similar to: histograms of profiles for each class

Displaying 20 results from an estimated 10000 matches similar to: "histograms of profiles for each class"

2010 Aug 18
1
Plotting K-means clustering results on an MDS
Hello All, I'm having some trouble figuring out what the clearest way to plot my k-means clustering result on an my existing MDS. First I performed MDS on my distance matrix (note: I performed k-means on the MDS coordinates because applying a euclidean distance measure to my raw data would have been inappropriate) canto.MDS<-cmdscale(canto) I then figured out what would be my optimum
2010 May 13
1
Comparing histograms?
Rhelpers: I'm curious what the appropriate analysis to use for testing the hypothesis that two histograms are statistically different from one another? Thanks! --j
2010 Apr 05
1
Using pch with the RGL library
Hi, I am trying to compare two 3D plots. For that, I am trying to use the "pch" parameter in the "points3d" function, but it is not working. Is it implemented? Any suggestion? Here goes a reproducible code. I wanted the second plot having different symbols for the points. x <- rbind(matrix(rnorm(100, sd = 0.3), ncol = 2), matrix(rnorm(100, mean = 1, sd = 0.3),
2005 Aug 03
7
call fortran in R
Hello, I used a mac G5, R.2.1.1, and G77 3.4.4 and I would like to use and call a fortran subroutine. The trouble is that it seems I am not able to correctly load the compiled code. Here is what I have done: In the terminal this how I compiled my fortran code: R CMD SHLIB ~/Desktop/Fortan_kmeans/kmeans3.f There is the wrapper I have paste inside de kmeans3.f file: c
2005 Feb 02
4
Combining two histograms
I have data like: a <- rnorm(20000) b <- rep(FALSE,20000) b[sample(1:20000,15000)] <- TRUE Using Lattice graphics, I can produce two side-by-side histograms quite easily by: histogram(a | b) However, I would like to produce a "single" histogram with two bars within each bin, one for each group, as the groups are in reality very slightly different from each other. The
2005 Mar 30
5
2d plotting and colours
Hi! I am new to R just 3 days in it and i apologize if my questions seem very trivial and consumed your valuable time. I am coding in perl and i stumbled upon R regarding plotting good statistical graphs. I tried the kmean clustering for a large matrix ,say > 150 * 150 . I tried the example code given in the tutorial to perform 2d plot # i ranges from 2 to 10 cl <- kmeans(x, i, 20)
2012 Jun 26
3
plotting two histograms on one plot with hist function
I would like to plot two data sets (frequency (y-axis) of mean values for 0-1(x=axis)) on a single histogram for comparison. The hist() only allow the overlay of two histograms, and although barplot() allows beside=TRUE, it does not show frequency values (like hist) but rather all of the values. Is there any way that I can use the hist() to plot two data sets similar to the barplot(). Any help or
2003 Jun 05
1
kmeans (again)
Regarding a previous question concerning the kmeans function I've tried the same example and I also get a strange result (at least according to what is said in the help of the function kmeans). Apparently, the function is disregarding the initial cluster centers one gives it. According to the help of the function: centers: Either the number of clusters or a set of initial cluster
2005 Apr 01
4
error in kmeans
I am trying to generate kmean of 10 clusters for a 165 x 165 matrix. i do not see any errors known to me. But I get this error on running the script Error: empty cluster: try a better set of initial centers the commands are M <-matrix(scan("R_mutual",n = 165 * 165),165,165,byrow = T) cl <- kmeans(M,centers=10,20) len = dim(M)[1] .... .... I ran the same script last night and
2006 Apr 07
2
cclust causes R to crash when using manhattan kmeans
Dear R users, When I run the following code, R crashes: require(cclust) x <- matrix(c(0,0,0,1.5,1,-1), ncol=2, byrow=TRUE) cclust(x, centers=x[2:3,], dist="manhattan", method="kmeans") While this works: cclust(x, centers=x[2:3,], dist="euclidean", method="kmeans") I'm posting this here because I am not sure if it is a bug. I've been searching
2003 Feb 13
1
k- means cluster analysis
Hi all, I am trying to run the k-means cluster analysis using the function kmeans in the package cluster. The data are: x = c(-0.26, -0.23, -0.05, -0.20, 0.30, -0.84, -0.10, -0.12, 0.10, -0.31, -0.19, 0.18, -0.26, -0.23, -0.37, -0.23) I've got two different solutions when I ran this function over a few times: kmeans(x, centers=2) The first solution gives the following: $cluster [1]
2011 Apr 06
2
Help in kmeans
Hi All, I was using the following command for performing kmeans for Iris dataset. Kmeans_model<-kmeans(dataFrame[,c(1,2,3,4)],centers=3) This was giving proper results for me. But, in my application we generate the R commands dynamically and there was a requirement that the column names will be sent instead of column indices to the R commands.Hence, to incorporate this, i tried using the R
2003 Apr 14
2
kmeans clustering
Hi, I am using kmeans to cluster a dataset. I test this example: > data<-matrix(scan("data100.txt"),100,37,byrow=T) (my dataset is 100 rows and 37 columns--clustering rows) > c1<-kmeans(data,3,20) > c1 $cluster [1] 1 1 1 1 1 1 1 3 3 3 1 3 1 3 3 1 1 1 1 3 1 3 3 1 1 1 3 3 1 1 3 1 1 1 1 3 3 [38] 3 1 1 1 3 1 1 1 1 3 3 3 1 1 1 1 1 1 3 1 3 1 1 3 1 1 1 1 3 1 1 1 1 1 1 3
2003 Oct 28
1
stacking histograms
Hi, I have a set of observations which are divided into two sets A and B. I have some code that bins the dataset into 10 bins based on the max and min of the observed values. I would like to make a histogram of A & B using my calculated bins but plot the distribution of B on top of A (like a stacked barplot). This is possible since both sets A & B are binned using the same bin ranges.
2002 May 13
3
Histograms rotated, side-by-side
Hi there, I am wanting to create 8 side-by-side histograms which have been rotated 90 degrees clockwise from how they usually sit.. all with the same scales. Is someone able to help me out? Thanks so much, Rachel Cunliffe -.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.- r-help mailing list -- Read http://www.ci.tuwien.ac.at/~hornik/R/R-FAQ.html Send
2013 Jun 24
1
K-means results understanding!!!
Dear members. I am having problems to understand the kmeans- results in R. I am applying kmeans-algorithms to my big data file, and it is producing the results of the clusters. Q1) Does anybody knows how to find out in which cluster (I have fixed numberofclusters = 5 ) which data have been used? COMMAND (kmeans.results <- kmeans(mydata,centers =5, iter.max= 1000, nstart =10000)) Q2) When I
2009 Jan 28
3
Newbie Question About Histograms
Hello everyone. Just have a question , cant figure out how to make this histogram. I have this table, that i stored in a variable name new.data2. Table looks like this Year GeoArea SmpNo Month Gear Maturity Length Age YearC 1989 1 362 10 22 1 225 1 1988 1991 1 267 10 10 1 191 1 1990 1991 1 267 10 10 1 202 1 1990 1992
2005 Nov 15
2
y-axis in histograms
Dear R- list, I have some data to present with histograms. Therefore I used hist(...). I have few values with almost 80% of the frequencies (totaly 800) and some other values with low frequencies ( totaly 5 -10 ) that I want to emphasize. Therefore I want to "cut" the y-axis on 100, but I don't know how to deal with this. Thanks in advance, Michael Graber
2004 May 11
2
Probleme with Kmeans...
Hello, I would like to have any help with the function Kmeans of R.. I use this to do a classification of my data...I have chosen 12 classes but, I have always an error message: Error: empty cluster: try a better set of initial centers So, I don't understand the probleme with this function.. Thank you to help me!! All the Best Clothilde Clothilde Kussener CNRS - CEBC 79360 Villiers en bois
2003 Jun 06
1
Kmeans again
Dear helpers I'm sorry to insist but I still think there is something wrong with the function kmeans. For instance, let's try the same small example: > dados<-matrix(c(-1,0,2,2.5,7,9,0,3,0,6,1,4),6,2) I will choose observations 3 and 4 for initial centers and just one iteration. The results are > A<-kmeans(dados,dados[c(3,4),],1) > A $cluster [1] 1 1 1 1 2 2 $centers