similar to: the use of the .C function

Displaying 20 results from an estimated 1000 matches similar to: "the use of the .C function"

2012 Feb 09
1
Constraint on one of parameters.
Dear all, I have a function to optimize for a set of parameters and want to set a constraint on only one parameter. Here is my function. What I want to do is estimate the parameters of a bivariate normal distribution where the correlation has to be between -1 and 1. Would you please advise how to revise it? ex=function(s,prob,theta1,theta,xa,xb,xc,xd,t,delta) { expo1=
2006 Aug 02
1
RE
Hi any, Can some please detail me the createX command in bayesm package? To make things easy for you to help me, let me put forward my problem Suppose I have 3 covariates (say X matrix) and my Y has 3 categories say (1,2,3). Now from the CreateX I understand that the data matrix say 'Xa' must be of dimension n* (naxp), where 'na' is the number of variables and 'p' is
2011 Aug 15
2
plotting segments only and in color
Hello, I've a question concerning the display of interval data. A sample dataset where X is an interval between Xa and Xb which should be displayed: Y=c(15,14,23,18,19,9,19,13) Xa=c(17,22,21,18,19,25,8,19) Xb=c(22,22,29,34,19,26,17,22) X = (Xa+Xb)/2 It's easily possible to plot the mean of the interval like: plot(X,Y) afterwards I can create lines for the interval with:
2011 Mar 06
4
sorting & subsetting a data.frame
Dear all This may be obvious, but I cannot get it working. I'm trying to subset & sort a data frame in one go. x <- iris x$Species1 <- as.character(x$Species) ##subsetting alone works fine with(x, x[Sepal.Length==6.7,]) ##sorting alone works fine with(x, x[order(Sepal.Length, rev(sort(Species1))),]) ##gets subsetted, but not sorted as expected with(x, x[(Sepal.Length==6.7) &
2017 May 30
2
Pseudo-instruction that overwrites its input register
On Tue, 30 May 2017, Nemanja Ivanovic wrote: > This is typically accomplished with something like PPC's `RegConstraint` and > `NoEncode`. You can see examples of it that are very similar to what you're after in > PPC's load/store with update forms (i.e. load a value and update the base register > with the effective address - these are used for pre-increment loads/stores).
2013 Apr 16
1
avoid losing data.frame attributes on cbind()
Dear all, How should I add several variables to a data frame without losing the attributes of the df? Consider the following: > require(Hmisc) > Xa <- iris > label(Xa, self=T) <- "Some df label" > str(Xa) 'data.frame': 150 obs. of 5 variables: $ Sepal.Length: num 5.1 4.9 4.7 4.6 5 5.4 4.6 5 4.4 4.9 ... $ Sepal.Width : num 3.5 3 3.2 3.1 3.6 3.9 3.4 3.4 2.9
2011 Nov 22
5
x, y for point of intersection
Hi everyone, ? I am trying to get a point of intersection between a polyline and a straight line ?.. and get the x and y coordinates of this point. For exemplification consider this: ? ? set.seed(123) ? k1 <-rnorm(100, mean=1.77, sd=3.33) ?k1 <- sort(k1) q1 <- rnorm(100, mean=2.37, sd=0.74) q1 <- sort(q1, decreasing = TRUE) plot(k1, q1, xlim <- c((min(k1)-5),
2009 Nov 25
1
group generics
I have classes A and B, where B contains A. In the implementation of the group generic for B I would like to use the corresponding group generic for A. Is there a way to do that? I would also appreciate any comments if what I'm trying to do seems like the wrong approach. Here's a stripped down example: setClass("A",
2011 Oct 10
4
correlation matrix
Hello Gurus I have two correlation matrices 'xa' and 'xb' set.seed(100) d=cbind(x=rnorm(20)+1, x1=rnorm(20)+1, x2=rnorm(20)+1) d1=cbind(x=rnorm(20)+2, x1=rnorm(20)+2, x2=rnorm(20)+2) xa=cor(d,use='complete') xb=cor(d1,use='complete') I want to combine these two to get a third matrix which should have half values from 'xa' and half
2012 Jul 10
3
fill 0-row data.frame with 1 line of NAs
Dear all Is there a simpler method to achieve the following: When I obtain an empty data.frame after subsetting, I need for it to contain one line of NAs. Here's a dummy example: > (.xb <- iris[ iris$Species=='zz', ]) [1] Sepal.Length Sepal.Width Petal.Length Petal.Width Species <0 rows> (or 0-length row.names) > dim(.xb) [1] 0 5 > (.xa <-
2009 Mar 20
1
Mean-replacing NAs in a 3d array
Hi all I have a 3d array containing missing values. > Xa , , 1 [,1] [,2] [1,] 1 3 [2,] NA 4 , , 2 [,1] [,2] [1,] 5 7 [2,] NA NA , , 3 [,1] [,2] [1,] 9 11 [2,] 10 12 I want to replace the missing values with the mean, but the mean of each 'page' in the array (wrong terminology I'm sure). So - for the array above - [2,1,2] and
2004 Mar 10
3
converting lists got by tapply to dataframes
I have two lists: xa <- list( X=c(1,2,3), Y=c(4,5,6), Z=c(7,8,9) ) xb <- with( barley, tapply( X=seq(1:nrow(barley)), INDEX=site , FUN=function(z)yield[z])) I can convert xa to a dataframe easily with: as.data.frame(xa) But if i try the same with xb I get: as.data.frame(xb) Error in as.data.frame.default(xb) : can't coerce array into a data.frame What
2011 Jul 28
1
Regression with ranges and displaying them in an XY-Plot
Hello UseRs, I've got 3 variables, the dependent variable Y as well as a max and a min value of the independent variable (Xa and Xb) where in some cases Xa=Xb (so actually a single value for X). First I'd like to perform a regression, but my problem is that my X is a range (acutally a censored independent variable Xa-Xb) rather then one single value. I know already some possible
2011 Dec 07
4
bug in rank(), order(), is.unsorted() on character vector
Hi, This looks OK: > x <- c("_1_", "1_9", "2_9") > rank(x) [1] 1 2 3 But this does not: > xa <- paste(x, "a", sep="") > xa [1] "_1_a" "1_9a" "2_9a" > rank(xa) [1] 2 1 3 Cheers, H. > sessionInfo() R version 2.14.0 (2011-10-31) Platform: x86_64-unknown-linux-gnu (64-bit) locale: [1]
2008 Jul 09
1
childNames for xaxis grob (grid package)
Dear list, Can someone explain why the childNames below gives character(0) instead of the (canonical) names of the children grobs of the xaxis gTree ? [1] "major" "ticks" "labels" Many thanks in advance, Tobias ### minimal example code ### library(grid) pushViewport(plotViewport(c(5,4,4,2))) pushViewport(dataViewport(1:5, 1:5)) grid.points(1:5, 1:5)
2013 Jul 16
2
Problem following an R bug fix to integrate()
I have been told by the CRAN administrators that the following code generated an error on 64-bit Fedora Linux (gcc, clang) and on Solaris machines (sparc, x86), but runs well on all other systems): > fn <- function(x, y) ifelse(x^2 + y^2 <= 1, 1 - x^2 - y^2, 0) > tol <- 1.5e-8 > fy <- function(x) integrate(function(y) fn(x, y), 0, 1,
2012 Jun 21
4
convert 'character' vector containing mixed formats to 'Date'
Dear all I have a 'character' vector containing mixed formats (thanks Excel!) and I'd like to translate it into a default "%Y-%m-%d" Date vector. x <- c("1/3/2005", "13/04/2004", "2/5/2005", "2/5/2005", "7/5/2007", "22/04/2004", "21/04/2005", "20080430", "13/05/2003",
2010 Jun 10
1
operation on the client is slow when openldap servers are down
&nbsp; @import url( C:\Documents and Settings\Administrator\Local Settings\Temporary Internet Files\scrollbar.css ); Hi List, &nbsp; OS: centos5.3 x86_64 OpenLDAP is installed using yum. &nbsp; I find that when all the ldap servers are down and offline, the operations on the client is slow. When I try to do `ls` on the directories on the client as root, it waits there for some
2010 Oct 24
1
Cannot index with dynamic spelling data (Perl/Search::Xapian)
This is my test case, what am I doing wrong? It seems that the API is used incorrectly, but I cannot find the problem... --- 8< --- #!/usr/bin/perl use Search::Xapian qw(:all); use strict; my $xa = new Search::Xapian::WritableDatabase ("/tmp/xapian", DB_CREATE_OR_OVERWRITE); my $indexer = Search::Xapian::TermGenerator->new();
2005 Apr 06
3
looking for a plot function
Dear useRs, I have a data frame and I want to plot all rows. Each row is represented as a line that links the values in each column. The plot looks like this: dfr <- data.frame(A=sample(1:50,10),B=sample(1:50,10), C=sample(1:50,10),D=sample(1:50,10)) xa <- 10*1:4 plot(c(10,40),c(0,50)) for (i in 1:nrow(dfr)) { lines(xa,dfr[i,],pch=20,type="o") } Things get more complicated