similar to: function similar to str_replace() in php.

Dear expeRt, I occasionally use help.search() function to find appropriate functions in R. Whenever committing help.search() after rerunning R, it takes so much time to find help (around 2 minutes). Is there any way to make it faster in help.search()? I think indexing help database is one of the solution, but i don't know how to do. Best, Dong-hyun Oh

Dear UseRs, I would like to know the way to find classes of each column of data.frame(). Thank you in advance. ========================================================= Dong-hyun Oh Center of Excellence for Science and Innovation Studies Royal Institute or Technology, Sweden e-mail: oh.dongh at gmail.com cel: +46 73 563 45 22

Dear UseRs, I would like to know the way to create a new column by naming it simultaneously. For example, in for() loop I want to create columns named as paste("test", i, sep = ""), as shown below. ---------------------------- dt <- data.frame(a = c(1, 2, 3), b = c(3, 2, 2), c = c(1, 3, 5)) for(i in 1:2){ dt$as.name(paste("test", i, sep = ""))

Dear useRs, I would like to know the way of deleting NA in list(). Following is a example. lt <- list(a = 1:3, b = NA, c = letters[1:3], d = NA) for(i in length(lt):1) { if(is.na(lt[[i]])) lt[[i]] <- NULL } How to simplify for() loop by using (l)apply family? Thank you in advance. ========================================================= Dong-hyun Oh Center of Excellence for

Hi, I'm trying to debug a function I wrote to calculate the cindex for a hierarchical tree. For this it is useful to compare my calculations with those in output from the clustindex function, in the cclust library. There's no way, however, to have the cindex value for a given output of the cclust function, as a NA value is always returned. This happens almost surely because the cindex in

Dear expeRts, I would simplify following code. --------------------------------------------- youtput <- function(x1, x2){ n <- length(x1) y <- vector(mode="numeric", length=n) for(i in 1:n){ if(x1[i] >=5 & x1[i] <= 10 & x2[i] >=5 & x2[i] <=10) y[i] <- 0.631 * x1[i]^0.55 * x2[i]^0.65 if(x1[i] >=10 & x1[i] <= 15 &

I''ve been searching for ages and not come up with anything on the internet. I was wondering if there is a Rails equiv. for the PHP function str_replace. For example; variable_for_new_string("value_to_repace", "string_to_replace_with", "string_to_perform_modification_to") Thanks in advance for any help. -- Posted via http://www.ruby-forum.com/.

Hola, Tengo una variable string que tiene muchos casos, pero necesito en cada uno de ellos reemplazar el último "==" por "=". asi está asi necesito si p1 == 1 o 2 == 1,3 si p1 == 1 o 2 = 1,3 si p1 == 3 o 4 == 1 si p1 == 3 o 4 = 1 si p1 == 5 == 0,7 si p1 == 5 = 0,7 si p1 == 5 = 0,7 si p1 == 5 = 0,7 si p1 == 6 == 0 si p1 == 6 = 0 si p1 == 7 == no aplica si p1 == 7 = no aplica

Mientras aparezca alguien que sepa guiarte bien, te muestro desde mi autodidactez por dónde encararía. Y lo que para mí fue un gran descubirmiento: El paquete RegExplain, [image: irudia.png] (==)([\d, \w]*=[\d, \w]*)$ Eso captura en dos grupos diferentes todo lo que está desde el final hasta el primer igual, más todo lo que sigue hasta en igual doble, que lo excluye y lo captura como otro grupo.

muchas gracias!! El mié, 15 mar 2023 a las 6:12, Carlos Ortega (<cof en qualityexcellence.es>) escribió: > Hola, > > Juntandolo todo se puede hacer así... > > #----------------------------- > cadena <- c( > 'si p1 == 1 o 2 == 1,3 si p1 == 1 o 2 = 1,3', > 'si p1 == 3 o 4 == 1 si p1 == 3 o 4 = 1', > 'si p1 == 5 == 0,7 si p1 == 5 =

hola ,muchas gracias! no conocía esa librería para los regex...respecto a la pregunta de Carlos, puedo tener más de un == dentro de la cadena, por ejemplo así: así está si p1 == 1 o 2 o p2 == 1 == 1,3 así necesito si p1 == 1 o 2 o p2 == 1 = 1,3 El lun, 13 mar 2023 a las 18:11, Juan Abasolo (<juan.abasolo en ehu.eus>) escribió: > Mientras aparezca alguien que sepa guiarte bien, te

Buenas, Una opción es partir la cadena usando el == como separador y luego recomponerla. > a <- "p1 == 1 o 2 o p2 == 1 == 1,3" > b <- strsplit(a, "==") > b <- b[[1]] > b [1] "p1 " " 1 o 2 o p2 " " 1 " " 1,3" > paste0(paste0(b[1:(length(b)-1)], collapse = '=='), '=', b[length(b)]) [1] "p1 ==

Muchas gracias!! Lo pruebo!!! El mar., 14 de marzo de 2023 04:55, Proyecto R-UCA <r-uca en uca.es> escribió: > Buenas, > > Una opción es partir la cadena usando el == como separador y luego > recomponerla. > > > a <- "p1 == 1 o 2 o p2 == 1 == 1,3" > > b <- strsplit(a, "==") > > b <- b[[1]] > > b > [1] "p1 "

hola! ,me sirve, pero el tema es que necesito crear tres variables nuevas con el resultado de strsplit....pero me genera una lista y no lo estoy pudiendo combinar con mutate de dplyr.... El mar, 14 mar 2023 a las 7:46, juan manuel dias (<juamadias en gmail.com>) escribió: > Muchas gracias!! Lo pruebo!!! > > El mar., 14 de marzo de 2023 04:55, Proyecto R-UCA <r-uca en uca.es>

Dear R-friends, the dataset I am using (data.it) is organized as follows partner stp btp reg hk 0.64 1 s ger 0.27 1 d tur 0.27 1 s rom 0.24 1 s-f por 0.24 1 s spa 0.23 1 s gre 0.22 1 d-f aus 0.17 1 d uk 0.16 1 s be 0.16 1 d arg 0.15 1 s usa 0.13 1 d-f fra 0.13 1 s neth

how to realize the following SQL command in R? select distinct A, B, count(C) from TABLE group by A, B ; quit; Best Regards --------------------------------- Sponsored Link Get a free Motorola Razr! Today Only! Choose Cingular, Sprint, Verizon, Alltel, or T-Mobile. [[alternative HTML version deleted]]

Hi, my data set is data.frame(id, yr, y, l, e, k). I would like to estimate Lee and Schmidts (1993, OUP) model in R. My colleague wrote SAS code as follows: ** procedures for creating dummy variables are omitted ** ** di# and dt# are dummy variables for industry and time ** data a2; merge a1 a2 a; by id yr; proc sysnlin maxit=100 outest=beta2; endogenous y; exogenous l e k

Hi, my data set is data.frame(id, yr, y, l, e, k). I would like to estimate Lee and Schmidts (1993, OUP) model in R. My colleague wrote SAS code as follows: ** procedures for creating dummy variables are omitted ** ** di# and dt# are dummy variables for industry and time ** data a2; merge a1 a2 a; by id yr; proc sysnlin maxit=100 outest=beta2; endogenous y; exogenous l e k

Dear useRs, I am trying to build my package (nonpareff) which deals with some models of data envelopment analysis. The building worked well, but checking complains when it tests examples. Zipped nonparaeff.Rcheck is attached. Following is the log. --------------------------------------------- arecibo:tmp arecibo$ R CMD build nonparaeff/ * checking for file 'nonparaeff/DESCRIPTION' ...

Dear useRs, I am trying to build my package (nonpareff) which deals with some models of data envelopment analysis. The building worked well, but checking complains when it tests examples. Zipped nonparaeff.Rcheck is attached. Following is the log. --------------------------------------------- arecibo:tmp arecibo$ R CMD build nonparaeff/ * checking for file 'nonparaeff/DESCRIPTION' ...