similar to: how do i find the annual maximun within several years?

dear r-helpers i've got a table that in extracts looks like this: V1 V2 V3 V4 V5 1 01/01/1975 00:00:00 125.837 3.691 296.618 2 01/01/1975 01:00:00 124.799 3.679 281.307 3 01/01/1975 02:00:00 111.607 3.536 281.307 4 02/24/1976 11:00:00 21.602 2.555 93.893 5 02/24/1976 12:00:00 27.804 2.623 93.893 6 02/24/1976 13:00:00 26.105 2.604 114.716 7 10/18/1977

If this has already been answered, my apologies in advance I am relatively new to this aspect of [R]. it is a bit of a basic question. I have 4 columns of data (site, Date, measurement type, value) in a tab delimited text file. Site is a site where measurements were collected, Date is a date in DD/MM/YYYY format, measurement is a code for the type of measurement made, and value just the value

Hi Group, Create some example data. set.seed(1) wide_data <- data.frame( id=c(1:10), predictor1 = sample(c("a","b"),10,replace=TRUE), predictor2 = sample(c("a","b"),10,replace=TRUE), predictor3 = sample(c("a","b"),10,replace=TRUE), measurement1=rnorm(10), measurement2=rnorm(10)) head(wide_data) id

I'm using asteriskathome 2.5. I'm using 2 spa3000 for dialing-out. I configured a trunk for each one with maximun channels=1 and an outbound route that includes both trunks. When a second outgoing call is placed, Asterisk tries to place it in the same that is already in use resulting in a busy tone. ?What can be the problem? -- Alejandro Vargas

hi everyone! hope you can help me here. i am a new R user. what i am trying to do is to find the maximum annual discharge from a daily record. i have a data.frame which includes date and the discharge. somewhat like this.. 10/1/1989 2410 10/2/1989 2460 10/3/1989 2890 ... ... ... 12/31/2005 5730 i have been browsing through the archives and fount out about the aggregate

Hello, I have problems interpreting the results of a Friedman test. It seems to me that the p-value resulting from a Friedman test and with it the "significance" has to be interpreted in another way than the p-value resulting from e.g. ANOVA? Let me describe the problem with some detail: I'm testing a lot of different hypotheses in my observer study and only for some the premises

Dear Mr. Baddeley   I just graduated from a Masters in Applied Mathematics on Jun19th. My thesis was about spatial distribution /a nalysis of some trees in a part of  the Congo Basic Forest. In my thesis I used your spatial package in R, and today I'm doing a more deeper study about how we choise the r distance in Function F(). I would like to be able to understand about value of rmaxdefault

Hi, I am wondering how to draw biplot with the same scales on both plots? For example, if the two plots have much different scales, generally the two x-y's are scaled so that the two plots are sitting in the center automatically. How to disable this? Thanks -- Weiwei Shi, Ph.D Research Scientist GeneGO, Inc. "Did you always know?" "No, I did not. But I believed..."

Dear list, I need to buy a phone which could monitor the state of the maximun number of sip extensions about 200. It is for an attendant. I just saw Snom 370 with keypad and Linksys 962 but they do not let me to monitor 200 extensions states adding keypads. Do you know any kind of phone that let me do that? Which is the maximun number of extensions your phones can monitor and which models phones

Hopefully an easy one, how do I merge two or more SQL query results? Example: result1 = find_by_sql(x) result2 = find_by_sql(y) What is the best way to merge result1 and result2? I want to be able to reference the objects as if they were obtained via one query. Cheers, Dan

Dear Group, I am having a function that I am running in a loop that generated two results for each loop The result1 is a zoo object The result2 is a data frame Now I want to put both of them in a list or some structure ... that I can access or output to a file after the loop is done. For e.g. for (i in 1:20){ niceFunction(x[i],i) } niceFunction (x,i) { result1 = someOperations() #zoo

Hello I am trying to find an automated way of fitting a mixture of normal and log-normal distributions to data which is clearly bimodal. Here's a simulated example: x.1<-rnorm(6000, 2.4, 0.6)x.2<-rlnorm(10000, 1.3,0.1)X<-c(x.1, x.2) hist(X,100,freq=FALSE, ylim=c(0,1.5))lines(density(x.1), lty=2, lwd=2)lines(density(x.2), lty=2, lwd=2)lines(density(X), lty=4) Currently i am using

The US water year extends from 01 October yyyy-1 through 30 September yyyy and is referenced by the year starting on the included 01 January yyyy. I'd like to be able to find the annual means for the water year. To do so I've taken the input date-time, which is in the usual format "1991-10-07 10:35:00" changed it by: w$d<-as.POSIXct(w$date.time) Now I can add an

Thank you for your help in advance. I am trying to pull some data back from a web service library(httr) sample2 <- GET("https://elevation.mapzen.com/height?json={\"range\":false,\"shape\":[{\"lat\":40.7,\"lon\":-76.5}]}&api_key=mycode") result2 <- content(sample2) height <- result2$height[[1]] I would like to put by own latitude

On Sep 24, 2013, at 12:40 PM, Michael Spencer <bigcheesegs at gmail.com> wrote: > On Tue, Sep 24, 2013 at 12:33 PM, Rui Ueyama <ruiu at google.com> wrote: > Hi LLD developers, > > I'm about to make a change to invert the return value of Driver::parse() to return true on success. Currently it returns false on success. > > In many other functions, we return true

On Sep 24, 2013, at 4:07 PM, Sean Silva <chisophugis at gmail.com> wrote: > On Tue, Sep 24, 2013 at 4:17 PM, Nick Kledzik <kledzik at apple.com> wrote: > > On Sep 24, 2013, at 12:40 PM, Michael Spencer <bigcheesegs at gmail.com> wrote: > >> On Tue, Sep 24, 2013 at 12:33 PM, Rui Ueyama <ruiu at google.com> wrote: >> Hi LLD developers, >>

Dear List, Shouldn't result1 and result2 be equal in the following case? Note that log$RequestID is a factor. That is, is.factor(log$RequestID) yields TRUE. result1 <- tapply(log$Flag,factor(log$RequestID),sum) result2 <- tapply(log$Flag,log$RequestID,sum) Yet, when I summarize the output, I get the following: summary(result1) Min. 1st Qu. Median Mean 3rd Qu.

I've seen some questions regarding the output of multiple objects from a function, however the suggestions all end up suggesting the use of return(list(result1=result1, result2=result2 , result3=result3)). How can I return multiple objects that are 2 big to be added to a list? -- View this message in context:

Hello everyone, What is the most efficient & simpliest way to convert all components of a list to separate columns in a matrix? Is there an easy way to programmatically "pad" the length of the resulting shorter character vectors so that they can be easily combined into a data frame? I have the following code that stores the 2 compoents (of differing lengths) in the same character

On Tue, Sep 24, 2013 at 4:17 PM, Nick Kledzik <kledzik at apple.com> wrote: > > On Sep 24, 2013, at 12:40 PM, Michael Spencer <bigcheesegs at gmail.com> > wrote: > > On Tue, Sep 24, 2013 at 12:33 PM, Rui Ueyama <ruiu at google.com> wrote: > >> Hi LLD developers, >> >> I'm about to make a change to invert the return value of Driver::parse()