similar to: plotting big zoo object memory problem

Displaying 20 results from an estimated 9000 matches similar to: "plotting big zoo object memory problem"

2008 Mar 03
2
read.zoo problem reading in date time
DateTime,Temp,SpCond,DOConc,Depth,pH,ORP,Turbidity+,Chlorophyll,Battery,Cond,DO%,Salinity,TDS 01/13/2006 17:01,10.87,84,9.36,0.664,7.3,132,28.8,3.1,11.5,0.062,84.6,0.04,0.055 01/13/2006 17:16,10.9,84,9.36,0.66,7.31,133,28.7,2.9,11.5,0.062,84.7,0.04,0.055 01/13/2006 17:31,10.92,84,9.36,0.655,7.3,132,28.4,2.6,11.4,0.062,84.8,0.04,0.055 01/13/2006
2008 Jul 02
1
Zoo plotting behavior
I have a matrix with data that runs from 1/1/06 00:01:00-1/31/08 23:46:00. I have read in the data with this fmt.chron <- function(x) { chron(sub(" .*", "", x), gsub(".* (.*)", "\\1:00", x)) } x <- read.zoo(file.choose(), sep=",", header=T, FUN=fmt.chron) plotted with this plot(x[,(seq(3, by=9, length.out=12))],
2008 Mar 03
1
write csv file from zoo object
# chron library(chron) fmt.chron <- function(x) { chron(sub(" .*", "", x), gsub(".* (.*)", "\\1:00", x)) } z1 <- read.zoo(SC3.csv, sep = ",", header = TRUE, FUN = fmt.chron) z2 <- read.zoo(SC2.csv, sep = ",", header = TRUE, FUN = fmt.chron) z3<-c(z1, z2) write.table(z3, sep="," , "SC.csv") How do you
2008 Mar 06
2
replace NA with 9999 in zoo object
This is the same set of data that I have been working with for those in the know. it is a matrix of ~174 columns and ~70,000 rows. I have it as a zoo object, but I could read it in as just a matrix as long as the date time stamp won't be corrupted. here is an example of what a column would look like: 1/1/06 12:00, 1, 2, 3, 4, 5, 6, 7, 8, 9, 0, 1, 2, 3, 4, 5,6 ,7, NA #read in with the
2008 Sep 22
1
as.day() Function (zoo question)
I am was going to look at the as.yearmon function in the zoo package and write a as.day function to aggregate a time series of 96 observations per day into the mean for each day, but I don't know how to look at the code so that I can convert it into something I can use. On top of that I believe that it is probably an S3 method and I haven't quite gotten that far in my programming
2008 Mar 07
1
zoo object won't plot
DateTime RM61 11/30/2006 12:31 NA 11/30/2006 12:46 NA 11/30/2006 13:01 2646784125 11/30/2006 13:16 NA 11/30/2006 13:31 NA 11/30/2006 13:46 NA 11/30/2006 14:01 2666435177 11/30/2006 14:16 NA 11/30/2006 14:31 NA 11/30/2006 14:46 NA 11/30/2006 15:01 2653041914 11/30/2006 15:16 NA 11/30/2006 15:31 NA 11/30/2006 15:46 NA 11/30/2006 16:01 2693126189 11/30/2006 16:16 NA 11/30/2006 16:31 NA 11/30/2006
2008 Aug 21
1
max and min with the indexes in a zoo object (or anything else that could solve the problem)
library(zoo) library(chron) t1 <- chron("1/1/2006", "00:00:00") t2 <- chron("1/31/2006", "23:45:00") deltat <- times("00:15:00") tt <- seq(t1, t2, by = times("00:15:00")) d <- sample(33:700, 2976, replace=TRUE) sin.zoo <- zoo(d,tt) #there are ninety six reading in a day d.max <- rollapply(sin.zoo, width=96, FUN=max)
2008 Nov 04
2
Zoo seems to be running slow in R 2.8.0 windows
R version 2.8.0 (2008-10-20) i386-pc-mingw32 locale: LC_COLLATE=English_United States.1252;LC_CTYPE=English_United States.1252;LC_MONETARY=English_United States.1252;LC_NUMERIC=C;LC_TIME=English_United States.1252 attached base packages: [1] stats graphics grDevices utils datasets methods base other attached packages: [1] StreamMetabolism_0.01 chron_2.3-24 zoo_1.5-4 loaded
2009 Aug 11
1
merge zoo objects contained in a list
I would like to merge zoo objects that are stored in a list into one big zoo object with one index for all of the observations. I have created the list (74 dataframes) with the code below, and have tried the do.call(merge, foo) in the call and the output is not what I expected. Any help would be greatly appreciated. Stephen Sefick ###################################################level logger
2008 Jul 29
1
combining zoo series with an overlapping index?
day<-structure(c(7.7, 7.7, 7.7, 7.7, 7.7, 7.71, 7.7, 7.71, 7.71, 7.7, 7.7, 7.7, 7.7, 7.69, 7.68, 7.68, 7.67, 7.67, 7.67, 7.66, 7.65, 7.65, 7.65, 7.64, 7.64, 7.63, 7.63, 7.63, 7.62, 7.62, 7.62, 7.62, 7.63, 7.63, 7.63, 7.63, 7.63, 7.64, 7.64, 7.65, 7.65, 7.65, 7.66, 7.66, 7.67, 7.67, 7.67, 7.68, 7.68, 7.69, 7.69, 7.69, 7.69, 7.7, 7.7, 7.7, 7.7, 7.7, 7.71, 7.7, 7.7, 7.71, 7.71, 7.7, 7.7, 7.7, 7.7,
2008 Jul 28
1
Interpolating a line and then summing there values for a diurnal oxygen curve (zoo object)
#I would like to interpolate a straight line between 06/08/06 04:16:00 - 06/08/06 20:31:00 with values and then sum them. This is an estimate of ecosystem #respiration and I will be using this in a larger context(48 days of these diurnal curves), but for right now I am just trying to figure out how to do it for this one #day example. I have some other code for Ecosystem (stream) Metabolism that
2010 Jun 28
1
Zoo series to a date time stamp that is regular
NOTE: I will provide data if necessary, but I didn't want clutter everyones mailbox All: I have a time series with level and temperature data for 11 sites for each of three bases. I will have to do this more than once is what I am saying here. OK, The time series are zoo objects with index values in chron format. The problem is that the date and times should be at even 15 min intervals,
2008 Jul 31
2
S 3 generic method consistency warning please help
I would like to include this in a package. The S3 methods on R CMD check says * checking S3 generic/method consistency ... WARNING window: function(x, ...) window.chron: function(data, day1, hour1, day2, hour2, ...) See section 'Generic functions and methods' of the 'Writing R Extensions' manual. I have looked and can not figure it out. This function is for convience. What
2013 May 01
3
Chron format question h:m not working
R 2.12.2 on Scientific Linux 6.4 #works chron(times.="15:00:00", format=c(times="h:m:s")) #doesn't work chron(times.="15:00", format=c(times="h:m")) From chron Manual: The times format can be any permutation of "h", "m", and "s" separated by any one non-special character. The default is "h:m:s". what am I
2008 Jul 25
1
plot zoo custom panel help
#the below code is the way that I would like the plot to look. I have tried to write a panel function: my.panel <- function(x, y, ..., pf = parent.frame()) { axis(side=1, at = seq(rng[1], rng[2], 1/12), labels = n, tcl = -0.3) } #but it does not work and I am at a loss and help would be appreciated. I will use this for multiple library(zoo) library(chron) #this is what I would like the
2008 Nov 29
1
chron and R 2.8
has anyone had problems with the upgrade to R 2.8 and chron date classes. I have a large zoo object that has a chron index, and it is taking 5x or so longer to do the same calculation as with 2.7 if it doesn't fail. I will provide anything necessary I am not entirely sure what ya'll would need if anything to try and reproduce the behavior. I am using the package StreamMetabolism. thanks
2010 Jun 29
3
formating chron date times for printing
the date were created with chron with this argument format=c(dates="Y/m/d", times="H:M:S")) so I have the dates being displayed as (10/06/22 12:00:00) I would like to have them displayed as "2010-06-22 12:00:00" or "%Y-%m-%d %H:%M:%S" and then I can convert these for mergeing with another data frame x <- (structure(c(14464, 14464.0104166667,
2008 Jun 26
1
Date Time Sequence
I would like a sequence of dates with a time step of 15 minutes starting: 1/1/2006 00:00:00 - 12/31/2006 23:45:00 function(x) { chron(sub(" .*", "", x), gsub(".* (.*)", "\\1:00", x)) } this is the piece of code I use to read in zoo objects for any help I would be grateful I have tried sequence and I can not seem to get it to work -- Let's not
2009 Aug 13
3
split number in a vector and then make a chron object out of it
These are date and times in the format YYYYMMDDhhmmss. I would like to take this column and make a chron object form them. I have tried a couple of the split family of functions but they need character input here is the data: date.time <- c(19851001001500, 19851001003000, 19851001004500, 19851001010000, 19851001011500, 19851001013000, 19851001014500, 19851001020000, 19851001021500,
2009 Aug 11
2
list indexing problem reading in files from a directory
I am running into a problem with allocating these files to a list as they are read in through a for loop. I know I am probably doing something wrong, but I can't figure out what. I know this is not reproducible. I am ending up with a data frame of the very last file to be read in. I know it is in the indexing, but I can't wrap my head around it. thanks for all of the help, Stephen