similar to: convert factor dataframe into numeric matrix

Hello. trying to do one of the simplest actions -read in data into R. I don't know why the FBfollowers column is being read as a factor and also if I use as.numeric on it, it looks really strange and actually complety alters the data. I am attaching the data set here called ddd.csv I used data=read.csv("ddd.csv",header=TRUE) fb=data$FBfollowers fb fb=as.numeric(fb) fb Thnxs in

I have two data frame A and B adn want to cross them. A has format as: a1 a2 a3 1 2 3 2 3 1 1 3 2 ... B: b1 b2 1 2 2 1 ... the combine result shall be something like a1 a2 a3 b1 b2 1 2 3 1 2 1 2 3 2 1 2 3 1 1 2 2 3 1 2 1 1 3 2 1 2 1 3 2 2 1 .... is there a function able of doing this instead of loops? Thanks, Sun

Dear all, I like to extract row names & column names from the named matrix...... like...... a<-matrix(1:6,2) ro<-c("aa","bb") co<-c("dd","ee","ff") dimnames(a)<-list(ro,co) a > dd ee ff aa 1 3 5 bb 2 4 6 from the above matrix "a" I like to extract rownames separately like

Hi all, I would like to know if it is posible by, someway, to get colMeans from a data.frame with numeric as well as character data, dispersed all over the object. Note that I would like to get colMeans neglecting character data. I am really in need of some function proceeding in that way… All the best Diogo André Alagador [[alternative HTML version deleted]]

Dear R-people, I have to compute C - -(pnorm(B)*dnorm(B)*B + dnorm(B)^2)/pnorm(B)^2 This expression seems to be converging to -1 if B approaches to -Inf (although I am unable to prove it). R has no problems until B equals around -28 or less, where both numerator and denominator go to 0 and you get NaN. A simple workaround I did was C <- ifelse(B > -25, -(pnorm(B)*dnorm(B)*B

Thank you all for your (fast) comments. Unfortunately I could not make the advise work: > mass [1] 800 800 800 800 800 800 800 800 800 800 800 800 800 800 800 800 800 800 910 910 910 910 910 910 910 [26] 910 910 910 910 910 910 910 910 910 910 910 910 910 910 1,020 1,020 1,020 1,020 1,020 1,020 1,020 1,020 1,020

I have got a dataframe containing measurement of aircraft noise like this: > Id <- c(1,4,5,2,3,6,4,1,2,5,6,3) > Noise <- c(88,94,97,98,92,56,103,102,87,95,92,97) > Height <- c(190, 150, 120, 115, 188, 104, 101, 189, 146, 111, 124, 126) > > df <- data.frame(Id, Noise, Height) Now I would like to split this in two new dataframes. The first one containing the rows

it must be terribly simple, can someone quickly help me? test <- data.frame(y=c(1:10), x=as.factor(c(rep("a",5),rep("b",5)))) how can i change the factor labels from "a" and "b" to for example "u" and "v"? i don't succeed with factor() thanks a lot ------------------------------------------------ Sebastian Leuzinger

Hi, all. I didn't find something similar to this problem in past list. I have a data frame (named restr) where some columns are factors, like you can see: > table(restr[,"p1"]) 0 1 2 3 4 5 0 26 1 0 1 0 > table(restr[,"p2"]) 0 1 2 3 4 5 6 0 13 11 1 2 1 0 When I use apply, the factor structure is missed: >

When I run a linear regression and include a variable in the regression with as.factor i.e. lm(y ~x +as.factor(x1) and i read the output as as.factor(x1)1.... as.factor(x1)2... etc. how do i interpret the estimate for each level? Is this simply to be regarded as a shift in the equation predicted by the intercept and independent variable x? jdr -- Justin Rapp 409 S. 22nd St. Apt. 1

Good Morning, Is it possible to use the R program for a CFA with dichotomous data? Thank you, Kathleen Kathleen Kemp, M.A. Doctoral Clinical Psychology Student, Concentration: Forensic Psychology Drexel University Philadelphia, PA 19104 kk354@drexel.edu [[alternative HTML version deleted]]

Hi all, I'm trying to load a csv file in which all the variables must be of type number.The object is a dataframe.When i load the file what i get is a dataframe in wich the variables are of type factor.How can I get variables of type number??? Thanks all

Hello, I have a data frame with a factor column, which uniquely identifies the observations in the data frame and it looks like this: sample1_condition1_place1 sample2_condition1_place1 sample3_condition1_place1 . . . sample3_condition3_place3 I want to turn it into three separate factor columns "sample", "condition" and "place". This is what I did so far: #

Hi. Is there a straightforward way to convert a character string containing comma-delimited numbers to a numeric vector? In my application, I use system(executable.string, intern=TRUE) which returns a string like "[0.E-38, 2.096751179214927596171268230, 3.678944959657480671183123052, 4.976528845643001020345216157, 6.072390165503099343887569007, 7.007958550337542210168866070,

How do a plot several columns of a matrix at once in a single plot versus a single x-variable? The default plot.matrix or plot.dataframe commands plot each column versus each other column in several sub-plots. I want to plot each column versus a single other vector (x) as several lines or points in one plot. I can do it by hand: get the range of all variables (i.e. columns of the matrix or

I wanted to test if there exists already a name (which is incidentally a substring of another name) in a dataframe. I did e.g.: > data(swiss) > names(swiss) [1] "Fertility" "Agriculture" "Examination" "Education" [5] "Catholic" "Infant.Mortality" > ! is.null(swiss$EduX) [1] FALSE > !

Hello All, I have had considerable bad luck with attempting the following with for loops. Here is the problem: # Suppose we have a data.frame with the following data, which can be considered a type of edgelist (for those with networks backgrounds): # # V1 V2 # 1 A # 1 A # 1 B # 2 A # 3 C # 3 A # 3 C # 3 B # # I want the output of the function to produce a matrix, such that #each factor of

Dear R experts,   I have a dataframe with 4 columns (variables). I want to redorder (or reposition) these columns on the basis of a value in its last row. e.g.   df1<-data.frame( v1= c(2,3,1,9,5), v2=c(8,5,12,4,11), v3=c(7,8,2,6,9), v4=c(1,4,6,3,6))    > df1    v1 v2 v3 v4 1  2  8  7  1 2  3  5  8  4 3  1 12  2  6 4  9  4  6  3 5  5 11  9  6 I wanto to get the order of df1 on the basis of

I have the following csv file: name,x,y,z category,delta,gamma,epsilon a,1,2,3 b,4,5,6 c,7,8,9 I'd like to create a numeric matrix of just the numbers in this csv dataset. I've tried the following program: sample.data <- read.csv("sample.csv") numerical.data <- as.matrix(sample.data[-1,-1]) However, print(numerical.data) returns what appears to be a matrix of

Hi all. I have a numerical function f(x), with x being a vector of generic size (say k=4), and I wanna take the numerically computed gradient, using deriv or numericDeriv (or something else). My difficulties here are that in deriv and numericDeric the function is passed as an expression, and one have to pass the list of variables involved as a char vector... So, it's a pure R programming