similar to: Error when using polr() in MASS

Displaying 20 results from an estimated 400 matches similar to: "Error when using polr() in MASS"

2008 Jun 11
1
Problem when combining dotplot() and textplot() using grid
Hi everyone. I want to solve the following problem. I have a data.frame and I create a dotplot using lattice. Then I want to use the grid-package to create a combined graphic which contains the dotplot as well as a textplot() (using package gplots) of the data.frame next to the dotplot. Example code: library(lattice) library(grid) library(gplots) xx <- data.frame(f=factor(rep(1:5, each=5)),
2004 Jun 22
3
[LLVMdev] Linearscan allocator bug?
Folks, I'm running into something which looks like a bug in linearscan allocator. Of course I can't be 100% sure it's not some unobvious mistake on my part, so I'd like to hear your opinion. First, I attach two files -- LLVM asm and the asm for my target. The problem with assembler is: on line 171 it uses register gr2, which is copied from gr6 above, on line 161. The only
2003 May 22
7
extract half a matrix
Dear all, I'm new to matrix operations in R. I couln't find a solution to the following problem among earlier help mails or in An introd to R, I guess because the question is really basic. I want to extract all above the diagonal, i.e. from 1 2 3 4 1 0 26 49 49 2 26 0 44 40 3 49 44 0 21 4 49 40 21 0 I want 26 49 44 49 40 21 Thanks in advance! Sincerely, Tord
2003 Dec 07
2
par(las = 1) not possible in polymap(), library(splancs)?
Dear all, I want my PhD thesis which I hand in tomorrow to look even nicer: Does polymap in the splancs library not allow horizontal plotting of y-labels? I have tried polymap(studyarea, xlab = "x (m)", ylab = "y (m)", las = 1) but it doesn't change the labels? Mayby some function in library(spatstat) support las? Thanks! Sincerely, Tord
2003 Nov 23
4
remove 0 rows from a data frame
Dear all, As part of a larger function, I am randomly removing rows from a data frame. The number of removed rows is determmined by a Poisson distribution with a low mean. Sometimes, the random number is 0, and that's when the problem starts: My data frame: > temp occ x y dbh age 801 0 2977.196 3090.225 6 36.0 802 0 2951.892 3083.769 8 40.6 803 0 2919.111
2003 Feb 05
1
simplify a data frame
Dear all, For the past three hours I have tried simplify a data frame. I would be really happy if someone could help solving this, I'm sure simple, problem. I want to "aggregate" the data frame: ObjektID BalteNummer Baltessegment S.13 S.13.1 S.13.1.2 S.13 S.13.1 S.13.1.3 S.13 S.13.2 S.13.2.1 S.13 S.13.2 S.13.2.2 S.13 S.13.2 S.13.2.3 S.13 S.13.3 S.13.3.6 S.13 S.13.3 S.13.3.7
2003 Jul 21
2
bold AND italic as font in text()
Dear all, Is it possible to somshow plot text as italic AND bold. I tried font=c(2,3) in text(), but it doesn't work. It seems like the latter value is used. Thanks in advance! Sincerely, Tord ----------------------------------------------------------------------- Tord Sn?ll Avd. f v?xtekologi, Evolutionsbiologiskt centrum, Uppsala universitet Dept. of Plant Ecology, Evolutionary Biology
2002 Jan 04
4
line up a matrix
Dear all, I try to rearrange my ref. database (now in Excel!! :( ) for importing it into a reference manager program (RIS format). My file basically look like this [3,4]-matrix: rbind(c("a", "b", "c", "d"), c("e", "f", "g", "h"), c("i", "j", "k", "l")) [,1] [,2] [,3]
2003 Oct 08
2
binomial glm warnings revisited
Dear all, Last autumn there was some discussion on the list of the warning Warning message: fitted probabilities numerically 0 or 1 occurred in: (if (is.empty.model(mt)) glm.fit.null else glm.fit)(x = X, y = Y, when fitting binomial GLMs with many 0 and few 1. Parts of replies: "You should be able to tell which coefficients are infinite -- the coefficients and their standard errors will
2003 Oct 20
4
warning from return() in 1.8 but not in 1.7.0 (PR#4687)
To whom it may concern, I get the following message when I run my function: Warning message: multi-argument returns are deprecated in: return(call.fn, repl, time, from, to, last.year, occup.m, ant.occ.m, > version platform i386-pc-mingw32 arch i386 os mingw32 system i386, mingw32 status major 1 minor 8.0
2005 Sep 19
4
factor as seq() in for loop
Dear all, I would like to use the values in vegaggr.BLMCMR02$colony str(vegaggr.BLMCMR02) `data.frame': 1678 obs. of 3 variables: $ vegtype : Factor w/ 27 levels "2010","2020",..: 3 4 5 19 4 5 19 5 $ colony : Factor w/ 406 levels "0","1","10","100",..: 1 1 1 1 2 2 2 $ Totvegproparea: num 0.00055 0.03956 0.95705
2003 Jul 31
2
how as.numeric() !-> factor
Dear all, I have divided two vectors: Np.occup97.98<- as.data.frame(cbind(site = levels(sums$site), Np.occup97.98 = sums$Ant.Nptrad97.98/Ant.trad$Ant.trad97.98)) > Np.occup97.98 site Np.occup97.98 1 erken97 0.342592592592593 2 erken98 0.333333333333333 3 rormyran 0.48471615720524 4 valkror 0.286026200873362 However, at a later stage of the analysis I want >
2006 Dec 27
3
counties in different colours using map()
Hi, I would like to plot a map of US counties using different colors. map() seems to be the function to use, e.g. library(maps); map('usa'); map('county', 'colorado', add=T,fill = T, col=c(1:5)) plots Colorado counties using colours 1 to 5. However, I want each color to represent a certain value - a value to be picked from a data frame. This code should show a
2001 May 27
2
library for mixed GLM?
Dear all, I am taking a course in GLM given by a devoted SAS user. He has given us a homework where a mixed GLM with a logistic link and binomially distributed observations should be fitted. I know of the library nlme for mixed effect models but as I understand it, one cannot choose between different links and distributions in the functions provided there. I have so far managed very well with
2003 Jan 02
1
replace NA with factor class
Dear all, I have a tree data matrix. For some trees I lack info about tree species, but I want to set them to be spruce. For some reason the tree species names on the remaining (non-NA) rows are changed into numbers (that I do not recognise). I guess that ifelse is not the correct function to use, but I have not found any better one in my searches. Thanks in advance! Sincerely, Tord >
2007 Mar 19
5
order of values in vector
Dear all, I would like to get the order of the values in a vector. I have tried rank(), order() and searched the archive, though without success. Here is an example of a try x= c(20,30,50,40,60,10) cbind(sort.list(x),x) x [1,] 6 20 [2,] 1 30 [3,] 2 50 [4,] 4 40 [5,] 3 60 [6,] 5 10 but I was hoping to get this: x [1,] 2 20 [2,] 3 30 [3,] 5 50 [4,] 4 40 [5,] 6 60 [6,] 1 10 I'm
2000 Dec 10
1
basic plot() question
Dear all, I try to plot a logstic regression model as follows: Valkror<- read.table("Valkror.txt", header=T) np.bark<- glm(Npinc~bark, family=binomial, data=Valkror) plot.formula(np.bark$fitted.values~ Valkror$bark) The above looks nice but I want to connect the points with a line so I try: plot.formula(np.bark$fitted.values~ Valkror$bark, type="b") but it gives a
2001 Nov 21
2
distances from points to line
Dear all, I have discovered that there are many things that I used to do in my GIS which are easily done directly in R, for example calculating interpoint distances using geoR and pick out points inside a polygon using splancs. I now wonder, is there a function to create a line object like a watercourse and then calculate the distances between many points in space and this line? I couldn't
2003 Jan 16
1
problem with as.data.frame.table
Dear all, I think that what I want is an as.data.frame.table-object, but see error message below. I have a data frame with one tree per row, diaclass tells if it is a small, mid or large tree > cpy.tradart[1:5, ] ObjektID diaclass 1 AX.Grb.1 bigdia 2 AX.Grb.1 middia 3 AX.Grb.1 middia 4 AX.Grb.1 smalldia 5 AX.Grb.1 middia > I want a data frame telling no of trees per diameter
2003 Jan 02
1
aggregate: "sum" not meaningful for factors
Dear all, I try to summarise my data per category using aggregate, but for some reason I get the error message "sum" not meaningful for factors even though my vector is numeric. The data set is shown below. Could someone please give a hint. Thanks in advance! Sincerely, Tord > names(test) [1] "ObjektID" "tallstubbyta" > is.factor(test$ObjektID);