similar to: Sorting data.frame and again sorting within data.frame

Displaying 20 results from an estimated 20000 matches similar to: "Sorting data.frame and again sorting within data.frame"

2013 Mar 28
6
How to delete Identical columns
Dear R forum Suppose I have a data.frame df = data.frame(id = c(1:6), x = c(15, 21, 14, 21, 14, 38), y = c(36, 38, 55, 11, 5, 18), x.1 = c(15, 21, 14, 21, 14, 38), z = c("D", "B", "A", "F", "H", "P")) > df   id  x  y    x.1 z 1  1 15 36  15 D 2  2 21 38  21 B 3  3 14 55  14 A 4  4 21 11  21 F 5  5 14  5  14 H 6  6 38 18  38 P
2013 Apr 16
3
Splitting the Elements of character vector
Dear R forum I have a data.frame df = data.frame(currency_type = c("EURO_o_n", "EURO_o_n", "EURO_1w", "EURO_1w", "USD_o_n", "USD_o_n", "USD_1w", "USD_1w"), rates = c(0.47, 0.475, 0.461, 0.464, 1.21, 1.19, 1.41, 1.43))   currency_type     rates 1      EURO_o_n   0.470 2      EURO_o_n   0.475 3       EURO_1w   0.461
2013 Apr 17
3
Creating a vector with repeating dates
Dear R forum I have a data.frame df = data.frame(dates = c("4/15/2013", "4/14/2013", "4/13/2013", "4/12/2013"), values = c(47, 38, 56, 92)) I need to to create a vector by repeating the dates as "Current_date", 4/15/2013, 4/14/2013, 4/13/2013, 4/12/2013,  "Current_date", 4/15/2013, 4/14/2013, 4/13/2013, 4/12/2013, Current_date,
2013 Apr 03
4
Better way of writing R code
Dear R forum, (Pl note this is not a finance problem) I have two data.frames as currency_df = data.frame(current_date = c("3/4/2013", "3/4/2013", "3/4/2013", "3/4/2013"), issue_date = c("27/11/2012", "9/12/2012", "14/01/2013", "28/02/2013"), maturity_date = c("27/04/2013", "3/5/2013",
2012 Dec 20
2
How to count the nos. in a range?
Dear R forum I have a following vector of random no.s x = runif(100, 0.01, 0.99)  [1] 0.47212037 0.77867992 0.33947474 0.93369035   [5] 0.03720073 0.79307831 0.81801835 0.92710688 ................................................. I need to count the random no. falling in the range (0 - 0.10), (0.10 - 0.20), (0.20 - 0.30)..upto (0.90 - 1) Thus, I need to have a data frame as
2012 Dec 21
2
Can data.frame be saved as image?
Dear R forum I have one stupid question, but I have no other solution to it in sight? Suppose some R process creates graphs etc alongwith main output as data.frame e.g output1 = data.frame(bands = c("A", "B", "C"), results = c(74, 108,  65)) I normally save this output as some csv file. But I need to save this output as some image (I understand this is weird,
2013 Apr 26
2
Splitting data.frame and saving to csv files
Dear R Forum, I have a data.frame as df = data.frame(date = c("2013-04-15", "2013-04-14", "2013-04-13", "2013-04-12", "2013-04-11"), ABC_f = c(62.80739769,81.04525895,84.65712455,12.78237251,57.61345256), LMN_d = c(21.16794336,54.6580401,63.8923307,87.59880367,87.07693716), XYZ_p = c(55.8885464,94.1358684,84.0089114,98.99746696,64.71083712),
2013 Oct 17
4
Subseting a data.frame
Dear Forum, I have a data frame as  mydat = data.frame(basel_asset_class = c(2, 8, 8 ,8), defa_frequency = c(0.15, 0.07, 0.03, 0.001)) > mydat   basel_asset_class defa_frequency 1                 2          0.150 2                 8          0.070 3                 8          0.030 4                 8          0.001 I need to get the subset of this data.frame where no of records for the
2013 Oct 17
4
Subseting a data.frame
Dear Forum, I have a data frame as  mydat = data.frame(basel_asset_class = c(2, 8, 8 ,8), defa_frequency = c(0.15, 0.07, 0.03, 0.001)) > mydat   basel_asset_class defa_frequency 1                 2          0.150 2                 8          0.070 3                 8          0.030 4                 8          0.001 I need to get the subset of this data.frame where no of records for the
2013 Oct 16
1
How to write an error to output
Dear R forum, The example below is just an indicative one and I have constructed it. My real life data and conditions are different. I have a data.frame as given below mydat = data.frame(A = c(19, 20, 19, 19, 19, 18, 16, 18, 19, 20), B = c(19, 20, 20, 19, 20, 18, 19, 18, 17, 16)) if (length(mydat$A) > 10) { stop("A has length more than 10") }else if (max(mydat$B) > 18) {
2013 Mar 26
2
Counting various elemnts in a vactor
Dear R forum I have a vector say as given below df = c("F", "C", "F", "B", "D", "A", "D", "D", "A", "F", "D", "F", "B",    "C") I need to find (1) how many times each element occurs? e.g. in above vector F occurs 4 times, C occurs 2 times etc. (2)
2012 Jul 18
2
How to have original (name) order after melt and cast command
Dear R helpers, I have a data.frame as given below - dat1 = data.frame(date = as.Date(c("3/30/12","3/29/12","3/28/12","3/27/12","3/26/12", "3/23/12","3/22/12","3/21/12","3/20/12", "3/30/12","3/29/12","3/28/12","3/27/12",
2013 Apr 29
2
Adding elements in data.frame subsets and also subtracting an element from the rest elements in data.frame
Dear R forum I have a data.frame as cashflow_df = data.frame(instrument = c("ABC","ABC","ABC","ABC","ABC","ABC","ABC","ABC","ABC","ABC","ABC","ABC","ABC","ABC", "ABC", "PQR", "PQR",
2013 Mar 27
1
Archieve of mails from R forum
Dear R helpers, Everyday I do receive many many mails from R forum and after some period of times, INBOX is filled with numerous mails. At times if for some period of time, I haven't accessed mails, it becomes difficult to keep track of mails and many times simply due to the volume (and owing to the lack of time due to office constraints), I have to simply delete the mails without opening
2013 Apr 25
1
Linear Interpolation : Missing rates
Dear R forum I have data.frame as df = data.frame(rate_name = c("USD_1w", "USD_1w", "USD_1w", "USD_1w", "USD_1m", "USD_1m", "USD_1m", "USD_1m", "USD_2m", "USD_2m", "USD_2m", "USD_2m",  "GBP_1w", "GBP_1w", "GBP_1w", "GBP_1w",
2010 Aug 27
1
Band-wise Sum
Hi I have a large credit portfolio (exceeding 50000 borrowers). For particular process I need to add up the exposures based on the bands. I am giving a small test data below. rating <- c("A", "AAA", "A", "BBB","AA","A","BB", "BBB", "AA", "AA", "AA", "A", "A",
2010 Aug 30
2
Band-wise Conditional Sum - Actual problem
Dear R helpers, Thanks a lot for your earlier guidance esp. Mr Davind Winsemius Sir. However, there seems to be mis-communication from my end corresponding to my requirement. As I had mentioned in my earlier mail, I am dealing with a very large database of borrowers and I had given a part of it in my earlier mail as given below. For a given rating say "A", I needed to have the bad-wise
2013 May 02
1
Clean Price of Bond : Can't install "RQuantLib" in R version 3.0.0
Dear Forum, I have R version 3.0.0 installed and need to install RQuantLib pacakge. I tried to install it from CRAN Mirror and I couldn't load it. I had saved the package i zip format and tried to install it locally but I am getting following error. > utils:::menuInstallLocal() Error in read.dcf(file.path(pkgname, "DESCRIPTION"), c("Package", "Type")) :  
2013 Jan 23
1
How to extract values of results in gamlss.tr
Dear R helpers, I have following loss data and I need to fit LEFT truncated Log Normal distribution to this data which is Truncated at 1000000. dat = c(1333834,5710254,9987567,7809469,6940935,3473671,1270209,1102523,1124002, 5830159,4302300,3925242,2638409,2324421,7238436,9088709,7439250,4976551,4864319, 8741334,1863770,7098310,4942288,4971829,4986372) library(gamlss.tr) gen.trun(5, LOGNO)
2013 Jan 21
1
lmomco package - Random number generation using Wakeby distribution
Dear R forum >From the given data, I have estimated the parameters of Wakeby distribution using lmomco package as library(lmomco) (amounts <- read.csv("input_S.csv")$amount) # ___________________________________________________________ # Wakeby distribution - Parameter estimation N                      = length(amounts) lmr                    = lmom.ub(amounts)