similar to: plotting big zoo object memory problem

DateTime,Temp,SpCond,DOConc,Depth,pH,ORP,Turbidity+,Chlorophyll,Battery,Cond,DO%,Salinity,TDS 01/13/2006 17:01,10.87,84,9.36,0.664,7.3,132,28.8,3.1,11.5,0.062,84.6,0.04,0.055 01/13/2006 17:16,10.9,84,9.36,0.66,7.31,133,28.7,2.9,11.5,0.062,84.7,0.04,0.055 01/13/2006 17:31,10.92,84,9.36,0.655,7.3,132,28.4,2.6,11.4,0.062,84.8,0.04,0.055 01/13/2006

I have a matrix with data that runs from 1/1/06 00:01:00-1/31/08 23:46:00. I have read in the data with this fmt.chron <- function(x) { chron(sub(" .*", "", x), gsub(".* (.*)", "\\1:00", x)) } x <- read.zoo(file.choose(), sep=",", header=T, FUN=fmt.chron) plotted with this plot(x[,(seq(3, by=9, length.out=12))],

# chron library(chron) fmt.chron <- function(x) { chron(sub(" .*", "", x), gsub(".* (.*)", "\\1:00", x)) } z1 <- read.zoo(SC3.csv, sep = ",", header = TRUE, FUN = fmt.chron) z2 <- read.zoo(SC2.csv, sep = ",", header = TRUE, FUN = fmt.chron) z3<-c(z1, z2) write.table(z3, sep="," , "SC.csv") How do you

This is the same set of data that I have been working with for those in the know. it is a matrix of ~174 columns and ~70,000 rows. I have it as a zoo object, but I could read it in as just a matrix as long as the date time stamp won't be corrupted. here is an example of what a column would look like: 1/1/06 12:00, 1, 2, 3, 4, 5, 6, 7, 8, 9, 0, 1, 2, 3, 4, 5,6 ,7, NA #read in with the

I am was going to look at the as.yearmon function in the zoo package and write a as.day function to aggregate a time series of 96 observations per day into the mean for each day, but I don't know how to look at the code so that I can convert it into something I can use. On top of that I believe that it is probably an S3 method and I haven't quite gotten that far in my programming

DateTime RM61 11/30/2006 12:31 NA 11/30/2006 12:46 NA 11/30/2006 13:01 2646784125 11/30/2006 13:16 NA 11/30/2006 13:31 NA 11/30/2006 13:46 NA 11/30/2006 14:01 2666435177 11/30/2006 14:16 NA 11/30/2006 14:31 NA 11/30/2006 14:46 NA 11/30/2006 15:01 2653041914 11/30/2006 15:16 NA 11/30/2006 15:31 NA 11/30/2006 15:46 NA 11/30/2006 16:01 2693126189 11/30/2006 16:16 NA 11/30/2006 16:31 NA 11/30/2006

library(zoo) library(chron) t1 <- chron("1/1/2006", "00:00:00") t2 <- chron("1/31/2006", "23:45:00") deltat <- times("00:15:00") tt <- seq(t1, t2, by = times("00:15:00")) d <- sample(33:700, 2976, replace=TRUE) sin.zoo <- zoo(d,tt) #there are ninety six reading in a day d.max <- rollapply(sin.zoo, width=96, FUN=max)

R version 2.8.0 (2008-10-20) i386-pc-mingw32 locale: LC_COLLATE=English_United States.1252;LC_CTYPE=English_United States.1252;LC_MONETARY=English_United States.1252;LC_NUMERIC=C;LC_TIME=English_United States.1252 attached base packages: [1] stats graphics grDevices utils datasets methods base other attached packages: [1] StreamMetabolism_0.01 chron_2.3-24 zoo_1.5-4 loaded

I would like to merge zoo objects that are stored in a list into one big zoo object with one index for all of the observations. I have created the list (74 dataframes) with the code below, and have tried the do.call(merge, foo) in the call and the output is not what I expected. Any help would be greatly appreciated. Stephen Sefick ###################################################level logger

day<-structure(c(7.7, 7.7, 7.7, 7.7, 7.7, 7.71, 7.7, 7.71, 7.71, 7.7, 7.7, 7.7, 7.7, 7.69, 7.68, 7.68, 7.67, 7.67, 7.67, 7.66, 7.65, 7.65, 7.65, 7.64, 7.64, 7.63, 7.63, 7.63, 7.62, 7.62, 7.62, 7.62, 7.63, 7.63, 7.63, 7.63, 7.63, 7.64, 7.64, 7.65, 7.65, 7.65, 7.66, 7.66, 7.67, 7.67, 7.67, 7.68, 7.68, 7.69, 7.69, 7.69, 7.69, 7.7, 7.7, 7.7, 7.7, 7.7, 7.71, 7.7, 7.7, 7.71, 7.71, 7.7, 7.7, 7.7, 7.7,

#I would like to interpolate a straight line between 06/08/06 04:16:00 - 06/08/06 20:31:00 with values and then sum them. This is an estimate of ecosystem #respiration and I will be using this in a larger context(48 days of these diurnal curves), but for right now I am just trying to figure out how to do it for this one #day example. I have some other code for Ecosystem (stream) Metabolism that

NOTE: I will provide data if necessary, but I didn't want clutter everyones mailbox All: I have a time series with level and temperature data for 11 sites for each of three bases. I will have to do this more than once is what I am saying here. OK, The time series are zoo objects with index values in chron format. The problem is that the date and times should be at even 15 min intervals,

I would like to include this in a package. The S3 methods on R CMD check says * checking S3 generic/method consistency ... WARNING window: function(x, ...) window.chron: function(data, day1, hour1, day2, hour2, ...) See section 'Generic functions and methods' of the 'Writing R Extensions' manual. I have looked and can not figure it out. This function is for convience. What

R 2.12.2 on Scientific Linux 6.4 #works chron(times.="15:00:00", format=c(times="h:m:s")) #doesn't work chron(times.="15:00", format=c(times="h:m")) From chron Manual: The times format can be any permutation of "h", "m", and "s" separated by any one non-special character. The default is "h:m:s". what am I

#the below code is the way that I would like the plot to look. I have tried to write a panel function: my.panel <- function(x, y, ..., pf = parent.frame()) { axis(side=1, at = seq(rng[1], rng[2], 1/12), labels = n, tcl = -0.3) } #but it does not work and I am at a loss and help would be appreciated. I will use this for multiple library(zoo) library(chron) #this is what I would like the

has anyone had problems with the upgrade to R 2.8 and chron date classes. I have a large zoo object that has a chron index, and it is taking 5x or so longer to do the same calculation as with 2.7 if it doesn't fail. I will provide anything necessary I am not entirely sure what ya'll would need if anything to try and reproduce the behavior. I am using the package StreamMetabolism. thanks

the date were created with chron with this argument format=c(dates="Y/m/d", times="H:M:S")) so I have the dates being displayed as (10/06/22 12:00:00) I would like to have them displayed as "2010-06-22 12:00:00" or "%Y-%m-%d %H:%M:%S" and then I can convert these for mergeing with another data frame x <- (structure(c(14464, 14464.0104166667,

I would like a sequence of dates with a time step of 15 minutes starting: 1/1/2006 00:00:00 - 12/31/2006 23:45:00 function(x) { chron(sub(" .*", "", x), gsub(".* (.*)", "\\1:00", x)) } this is the piece of code I use to read in zoo objects for any help I would be grateful I have tried sequence and I can not seem to get it to work -- Let's not

These are date and times in the format YYYYMMDDhhmmss. I would like to take this column and make a chron object form them. I have tried a couple of the split family of functions but they need character input here is the data: date.time <- c(19851001001500, 19851001003000, 19851001004500, 19851001010000, 19851001011500, 19851001013000, 19851001014500, 19851001020000, 19851001021500,

I am running into a problem with allocating these files to a list as they are read in through a for loop. I know I am probably doing something wrong, but I can't figure out what. I know this is not reproducible. I am ending up with a data frame of the very last file to be read in. I know it is in the indexing, but I can't wrap my head around it. thanks for all of the help, Stephen