similar to: Getting Annual (Conditional) Averages

Hi, I'd like to make a time series at an annual frequency. > a<-xts(x=c(2,4,5), order.by=c("1991","1992","1993")) Error in xts(x = c(2, 4, 5), order.by = c("1991", "1992", "1993")) : order.by requires an appropriate time-based object > a<-xts(x=c(2,4,5), order.by=1991:1993) Error in xts(x = c(2, 4, 5), order.by =

Hello, I'm an R newbie. I've tried to search, but my search skills don't seem up to finding what I need. (Maybe I don't know the correct terms?) I need the standard errors and not the confidence intervals from an ARIMA fit. I can get fits: > coef(test) ar1 ma1 intercept time(TempVector) - 1900

Dear Sir/Madam, How to use getSymbols() to get annual data? For example, I need the annual stock price of APPLE from the year 2000 to 2016. How to write the command? I only know how to get the daily data. It is: getSymbols("AAPL",from="2000-01-01",to="2016-12-31") Thank you very much. Have a good week! Best regards, Yingrui Liu [[alternative HTML

hi everyone! hope you can help me here. i am a new R user. what i am trying to do is to find the maximum annual discharge from a daily record. i have a data.frame which includes date and the discharge. somewhat like this.. 10/1/1989 2410 10/2/1989 2460 10/3/1989 2890 ... ... ... 12/31/2005 5730 i have been browsing through the archives and fount out about the aggregate

Hi, I was wondering if there is a package I can use to convert my 22 annual observations to quarterly time series so that I will have 88 observations. Also, will there be any harm in doing so? will I loose any important data specific info? I want to run VARs in levels using TY method. Due to small sample, i will probably use a bootstrap method. Thanks! [[alternative HTML version deleted]]

Hello world, I am actually transferring a course in data management for students in biology, geography and agriculture from statistica to R - it works surprisingly well. If anyone is interested in my scratch/notepad (in German language), please see www.hydrology.uni-kiel.de/~schorsch/statistik/statistik_datenauswertung.pdf (pages 40-52) The dataset is:

dear kind helper, i would like to know how to find the annual maximun for a table that basicly looks like this: date time measurement1 measurement2 measurement3 mm/dd/yyyy hh:mm:ss m1 m2 m3 there are about 9000 measurements for each year, which makes it quite large... i already tried to subset all rows for a year, to find the maximum within these choosen rows, y <-

dear r-helpers i've got a table that in extracts looks like this: V1 V2 V3 V4 V5 1 01/01/1975 00:00:00 125.837 3.691 296.618 2 01/01/1975 01:00:00 124.799 3.679 281.307 3 01/01/1975 02:00:00 111.607 3.536 281.307 4 02/24/1976 11:00:00 21.602 2.555 93.893 5 02/24/1976 12:00:00 27.804 2.623 93.893 6 02/24/1976 13:00:00 26.105 2.604 114.716 7 10/18/1977

I have been using browsercam.com for CSS testing, but it is rather expensive. Recently, I discovered others using funadable.org to purchase a yearly membership as a group. A year long membership at browsercam.com costs $480.00. This gives us 25 user accounts. I am proposing that 25 people throw in $19.20 for their 1/25th share of the membership cost. Once I have raised $479.40 I will

Hello, Can anyone explain the following behaviour? To me it seems a bug, but maybe it is intentional. It seems that a diff on a zooreg class that is not _strictly_ regular only considers those entries that are 'deltat' apart. In the following, diff on the zooreg class only returns values where the index was one second apart. The example replicates by dev code, but I've also tested

Hi, I'm trying to plot the forecasts I generated using the Plot.Fore function of the BootPR package. But I got an error from zoo: My data: Time Series: Start = 1 End = 18 Frequency = 1 [1] 38731 38628 39117 92809 71984 31226 58613 72360 107956 92066 [11] 95208 99098 95848 120383 110717 105680 98469 101916 Script: y1<-ts(y1);

Hi all and thanks for your time in advance, I can't figure out why summary.lmrob complains when lmrob is used on a zooreg object. If the zooreg object is converted to vector before calling lmrob, no problems appear. Let me clarify this with an example: >library(robustbase) >library(zoo) >dad<-c(801.4625,527.2062,545.2250,608.2313,633.8875,575.9500,797.0500,706.4188,

Apologies for the limitations of the registration system. - No email is sent upon completion - If you get a page at the end that says you successfully registered, then you are good to go - There have been a few reported cases of the registration page hanging, if so try another browser such as Firefox. If you have questions mail me directly (dkipping at qualcomm.com). If the group wants, I can

I have date data as a numeric and hourly data in 0 to 2300 hours in a dataframe. d <- rep(20110101,24) h <- seq(from = 0, to = 2300, by = 100) df <- data.frame(LST_DATE = d, LST_TIME = h, data = rnorm(24, 0, 1)) S <- chron(dates. = as.character(df$LST_DATE), times. = paste(as.character(df$LST_TIME/100), ":0:0", sep = ""), format =

R-listers, I am using xts with a yearmon index, but am getting some inconsistent results with the date index when i drop observations (for example by using na.omit). The issue is illustrated in the example below. If I start with a monthly zooreg series starting in 2009, yearmon converts this to "Dec-2008". Not such a worry for my example, but strange. Having converted to xts, i drop

Dear R users, I am currently working in subsetting a zooreg() object using either window or subset. I have a solution but it may be a bit cumbersome when I start working with actual data. Your inputs would be greatly appreciated. Example: I have a zooreg() object that starts in 1997 and ends in 2001. This object contains daily data for the 4 years

I create a zooreg object that runs from Jan-1-2002 0:00 to Jun-1-2005 0:00... regts.start = ISOdatetime(2002, 1, 1, hour=0, min=0, sec=0, tz="") regts.end = ISOdatetime(2005, 6, 1, hour=0, min=0, sec=0, tz="") regts.zoo <- zooreg( NA, regts.start, regts.end, deltat=3600 ) Upon inspection: > regts.zoo[1:3] 2002-01-01 00:00:00 2002-01-01 01:00:00 2002-01-01 02:00:00

Hi all, can anyone please guide me how to create a sequence of months? Here I have tried following however couldn't get success > library(zoo) > seq(as.yearmon("2010-01-01"), as.yearmon("2010-03-01"), by="1 month") Error in del/by : non-numeric argument to binary operator What is the correct way to do that? Thanks for your time.

Dear all, please consider my following workbook: library(zoo) lis1 <- vector('list', length = 2) lis2 <- vector('list', length = 2) lis1[[1]] <- zooreg(rnorm(20), start = as.Date("2010-01-01"), frequency = 1) lis1[[2]] <- zooreg(rnorm(20), start = as.yearmon("2010-01-01"), frequency = 12) lis2[[1]] <- matrix(1:40, 20) lis2[[2]] <-

Dear R users, I would like to combine lattice plot (xyplot) and standard R plot (plot and plotCI) in an unique figure. I use the function "par()" to combine plot and plotCI and I use the function "print()" to combine xyplot. I tried to use these functions to combine xyplot and plotCI and plots but they do not work. Does anybody know how I can do this? Thank you very much in