similar to: Possible POSIXlt / wday glitch & bugs.r-project.org status

Hey guys, I was playing with the cron trigger, and I noticed that wday is not honored. Looking at the code confirms this. Has anyone else seen this? Thanks Adam -------------- next part -------------- An HTML attachment was scrubbed... URL: http://rubyforge.org/pipermail/backgroundrb-devel/attachments/20071217/44d3a8a6/attachment.html

I'm reading in ~3 years worth of data that includes hourly timestamps. Presumably to avoid DST confusion, all the data is in PST time zone -- no discontinuities in the spring or fall. The data comes in a csv file, which I'm reading with myvariable <- read.csv("my_data_file.csv",header=FALSE,

Hola, El problema que tienes es en esta sentencia: ymd_hms(TEM$TIMESTAMP) No la estás asignando a nada. Lo suyo es que hagas algo así: TEM$myTimeStamp <- ymd_hms(TEM$TIMESTAMP) Y crees el intervalo (seq...) on esta nueva variable. El error que obtienes es que "TEM$TIMESTAMP" al leerla del fichero es un string, pero en la lectura automáticamente (salvo que le digas que no lo

Buen día para todos, Tengo un dataframe nombrado como mydata en donde una de sus variables en columna de nombre *date* tiene una secuencia de fechas en formato *ymd_hms*. Ahora quiero convertir este formato a *dmy_hms * en toda la variable *date.* Me podrían ayudar a saber como debo hacerlo? Quedo atento a sus comentarios. Saludos, Gracias, *JONATHAN BARTOLO PINZON * *"En los

Sorry, la función por el formato que tienen tus fechas debe de ser "dmy_hms()"... Saludos, Carlos Ortega www.qualityexcellence.es El 25 de septiembre de 2014, 18:14, Eduardo Bieñkowski <edukoski en gmail.com> escribió: > Si lo proceso con date<-ymd_hms(dato$actualizado) no me da error pero la > transformación no es la correcta > > > head(dato$actualizado) >

Eduardo, Me parece que el problema es el locale para TIME y la interpretación de %p, para no tener ese problema lo que tengo que hacer en mi caso es cambiar LC_TIME: > Sys.getlocale() [1] "LC_COLLATE=Spanish_Argentina.1252;LC_CTYPE=Spanish_Argentina.1252;LC_MONETARY=Spanish_Argentina.1252;LC_NUMERIC=C;LC_TIME=Spanish_Argentina.1252" > Sys.setlocale("LC_TIME",

try using 'lubridate' > library(lubridate)Attaching package: ?lubridate? The following objects are masked from ?package:base?: date, intersect, setdiff, union > x <- "2017-02-28T13:35:00+03:00"> ymd_hms(x)[1] "2017-02-28 10:35:00 UTC" > Thanks Jim Holtman *Data Munger Guru* *What is the problem that you are trying to solve?Tell me what you

OK, so the consensus is (1) One cannot make strptime accept ISO8601-compliant zone designators (2) The lubridate package can (3) Or one can hack away with regex. Lubridate it is, then. But I do regard strptime's inability to process ISO8601-compliant zone designators as a bug. On Mon, 6 Nov 2023 at 13:18, jim holtman <jholtman at gmail.com> wrote: > try using 'lubridate'

Thanks to all who replied. On Mon, 6 Nov 2023 at 18:37, Richard O'Keefe <raoknz at gmail.com> wrote: > OK, so the consensus is > (1) One cannot make strptime accept ISO8601-compliant zone designators > (2) The lubridate package can > (3) Or one can hack away with regex. > Lubridate it is, then. > > But I do regard strptime's inability to process

Full_Name: Ross Darnell Version: 2.4.1 OS: Linux Submission from: (NULL) (130.102.133.33) rdarnell at pc:~/Data$ ls -al .RData -rwxrwxrwx 2 root root 13551 2006-12-06 08:58 .RData rdarnell at pc:~/Data$ R R version 2.4.1 (2006-12-18) Copyright (C) 2006 The R Foundation for Statistical Computing ISBN 3-900051-07-0 R is free software and comes with ABSOLUTELY NO WARRANTY. You are welcome to

Hi all, Is there a simple function already implemented for getting the ISO weeks of a Date object? I couldn't find one, and so wrote my own function to do it, but would appreciate a pointer to the "default" way. If a function is not yet implemented, could the code below be of interest to submit to CRAN? Best Regards, Gustaf --------------------

Hi all Observe: x <- c(1,2) y <- c(1,-1) phi <- 1 p <- 2 par( mfrow=c(1,2)) plot(x , y, main=bquote( paste( p==.(p)," and ",phi==.(phi)) ) ) plot(y ~ x, main=bquote( paste( p==.(p)," and ",phi==.(phi)) ) ) par( mfrow=c(1,2)) On my system (details below), the first plot is correct (in my understanding), and produces a title reading "p=2 and phi=1"

On converting character variables to ordered factors, regression result has strange names. Is it possible to obtain same variable names with and without intercept? Thanks, Naresh mydf <- data.frame(date = seq.Date(as.Date("2024-01-01"), as.Date("2024-03-31"), by = 1)) mydf[, "wday"] <- weekdays(mydf$date, abbreviate = TRUE) mydf.work <- subset(mydf, !(wday

Buenas tardes a tod@s, Estoy incursionando en el analisis de tweets utilizando el paquete twitteR y siguiendo http://www.webmining.cl/2012/07/text-mining-de-twitter-usando-r/ Desafortunadamente cuando ejecuto # cargar librerias library(twitteR) library(tm) library(wordcloud) # recolecta tweets de @camila_vallejo tweets = userTimeline("camila_vallejo", 2000) obtengo Error in

I have an S4 object class defined in a Bioconductor package which contains multiple slots, some of which are tibbles, whilst others are vectors. If I call slot(object, name) where 'name' is an slot that contains a vector, everything works as expected. However, when I call slot(object, name) where 'name' is an slot that contains a tibble I get the following warning: Warning

Hola a todos, Me gustaria leer el texto que se encuentra en http://dl.dropboxusercontent.com/u/9601860/txt.txt He intentado txt <- 'http://dl.dropboxusercontent.com/u/9601860/txt.txt' r <- scan(txt) #Error in scan(file, what, nmax, sep, dec, quote, skip, nlines, na.strings, : # invalid multibyte string at '<ff><fe>M' r <- read.table(txt, header = FALSE)

Hello, I have a seemingly simple problem that a tab-delimited file can't be read in. > annoTranscripts <- read.table("matched.txt", sep = '\t', stringsAsFactors = FALSE) Error in scan(file, what, nmax, sep, dec, quote, skip, nlines, na.strings, : line 5933 did not have 12 elements However, all lines do have 12 columns. > lines <-

Bug summary: glm() causes a segfault if the argument 'data' is a data frame with more than 16384 rows. Bug demonstration: -------input --------------- N <- 16400 df <- data.frame(x=runif(N, min=1,max=2),y=rpois(N, 2)) glm(y ~ x, family=poisson, data=df) ------ output --------------- *** caught segfault *** address (nil),

Hello, I have a minimal example that shows a problem I'm having with parallel processing. library(parallel) mcmapply(function(x, y) { print("Running") Sys.sleep(10) }, as.list(1:10), as.list(10:1), mc.cores = 16, SIMPLIFY = FALSE) I see "Running" printed once every ten seconds. I read the documentation for mcmapply, but I don't understand why it wouldn't

Hi there, using cbind with a numeric and raw argument produces an incorrect result. I've posted some details below, kind regards, Mike. e.g. > cbind(0, as.raw(0)) [,1] [,2] [1,] 0 6.950136e-310 A longer example shows that the result is not a rounding error, is not consistent, and repeated applications get different results. > cbind(0, as.raw(1:10))