similar to: write.csv

dear list, i have a problem using the adaboost function from the package boost. running the example of leukemia works out very well, but so it does not on my own data. i always get the following 22 warnings: 1: cannot compute exact p-value with ties in: wilcox.test.default(x[which(y == 0)], x[which(y == 1)]) can anybody please help me with the meaning of this warning. thnak you stefan

Hello I have around 200 PDF-documents, containing data i want organized in R as a dataframe. The PDF-documents look like this; http://www.nabble.com/file/p21667074/PRRS-billede%2Bmed%2Bfarver.jpeg or like this; http://www.nabble.com/file/p21667074/PRRS-billede%2Bmed%2Bfarver%2B2.jpeg So i want to pull out the data in coloured boxes it become organized like this (just in R instead of

hello, this is my script: #1) read in data: daten<-read.table('K:/Analysen/STRUCTURE/input_STRUCTURE_tab_excl_5_282_559.txt', header=TRUE, sep="\t") daten<-as.matrix(daten) #2) create empty matrix: indxind<-matrix(nrow=617, ncol=617) indxind[1:20,1:19] #3) compare cells to each other, score: for (s in 3:34) { #walks though the matrix colum by colum, starting at

Hi You wrotte me in R help and I´m very gratefull. I couldn´t reply because an illness. I writte this to see if you can help to solve. I´m a begginer (I´m 20 years old ) but I´m trying to learn more about this program also I´m learning Octave. I need to create a matrix in R whose values depends on the values of other matrix. You see: I have a first "R" matrix whose first row and

Hello, I have a problem with reading a csv-file. One colum of the inputfile consists of characters and numbers. After reading the csv-file I create a new dataframe by dividing the values of that colum into more colums (then a colum contains just characters or numbers) but the numbers are converted to factors. How can I create the new dataframe without having the numbers converted to factors?

Dear r-helpers, I read a .csv file into R with the following command: A<-read.csv2(file="Mappe3.csv") It worked fine, except that I would like to get rid of the points between the words and get spaces instead like I have got in the .csv file. At the moment it looks like the following: habe.mich.gut.mit.KlassenkollegInnen.verstanden hatte.gutes.Verhältnis.zu.Eltern

Hi I want to set a variable to either 1 or 0 depending on an value of a dataframe and then add this as a colum to the dataframe. This could be done with a loop but as we are able to do questions on a complete row or colum without a loop it would be sweet if it could be done. for example: table: Name Age Joel 24 agust 17 maja 40 and so on... And what I want to do is a command that

Hi everybody How do I do to calculate the median and average of a colum of time data like this: "8:50:10". I also need to plot the time difference between two colums Thanks a lot -- View this message in context: http://n4.nabble.com/median-for-time-data-tp932287p932287.html Sent from the R help mailing list archive at Nabble.com.

What function and package I use to conduct ordinal regression?? My data is composed 2colums and 180rows. The first colum indicate level of mass and second colum is intensity. So, I want to calculate how much intensity are related mass. [[alternative HTML version deleted]]

I have a matrix, I would like to use it like I use where query on an SQL table Let's say my matrix is > wok who task 1 joe task1 2 joe task2 3 joe task3 4 jack task1 5 jack task2 I want to extract a matrix that contains only rows where who = "joe" and task != "task2" The result would be the following matrix 1 joe task1 2 joe task3 How can I do

I have a data frame whose first colum contains the names of the variables and whose second colum contains the values to assign to them: : kkk <- data.frame(vars=c("var1", "var2", "var3"), vals=c(10, 20, 30), stringsAsFactors=F) If I do : assign(kkk$vars[1], kkk$vals[1]) it works : var1 [1] 10 However, if I try with mapply

Hi all, I want to plot trough pairs() plot a matrix with 4 columns. I want to make a trhee plot in a graph. Plotting pairs colum 2,3,4 on y axis and 1 on X axis. You mean (a plot with three graphs) ommitting the first pair with itself. And only the pairs with colum 1 with the other not all pairs. I. e. this matrix 4177 289390 8740 17220 3907 301510 8530 17550 3975 316970 8640 17650 3651 364220

Hi all: Can someone help me count the number of rows with values in colum "a" only. assume the name of my dataframe is "weekly" I was trying i<- nrows(weekly$a) i but returns 7 when it should be 4. Thanks a b c d 27.000 27.000 1.569 0.013 160.000 27.000 1.632 0.013 146.000 27.000 1.830 0.015 70.000 27.000 2.475 0.019

Sebastian Pop wrote: > Jack Howarth wrote: > > The attached patch eliminates http://llvm.org/bugs/show_bug.cgi?id=15817 by removing the remaining > > "; XFAIL:*" added in http://lists.cs.uiuc.edu/pipermail/llvm-commits/Week-of-Mon-20130415/171812.html. > > The Isl/CodeGen/scevcodegen-1.ll testcase in polly appears as an XPASS in current llvm/polly 3.3 > >

Hallo, Ich habe ebendfalls das Problem, dass ich mich extra anmelden muss bei meinem Linux-Server. Hast Du da eine L?sung gefunden. From: "Marcel Stein" <marcel-stein@arcor.de> Subject: samba und netzlaufwerke unter winxp Date: Thu, 26 Jun 2003 20:04:56 +0200 Message-ID: <000001c33c0d$76d703f0$0201a8c0@winxp> Ich habe einen samba zu laufen und greife vom client winxp

Hi all, I want to make multiple least squares estimation on two matrix (without intercept) imagine matrix "a" and matrix "b", I want to "regress" each colum on matrix "a" (dependent variable) on each column of matrix b, I mean, regress first colum on a to first column on b. Second column on a to second column on b. Imagine "a" and "b"

On 05/31/2013 10:11 AM, Sebastian Pop wrote: > Sebastian Pop wrote: >> Sebastian Pop wrote: >>> Jack Howarth wrote: >>>> The attached patch eliminates http://llvm.org/bugs/show_bug.cgi?id=15817 by removing the remaining >>>> "; XFAIL:*" added in http://lists.cs.uiuc.edu/pipermail/llvm-commits/Week-of-Mon-20130415/171812.html. >>>>

Hi, Hopefully someone can point me in the right direction on how I would go about solving the following. I have some data and need to find the column name of the maximum value in each row. This could be the data... > a <- data.frame(x = rnorm(4), y = rnorm(4), z = rnorm(4)) > a x y z 1 1.6534561 0.11523404 0.2261730 2 -1.2274320 -0.24096054 1.5096028

Hallo Zusammen, hatte gestern die Schnauze voll von Vista und habe mir daraufhin Ubuntu installiert. Bin also mit Ubuntu ?berhaupt nicht vertraut. Nun habe ich ohne Erfolg versucht, R zu installieren. Soweit ich der Anleitung folgen konnte habe ich es so wie auf http://wiki.ubuntuusers.de/R gemacht. Im Terminal kann ich R problemlos starten. Allerdings bei der Installation von

On 05/31/2013 01:09 PM, Jack Howarth wrote: > On Fri, May 31, 2013 at 10:59:52AM -0700, Tobias Grosser wrote: >> On 05/31/2013 10:11 AM, Sebastian Pop wrote: >>> Sebastian Pop wrote: >>>> Sebastian Pop wrote: >>>>> Jack Howarth wrote: >>>>>> The attached patch eliminates http://llvm.org/bugs/show_bug.cgi?id=15817 by removing the