similar to: Concatenation and Evaluation

The problem: =========== Once a dendrogram has a branch with both a line type AND a color (which is a character color), the plot.dendrogram function will not plot and return an error. I say this is a bug because (I believe), we would like a dendrogram to be able to use character colors, while also allowing control over line types. This e-mail includes an example, and what I think a solution

Dear useRs, I am working on a project involving the clustering of a large dataset. I need to extract specific sub-clusters from the parent dendrogram for further analysis. The data is too large for the use of convenient tools such as identify.clust (it selects the specific group of interest on a graph), so alternatively I have saved the plot as a large image file so that it can be printed or

Dear R-users, I need some help concerning the plotting of dendrograms for hierarchical agglomerative clustering. The agglomeration niveau of each step should be displayed at the branches of the dendrogram. For this I need the x/y coordinates of the branch-agglomerations of the dendrogram. The y-values are known (the heights of the agglomeration), but how can I get the x-values? > mydata

hi all, i'm trying to plot a dendrogram with labeled leaves >rownames(f)<-v.names >v<-rowMeans(f, na.rm=T) >clust<-hclust(dist(v)) >dend<-as.dendrogram(clust,hang=0.05) >clust2<-cut(dend, h=0.5) >class(clust2$low[[1]]) >[1] "dendrogram" then >plot(clust2$low[[1]],horiz=TRUE,frame=F,type = "tr")) but my leaf labels do not fit

I am having trouble displaying a dendrogram of evolutionary relationships (a phylogram imported from the ape package) as the vertical component of a heatmap, but keeping the hierarchical clustering of the horizontal component. The relationships of the vertical component in the generated heatmap are not that of the dendrogram, although the ordering is. In more detail, I am attempting to generate

Dear list, I am trying to plot a radial dendrogram using the ape package, which requires my data to be of class 'phylo'. Currently I have my dendrogram stored as an object of class 'dendrogram' which was produced from an outside bit of C code, but was made into an object of class 'igraph.eigenc' and converted to a dendrogram using 'as.dendrogram()' from the igraph

Hi, I am a beginner for R. I had use gplots to generate a heatmap as following: >heatmap.2(matrix, col=topo.colors(75), dendrogram="column", Rowv=FALSE, trace="none", key=TRUE, keysize=0.8, density.info="none", cexRow=0.2, cexCol=0.6) It work well. It generate heatmap whith rcolumn clustering dendrogram and I can export a very nice graph. But I don not know how

Hello, My name is Rodrigo, I am using R program and I have a trouble. I am trying to do a dendrogram with genetics information. Let me explain... The Similarity Matrix was already did, and with this matrix I want to construct a dendrogram. So, the distance is done. I need to transform this matrix (that I have) in a dendrogram, I woud be very grateful if someone could help me. PS: I am sending

>>>>> Tal Galili <tal.galili at gmail.com> >>>>> on Mon, 18 May 2015 23:01:44 +0300 writes: > The problem: > =========== > Once a dendrogram has a branch with both a line type AND a color (which is > a character color), the plot.dendrogram function will not plot and return > an error. If the dendrogram has been messed up

Core developers, I couldn't find any simple way to send a vector of colors to apply to each terminal in plot.dendrogram() or plot.hclust()---I asked R-help about it a few weeks ago and didn't get any response---so I hacked that functionality into the plot.dendrgram code (see below for hacked function plus examples).... Is there any chance this functionality could be added to the

Hi all, I think I have some problems to use correctly the function dendrapply. Let suppose dend is a dendrogram object. I would likde to know the cardinal number of leaves depending of each node of the tree dend. It is right that the command attr(dend,"members") gives the total number of leaves, and attr(dend[[1]],"members") gives the number of leaves for the first left

Hello Aidan, Sorry for dropping this for a while. ? Thu, 2 Mar 2023 21:03:59 +0000 "Lakshman, Aidan H" <AHL27 at pitt.edu> ?????: > //after > curnode = eval(lang3(R_Bracket2Symbol, parent->node, DEND_IND), env); lang3() always constructs a new language object. If you do end up using eval(), it may make sense to move lang3() out of the loop and reuse the existing object

Dear R user, I am a biochemist/bioinformatician, at the moment working on protein clusterings by conformation similarity. I only started seriously working with R about a couple of months ago. I have been able so far to read my way through tutorials and set-up my hierarchical clusterings. My problem is that I cannot find a way to obtain information on the rooting of specific nodes, i.e. of

I have done a cluster analysis doing: 1-clusNorth <-hclust(dist(Artorious)^2, method="ward") 2-clusNorth$labels <-Artorious$Name ## to show the case names and not numbers 3-dend1 <- as.dendrogram(clusNorth) 4-plot(dend1) My Dendrogram is now showing the names of my cases in the dataframe on the x axis 1 OMNICELL INC COM 2 GETTY IMAGES INC

Dear all, I am using the heatmap representations of latticeExtra package and I would be interested to draw color side bars representing the groups of a factor of interest. From my understanding of : > help(dendrogramGrob) ... The 'add' argument can be used for additional annotation at the base of the dendrogram. It should be a list with one component for each row,

How would I set the "scales" property of a lattice levelplot, so that I can add specific annotations at specific positions? For example, I have a 200 x 1000 element levelplot. Along the y-axis (along the 1000-element axis) I would like to add annotations on the left side of the levelplot at elements 120, 300, 500, and 805, which represent clusters of interest. Currently I have

I am doing cluster analysis [hclust(Dist, method="average")] on data that potentially contains redundant objects. As expected, the inclusion of redundant objects affects the clustering result, i.e., the data a1, = a2, = a3, b, c, d, e1, = e2 is likely to cluster differently from the same data without the redundancy, i.e., a1, b, c, d, e1. This is apparent when the outcome is visualized

Hi all, I've been doing some investigation to see if it is possible to implement an hclust/dendrogram related requirement that I've been given. So far ?hclust and a lot of googling haven't provided the information I'm looking for (I've been using R sporadically for a year). The requirement I have is to: On a dendrogram plot, draw points at various merge locations, based on

im using plclust and want the labels to be different colors. i took a look at getS3method("plot","hclust") and saw a call to .Internal. i looked at the help on .Internal and dont know where to go next. any help appreciated! thanks, rafael

Hi I made heatmap of QTL based on Lod score. Where I have traits in columns and marker data (rows). I can not cluster both column and rows as I need the right order for marker data. Can someone suggest me better way of generating heatmaps especially the colour key I want to select to visualize the results which are more interesting to look at. > library(gplots) >