(x,plot=F)$rel.freqs) # [1] -0.8076923 The reason is, that "sum(x)" is used instead of "length(x)" in the following line near

Hello, To indicate probability densities instead of counts on a histogram, I specify freq = FALSE. However, I expect that summing all top y coordinates over all the intervals of the histogram will provide 1. 1) v <- c(0.2885, 0.2988, 0.3139, 0.2615, 0.3179, 0.3163, 0.2583, 0.3052, 0.2527, 0.3147, 0.3235, 0.2408, 0.2480, 0.3108, 0.3577, 0.2829, 0.2694, 0.3275, 0.3314, 0.2639, 0.3076,

Hi, people. Within ?hist (using R 2.3.0), one reads: density: values f^(x[i]), as estimated density values. If 'all(diff(breaks) == 1)', they are the relative frequencies 'counts/n' and in general satisfy sum[i; f^(x[i]) (b[i+1]-b[i])] = 1, where b[i] = 'breaks[i]'. I trip on this explanation each time I read it. Some R guardians will be

Dear All, I am a undergraduate using R for the first time. It seems like an excellent program and one that I look forward to using a lot over the next few years, but I have hit a very basic problem that I can't solve. I want to produce a standardised histogram, i.e. one where the area under the graph is equal to 1. I look at the manual for the histogram function and find this: freq:

Hello! Up to now I have been using hist() to display the distributions. Howevere, I noteiced strange numbers on y (vertical) axis, if I used probability = T or freq = F option. I thought it is a bug and launched the R-bug system and found some posts on that matter. Brian Ripley responded to one, that one should look at truehist() for that. Ok I can use truehist() if I want to see the ratios

I have problems getting a histogram with relative frequencies on the y-axis. Here is an example data set: > a <- c(4.626, 4.627, 4.627, 4.628, 4.629, 4.629, 4.630, 4.631, 4.632, 4.632) > d = hist(a,freq=F) > d$density [1] 299.9999 100.0000 200.0000 100.0000 100.0000 200.0000 The obtained densities are given by counts/(total n * bin width), with bin width being

Hi all, A friend send me a question on why does this: x<-rpois(100,1) sum( hist(x)$density ) Gives out "2" I tried this: sum( hist(x, freq =T)$density ) It didn't help. Then he came back with the following insight: # with breaks b<-c(0,0.9,1:8) sum(hist(x,breaks=b)$density) # Much more then 2 # but if we add weights according to the interval length

For the hist estimate >par(mex=1.3) >dens<-density(q) >options(scipen=4) > ylim<-range(dens$y) > h<-hist(q,breaks="scott",freq=FALSE,probability=TRUE, +? right=FALSE,xlim=c(9000,16000),ylim=ylim,main="Histogram of q(scott)") > lines(dens) >box() ? For the kernel estimate>options(scipen=4) > d <- density(q, bw =

Dear list, I'm new to R, please bear with my silly questions. I'm trying to get an understanding of why the results I get from a call to hist() are not as I thought I would get. When I use the parameter freq=FALSE, I think the plot will contain bars that none of them is larger than 1, because they're probabilities. But for my code, the bars exceeded 1. The actual data seems

On Sun, 11 Dec 2005 clausen at econ.upenn.edu wrote: > Full_Name: Andrew Clausen > Version: 2.1.0 > OS: Debian GNU/Linux > Submission from: (NULL) (71.242.192.73) > > > Hi, > > When I type > > hist(x, freq=F) > > I get a density function, as I expect. However, if I type > > plot(hist(x, freq=F)) > > then I get the same output as if I had

Hi, I have a couple of observations, a question or two, and perhaps a suggestion related to the plotting of density on the y-axis within the hist() function when freq=FALSE. I was using the function and trying to develop an intuitive understanding of what the density is telling me. After reading through this fairly helpful post:

Hi, This is a very basic question, but I would like to undestand hist(). I thought that the hist( , freq=FALSE) should provide the relative frequencies (probabilities), and so they should sum 1, however: set.seed(2) ah <- hist(rnorm(100), freq=F) sum(ah$intensities) [1] 2 set.seed(2) bh <- hist(rlnorm(100), freq=F) sum(bh$intensities) [1] 0.4999996 I'm getting similar figures with

just realized that the bin value is actually the relative frequency divided by the bin width. sorry for consuming band width. Alas, is there anyway to make hist() calculate relative frequencies irrespective of bin width? thanks Murad Nayal wrote: > > Hello, > > I am rather new to R. in trying to use the hist() command I get behavior > that is somewhat puzzling me, in short,

Hi, if I dermine the break points using the hist() function and then try to re-use these in a new histogram, R fails. Here is an example of the problem: ##First, plot a histogram: data(islands) foo <- hist(islands,freq=T) ##Now, try plot it again, with the previously determined break points: hist(islands,breaks=foo$breaks,freq=T) ##... this lead to the warning message: Warning message:

I want to make a histogram from the lengths vector which is part of the output of rle. But I don't know how to access that vector so that I use it as an argument of hist(). What argument must I use so that I use the lengths vector as an input to hist()? Example output is: Run Length Encoding lengths: int [1:4] 1 2 3 3 values : num [1:4] -1 1 -1 1 A printout of the function rle() may