similar to: How to name variables in a single plot

Dear R core team I've a proprosal to improve the function interaction.plot. It should be allowed to use type = "b". This can be done by changing the function's header from function( , type = c("l", "p"), ) to function( , type = c("l", "p", "b"), ) Then it works. This type = "b" is useful, if

Dear R Users, My question is overall and not necessarily related to R. Suppose we face to a situation in which MSE( Mean Squared Error) shows desired results but Bias shows undesired ones, Or in advers. How can we evaluate the results. And suppose, Both MSE and Bias are important for us. The ecact question is that, whether there is any combined measure of two above metrics. Thank you so

hi all, I wish to draw on the same graphic device 3 functions. But i don't want them to be on different graph, i want to compare them on the same I don't need mfrow or mfcol, I need something else... 1 graph on 1 device inside this graph 3 ploted function. I saw something unsing data.frame, but i think it's overkill, and something less complicated must exist, if not why? why not

Dear David, Dear Friends, After any running svm I receive different results of Error estimation of 'svm' using 10-fold cross validation. What is the reason ? It is caused by the algorithm, libsvm , e1071 or something els? Which value can be optimal one ? How much run can reach to the optimality.And finally, what is difference between Error estimation of svm using 10-fold cross validation

I'm slowly moving my statistical analysis from Matlab to R, and find myself missing two features: a) How do I mimic Matlab's 'hold on'? (I want to show several plots together, when I type two plots one after the other the second overwrites the first) b) How do I mimic Matlab's 'axis'? (after drawing my plots I want to zoom on specific parts- for example, x=0:5,

Dear R Users, Suppose we are interested for generating a new vector ( x ) from a current vector (y) of length 1000 so that x includes the sum of every 5 values in y respectively from the first to the end of length y. The same length of y for x is desired, so that other 4 positions (indices) in x are filled out with NA. For generating such a new vector, I have no idea. I tried in some

Dear R Users, For running wavelet functions using dwt( ), modwt( ), and mra( ), a wavelet filter algorithm is applied. For all these functions, default is "la8" and other possibility is "haar". In related documents, another possibilities like as symlet and coiflet ... are not cited. Besides "la8" and "haar", which wavelet filters can be used? Thank

Hi R Users, I don't know how much is difficult my problem and even it is possible to solve in R or not. Given a vector with 2000 observations. I want to creat a new vector from that vector so that new vector be the sum of every 5 observations sequently. That is , each new observation is sum of every 5 sequent observations, from the first observation of previous vector to the end. So

Hello, All: ????? Roughly a decade ago, I added "matplot.Date" and "matplot.POSIXct" to the "fda" package, so we could get reasonable labeling of the horizontal axis when "x" was class "Date" or "POSIXct".? I also added a local version of "matplot.default" that just changes the defaults for "xlab" and

On 2020-01-28 05:13, Martin Maechler wrote: >>>>>> Spencer Graves >>>>>> on Mon, 27 Jan 2020 23:02:28 -0600 writes: <snip> > > Still, as Abby mentioned, turning a simple function into the > default method of an S3 generic is easy to do, but comes with a > bit of cost, not just S3 dispatch which typically is negligable in > graphics,

????? Thanks for the reply. On 2020-01-27 19:56, Abby Spurdle wrote: > Maybe I'm missing something really obvious here, but I was unable to > create a matrix out of POSIXct object(s). > Perhaps that deserves a separate discussion...? ????? Can you provide an example? ????? The standard matplot application that concerns me is with matplot(x, y, ...) where x has class Date or

Hi, Matplot works with x being Date class but not POSIXt. Here is the example with R version 2.5.0 Under development (unstable) (2006-12-06 r40129) Example: x <- Sys.Date() - c(1:10) y <- cbind(1:10, 10:1) class(x) ## [1] "Date" matplot(x, y) x <- strptime(as.character(x), format="%Y-%m-%d") ## [1] "POSIXt" "POSIXlt" matplot(x, y) Error in

Hi list, I know that points involving NAs are not plotted in 'matplot', but when I plot them as lines, I still want the lines to connect all the points (i.e. not broken where there are NAs).? Please see the example below.? How can I achieve this in 'matplot'?? If I can't, any good alternatives so I don't have to use 'plot' + 'lines' and loop through all the

Hi dear R users, Is it basically correct that a problem is ( linearly on nonlinearly ) modeled so that the slack variable is bounded by an upper bound ? If so, how it can be handled and coded practically ? for example: x1+ x2 =< b so ----> x1 + x2 + s=b s=b- x1 - x2 b- x1 - x2 =< upper value But algorithms can not calculate b- x1 - x2 , because

Hello R users -- I am using matplot to prepare graphs and cannot find a way to use (for example) box(lwd=3) within the matplot command and instead have been setting the box line width after drawing the graph, by using box(lwd = 3). Looking over the ?par options and the matplot() help I do not see a way to set box width within matplot. Is there such an option? Thanks for suggestions,

Dear R Users, Suppose we want to creat a new vector ( x ) from a current vector (y) of length 1000. The current vector y includes negative, zero and positive values. We want our new vector x includes the negative values in y, otherwise NA with the same length as y. For this, we have x=y[y<0] . Now x includes a subset of y with shorter length than y. With x=match(y,x) we would

Hi, I apologise in advance for the na?ve question. I have large matrices that I want to plot. I currently use color2D.matplot. However, these matrices contain many values of no interest (i.e. where there is no data, the figure -999 is automatically displayed). Is there any way of removing these from the matrices to be plotted by matplot? An obvious possibility is setting them all to 0, but that

Hi, I finally came up with a nice colored matrixplot, using the color2D.matplot function of the plotrix package. But I can't assign xtics and ytics to this plot. I made sure that the matrix has correct colnames() and rownames(). Here's what I do: a=matrix(1:16, 4, 4) colnames(a) <- c("X1", "X2", "X3", X4) rownames(a) <- c("Y1",

I raised this question quite some time ago but it quitly went down the river. I'll give it a second try (before keeping my modified version of matplot for ever...): matplot supports vectors (and/or character strings) for a number of arguments namely `type', `lty', `lwd', `pch', `col', `cex'. all of them act consistently in such a way that the first entries are used

Full_Name: Christophe Genolini Version: 2.8.1, but also 2.9 OS: Windows XP Submission from: (NULL) (82.225.59.146) I am using matplot with the option lend="butt", but only the first line (the black) is printed correctly : > matplot(matrix(1:9,3),type="c",lwd=10,lty=1,lend="butt") Gabor Grothendieck find the problem in matplot code: the ... is passed to plot