similar to: MLE Function

Hi, I have written out the log-likelihood function to fit some data I have (called ONES20) to the non-central chi-squared distribution. >library(stats4) >ll<-function(lambda,k){x<-ONES20; 25573*0.5*lambda-25573*log(2)-sum(-x/2)-log((x/lambda)^(0.25*k-0.5))-log(besselI(sqrt(lambda*x),0.5*k-1,expon.scaled=FALSE))} > est<-mle(minuslog=ll,start=list(lambda=0.05,k=0.006))

I have a data with 236 observations. After plotting the histogram, I found that it looks like non-central t distribution. I would like to get MLE for mu and df. I found an example to find MLE for gamma distribution from "fitting distributions with R": library(stats4) ## loading package stats4 ll<-function(lambda,alfa) {n<-200 x<-x.gam

my problem actually arised with fitting the data to the weibulldistribution, where it is hard to see, if the proposed parameterestimates make sense. data1:2743;4678;21427;6194;10286;1505;12811;2161;6853;2625;14542;694;11491; ?? ?? ?? ?? ?? 14924;28640;17097;2136;5308;3477;91301;11488;3860;64114;14334 how am I supposed to know what starting values i have to take? i get different

I am trying to fit the chi-squared distribution to a set of data using the fitdistr function found in the MASS4 library, the data set is called ONES3, I have loaded it using the command ONES3<-read.table("ONES3.pdf",header=TRUE,na="NA") I print out the dataset ONES3 to the screen to make sure it has loaded Then I try to fit this data using the command

Hi, Actually I am facing a similar problem. I would like to fit both an ordinary (symmetric) and a non-central t distribution to my (one-dimensional) data (quite some values.. > 1 mio.). For the symmetric one, fitdistr or funInfoFun (using fitdistr) from the qAnalyst package should do the job, and for the non-central one.. am I right to use gamlss(x ~ 1, family=GT()) ? Anyway, I am a little

Dear, I'm starting on R language. I would like some help to implement a MLE function. I wish to obtain the variables values (alpha12, w_g12, w_u12) that maximize the function LL = Y*ln(alpha12 + g*w_g12 + u*w_u12). Following the code: rm(list=ls()) ls() library(stats4) Model = function(alpha12,w_g12,w_u12) { Y = 1 u = 0.5 g = -1 Y*log(alpha12 + g*w_g12 + u*w_u12) } res =

Hi, How can we set the environment for the minuslog function in mle()? The call in this code fails because the "ll" function cannot find the object 'y'. Modifying from the example in ?mle: library(stats4) ll <- function(ymax=15, xhalf=6) { -sum(stats::dpois(y, lambda=ymax/(1+x/xhalf), log=TRUE)) } fit.mle <- function(FUN, x, y) { loglik.fun <- match.fun(FUN)

1) The Pareto P(alfa) distribution is defined by its density f(x|alfa) =alfa*X^(-alfa-1) over (1 to infinity). Show that it can be generated as the -1/alfa power of a uniforme variate. Plot the histogram and the density. 2) The Poisson distribution P(lambda) is connected to the exponential distribution through the Poisson process in that it can be simulated by generating exponential random

Dear R users, I have to call fortran program from within R (R 2.8.1 on ubuntu 8.10 machine). Suppose I have a fortran code like this (this is only a toy model, my working model is far more complex, but input/output is similar) DOUBLE PRECISION FUNCTION model(times, alfa, beta) DOUBLE PRECISION alfa, beta, times model=beta*sin(times)+alfa*cos(times) END FUNCTION which

When I try to push my application to ''GitHub'' using ''Git'', I get the following: $ git push origin master Enter passphrase for key ''/c/Users/Medicine - SWEng/.ssh/id_rsa'': ERROR: Repository not found. fatal: The remote end hung up unexpectedly **EDIT:** Output of running `git remote -v`: $ git remote -v heroku

> On Jul 30, 2017, at 8:25 AM, Uwe Ligges <ligges at statistik.tu-dortmund.de> wrote: > > > > On 30.07.2017 17:22, Milan Cisty wrote: >> Dear all, >> I appreciate suggestions for following problem. I wrote to RStudio: >> plot(c(1,20),c(1,20), xlab = expression(paste(alfa))) >> or the same happen when I wrote: >> plot(c(1,20),c(1,20), xlab =

Hello everybody! I keep on trying to make my samba installation to work. I have tried a couple threads before but I have not been able to pinpoint the problem. So, yesterday I made a second last attempt to solve the problem before my boss forces me to install Windows2003 since it works out of the box. The scenario is that I'm trying to use Samba (Suse 10) as a fileserver that

Hi I have the following formula (I hope it is clear - if no, I can try to do better the next time) h(x, a, b) = integral(0 to pi/2) ( ( integral(D/sin(alpha) to Inf) ( ( f(x, a, b) ) dx ) dalpha ) and I want to do an mle with it. I know how to use mle() and I also know about integrate(). My problem is to give the parameter values a and b to the

Dear all, I appreciate suggestions for following problem. I wrote to RStudio: plot(c(1,20),c(1,20), xlab = expression(paste(alfa))) or the same happen when I wrote: plot(c(1,20),c(1,20), xlab = expression(alfa)) what happen is, that description under x label is exactly "alpha", not greek letter alfa (?). Please where should I search problem, or what information to sent to list for

hello my data is data2:2743 4678 21427 6194 10286 1505 12811 2161 6853 2625 14542 694 11491 14924 28640 17097 2136 5308 3477 91301 11488 3860 64114 14334 by calculating shape<-(mean(data2))^2/var(data2) scale<-var(data2)/mean(data2) i get the idea what the parameters of the gammadistribution would be. but if i try using the method mle() i get stock and i don't know, how to

Hi all, I am trying to filter the element of a df that start with "TF", like this: alfa = c(123221,"TF13124",41243,"TF1234",32414,"TF13124","TF14333",2134123,"TF1234") beta =

Full_Name: Ximing Zhao Version: R 1.7.1 OS: MacOs X Submission from: (NULL) (64.136.27.51) When I used function plot in R 1.7.1, I found two bugs. My whole function is this: ***************** drawexp<-function(X,x,c,b){ exp<-function28(X,x,c,b) if(max(exp)>=max(dexp(x,rate=1))){ plot(x,exp, type="l",main= paste("Exponential ,n=",length(X),"

Hello I?m need fitt growth curve with data length-age. I want to evaluate which is the function that best predicts my data, to do so I compare the Akaikes of different models. I'm now need to evaluate if changing the initial values changes the parameters and which do not allow to estimate the model. To do this I use the function nls(); and I randomize the initial values (real positive number).

On 30.07.2017 17:22, Milan Cisty wrote: > Dear all, > I appreciate suggestions for following problem. I wrote to RStudio: > plot(c(1,20),c(1,20), xlab = expression(paste(alfa))) > or the same happen when I wrote: > plot(c(1,20),c(1,20), xlab = expression(alfa)) Write "alpha", not "alfa". Best, Uwe Ligges > what happen is, that description under x label is

Is it possible, that dovecot-lmtp, has in inserted "Received:" header something about its version ie. instead: --8<---------------cut here---------------start------------->8--- Received: from alfa.kjonca by alfa.kjonca with LMTP id n1O7D5Q3v1toSQAApvcrCQ (envelope-from <envelope at from>) for <kjonca at localhost>; Thu, 11 Oct 2018 13:44:20 +0200