similar to: Losing factor levels when moving variables from one context to another

Hi everyone, I'm a new R user (if this is a really basic question, please do excuse me...) and I'm having some questions regarding a deciles problem. I have a variable which I need to categorize according to its deciles (X). However, this categorization should be made into another variable (call it NewVar). Ex. for the quartiles case (just for the sake of exposition, since I need

Hello, If I have two variables that are factors or characters and I want to create a new variable that is the combination of both what function can I use to accomplish this? Ex. Var1 Var2 SA100055113 19851113 And I want NewVar SA10005511319851113 Thanks in advance. Cameron Guenther, Ph.D. Associate Research Scientist FWC/FWRI, Marine Fisheries Research 100 8th Avenue S.E. St.

This is an example from chapter 11 of the 6th edition of Devore's engineering statistics text. It happens to be a balanced data set in two factors but the calculations will also work for unbalanced data. I create a factor called 'cell' from the text representation of the Variety level and the Density level using '/' as the separator character. The coefficients for the linear

I would like to add an extension to the current name of a variable to create a new variable that is its sqrt transform. Each piece of the equation below works independently, but the left side definition fails on run. I also tried creating the variable name first, but ended up with an object that toString() did not fix. Better ideas? Example 1

Hello list, how can I go from CALLINGout to just CALLING ? I've tried : exten => s,n,Set(newVAR=${CUT(CALLINGout,,3)}) or exten => s,n,Set(newVAR=$[CUT(CALLINGout,,3)]) But no result : [Jan 4 11:10:12] -- Executing [s at from-S:34] NoOp("SIP/s2-0000003b", "newVAR=") in new stack Asterisk 1.6.10 here. Kind regards, Jonas. -------------- next part

I need an object created in a user defined function to be accessible to another user defined function. I am fairly certain the object is correctly created as it prints when I use the return() function, however the 2nd function seems unable to use it. I am guessing objects created in functions are not globally accessible, is this correct? What is an appropriate way to pass the object to the

I have a large 3 dimensional array of size (243,246,768) The first dimension is Rows, second is columns and the third is Time. So for each row and column, I want to calculate the mean of time steps 1:8, 2:9, 3:10 and so on and assign the values to a new array. For this I am using the following script. for(i in 1:243) { for(j in 1:246) { for(k in 1:768) { newVar[i,j,k] <- mean(

I'm trying to fix a problem with the GrandStream Budgetone 102. I've been reading the source code, mailing lists and other resources. Here's the scenario and the approach I have been pursuing. I'm having some problems with the AGI calls and I hope someone can give me some clarification. PSTN <---> T1,PRI * <---> Grandstream BT 102 (12)

I need to look through a dataset with two factor variables, and depending on certain criteria, create a new variable containing the data from one of those other variables. The problem is, R keeps making my new variable an integer and saving the data as a 1 or 2 (I believe the levels of the factor). I've tried using as.factor in the IF output statement, but that doesn't seem to work. Any

Dear all, I have a question with respect to counting process formulation of the coxph(survival) model. I have two groups of observations for which I have partitioned each observation into two distinct time intervals, namely, entry day till day 13, and day 13 till death or censorship day (of course the latter only for the observations that survived the first 13 day interval), and added a

Hi All, I have some data where I am doing fairly simple calculations, nothing more than adding, subtracting, multiplying and dividing. I’m running into a problem when I divide one variable by another and when they’re both 0 I get NaN. I realize that if you divide a non-zero by 0 then you get Inf, which is, of course, correct. But in my case I never get Inf, just NaN because of the structure

I am new to R, but have been using SAS for years. In this transition period, I am finding myself pulling my hair out to do some of the simplest things. An example of this is that I need to generate a new variable based on the outcome of several existing variables in a data row. In other words, if the variable in all three existing columns are "Yes", then then the new variable should

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Dear R listers, I am trying to create a new variable that uniquely identifies groups of observations in a dataset. So far I couldn't figure out how to do this in R. In Stata I would simply type: egen newvar = group(dim1, dim2, dim3) Please, find below a quick example to show what I am dealing with: I have a dataset with 4 variables: var <- runif(50) ## a variable that I want to group

I have noticed that after I ran a batch script multiple times I get multiple copies of a package's name when I call search(). Is this a problem? > search() [1] ".GlobalEnv" "DF" "DF" [4] "DF" "DF" "DF" multiple copies here ... [13] "DF" "DF"

Hi, I am trying to do a kruskal wallis test on two lists, fVisited and cSN: fVisited[[1]] [1] 0.17097623 0.30376141 0.17577266 0.14951855 0.03959753 0.08096217 0.05744888 0.02196257.... .... cSN[[1]] [1] 0.08557303 0.36477791 0.19601252 0.12981040 0.05351320 0.10385542 0.03539577 0.03106175.... So if I just want to do a test on just one of the entries this is simple enough:

Hello all I have a big data frame and I regularly want to break it down into subsets, calculate some new data, and add it back to the data frame. At the moment my technique seems a bit ugly and embarrassing. Something like: result <- by(mydata, mydata$some_factor, function (x) { # do something to create a vector v with length(v) == nrow(x) return(v) }) # now result has a big list, argh...

Hello Gurus, I am still new to R. Here is my issue. I was trying to add column to data frame that was populated by read.spss(). When I used cbind to add a new variable(column). library(foreign) mydf<-read.spss(file="C:/myspss.sav",use.value.labels=FALSE, to.data.frame=TRUE,use.missings=FALSE) attr(mydf,"variable.labels") ## it gives you all the labels

I'm wondering if there is a simple way to assign a quantile to a vector in a data frame, much like one could in Stata using centile. Let's say I want 100 slices in my assignation. I can easily see what the limits of each slice by using quantile: quantile(my.df$my.var, probs=seq(0, 1, 0.01)) But how do I assign the appropriate value to each row/record in my data frame? Clearly the

Hi people! I want to save the 1st letter from the ${EXTEN} variable. I don't want to trim it, I want to RESAVE it into a new variable. Let us assume the ${EXTEN} contains: 0698332977 then I'd love to get the 0 I would thank you for all advises. Tamer