similar to: on how to make a skip-table

input: > values [1] 0.854400 1.648465 1.829830 1.874704 7.670915 7.673585 7.722619 > thresholds [1] 1 3 5 7 9 expected output: [1] 1 4 4 4 7 That is, need a vector of indexes of the maximum value below the threshold. e.g. First element is "1", because value[1] is the largest below threshold "1". Second element is "4", because value[4] is the

Dear list Sorry to ask a user's question on developer list. I didn't find the user list. I am experimenting with --cuesheet and encoded a flac file with a cuesheet. Result is: * Totem on opensuse 10.2 opens the flac file with no meta data, no play list. "Next" button doesn't work; * Mplayer on opensuse 10.2 opens the flac file with no meta data,

Hello. In my case I can successfully boot up my Thinkpad X32, but the same configuration doesn't work for my desktop computer with Intel network card, with Intel Boot Agent 2.2 DHCP server is 10.0.0.1, tftpd (used tftp-hpa) runs on 10.0.0.32. netstat told me the daemon listen to 69 UDP port just fine. running tftp in commandline also shows it works (retrieve pxelinux.0 less then 1 second).

Dear all I've got stuck when trying to replace values in a vector by selecting replacements from a replacement table. I'm trying to use only base functions. Here's a dummy example: > (x <- rep(letters,2)) [1] "a" "b" "c" "d" "e" "f" "g" "h" "i" "j" "k" "l"

Dear List. My requirement is to set up a samba share named "music" that: I. it's read-only accessible from both Windows 98 and Windows 2000/XP not requiring password; II. it's write-accessible from Windows XP protected by a password. I thought in order to cope with Windows 98 I need to I. use "security = share" (done), and set "guest ok =

I have been working with the pls procedure and have problems getting the procedure to work with matrix or frame data. I suspect the problem lies in my understanding of frames, but can't find anything in the documentation that will help. Here is what I have done: I read in an 10000 x 8 table of data, and assign the first four columns to matrix A and the second four to matrix B pls <-

Hi, In the example you showed: m1<- matrix(0,length(vec),max(vec)) 1*!upper.tri(m1) #or ?m1[!upper.tri(m1)] <-? rep(rep(1,length(vec)),vec) #But, in a case like below, perhaps: vec1<- c(3,4,5) ?m2<- matrix(0,length(vec1),max(vec1)) ?indx <- cbind(rep(seq_along(vec1),vec1),unlist(tapply(vec1,list(vec1),FUN=seq),use.names=FALSE)) m2[indx]<- 1 ?m2 #???? [,1] [,2] [,3] [,4] [,5]

Dear R experts, I have 2 matix: A& B. I am trying to index B against A - (1) find out B rows that fall between the col 1 and 2 of A& put them into a new vector SNP.I made code as below, but I cannot think of a right way to do it. Could anyone help me with the code? Thanks,Jiang---- A <-

Folks: In answer to a query, Andy Liaw recently submitted some code to construct a block diagonal matrix. For what seemed a fairly straightforward task, the code seemed a little "overweight" to me (that's an American stock analyst's term, btw), so I came up with a slightly cleaner version (with help from Andy): bdiag<-function(...){ mlist<-list(...) ## handle case in

Dear R users. I'm trying to avoid using nested loops in the following code but I'm not sure how to proceed. Any help would be greatly appreciated. With regards,Phil X = matrix(rnorm(100), 10, 10) ## Version with nested loopsresult = 0 for(m in 1:nrow(X)){ for(n in 1:ncol(X)){ if(X[m,n] != 0){ result = result + (X[m,n] / (1 + abs(m - n))) } }} ## No loop-sum(ifelse(M

> Hello, > > Is this the fastest way to use indices from one matrix to reference rows > in another smaller matrix? I am dealing with very big data (lots of columns > and I have to do this lots of times). > > ######sample data ############## > vals = matrix(LETTERS[1:9], nrow=3,ncol=3) > colnames(vals) = c('col1','col2','col3') > rownames(vals)

Can anybody please tell me a good way to do the following? Given a vector, number of rows and number of columns, return a matrix as follows. Easiest to give an example: x=c(1,2), nrow=5, ncol=4 return the matrix: 1 0 0 0 2 1 0 0 0 2 1 0 0 0 2 1 0 0 0 2 Thanks very much for any help! Bill

Hola! I am programming a class (S3) "symarray" for storing the results of functions symmetric in its k arguments. Intended use is for association indices for more than two variables, for instance coresistivity against antibiotics. There is one programming problem I haven't solved, making an inverse of the index function indx() --- se code below. It could for instance return the

Dear R users, I want to check matrices when i change the order of the rows or/and the order of the columns or/and the combination of them i will give an example what i want  1  -1  1  1      1  1   1  1 -1  -1 -1 -1    -1 -1  -1  -1   1  1    1  1     1 -1    1   1 these 2 matrices are identical because i change the first row and make it third   1  -1  1  1      -1  1   1  1 -1  -1 -1

I wrote a function which does "moving window" regressions. E.g. if there are 100 observations and the window width is 50, then I first run the regression for observations 1..50, then for 2..51, and so on. I am extremely pleased with R in my experience with writing this, since I was able to pass the model as an argument into the function :-) Forgive me if I sound naive, but that's

Hello, Is the first time I am using SNOW package and I am trying to tune the cost parameter for a linear SVM, where the cost (variable cost1) takes 10 values between 0.5 and 30. I have a large dataset and a pc which is not very powerful, so I need to tune the parameters using both CPUs of the pc. Somehow I cannot manage to do it. It seems that both CPUs are fitting the model for the same values

Hi all, I need to estimate S.E. of a certain indicator. The function to compute the value of indicator contains two arguments. Can anybody tell me how to do it? Example: We have data: a <- c(1:10) b <- c(11:20) data <- data.frame(a, b) Function to compute value of the indicator: indicator <- function(X, Y) sum(X)/(sum(Y)*2) Next I need to do the

Hi all, What would be an efficient way to match rows of a matrix to a vector? ex: m<-matrix(1:9, nrow=3) m [,1] [,2] [,3] [1,] 1 4 7 [2,] 2 5 8 [3,] 3 6 9 ################################# which(m==c(2,5,8)) # I want this to return 2 ###################### Thanks, Sachin [[alternative HTML version deleted]]

Could someone please suggest a more clever solution to the following problem than my loop below? Given X a 2xN matrix X, and I a k-subset of N, Generate the (2^k)xN matrix Y with columns not in I all zero and the other columns with all choices of an entry from the first or second row of X. For example, with X <- matrix(1:8, nrow=2) I <- c(1,3) X is 1 3 5 7 2 4 6 8 and Y should be 1 0 5

Hi All, I need a basic help from you. I've built a function like this, windowlength<-function(x) { z <- rep(seq(0,331,by=x-1)+1, each=2) zz <- z[-c(1,length(z))] ind <- as.data.frame(matrix(zz, nr=2)) j<-lapply(ind, function(x) mat[x[1]:x[2],]) cat("For",x/4,"month