Displaying 20 results from an estimated 2000 matches similar to: "Multiply mailboxes vs one huge"
2011 Feb 10
3
Separate access to different "folders" of the same mailbox?
Hello Timo and everyone,
I think on such an idea that may save me a bit of space and time:
in my company we have a mailbox that holds a copy of every message that
our SMTP processed. While it eats a lot of space, it saved us several
times when, you may imaging, user "suddenly" deleted the most important
message in his life and call our IT guys for help. The mailbox contains
2018 Sep 17
3
Proxy secured incoming POP3/IMAP4 to unsecure backend?
The port is determined with port=nnn setting. You can't return per-protocol port like that, you need to look at the protocol requested by user and return port based on that, or you can omit port to default into "standard port".
not using ssl/starttls is default.
> On 17 September 2018 at 16:35 Alexander Chekalin <alexander.chekalin at gmail.com> wrote:
>
>
>
2018 Sep 17
4
Proxy secured incoming POP3/IMAP4 to unsecure backend?
Hi,
I try to set up dovecot as a proxy server, to proxy requests to several
dovecot-based backend servers. I wand external clients who connects to this
proxy Dovecot to use TLS (this is easy to set up) while want to have
unsecured (plain IMAP/POP) connections to backends.
You see, links to backends are over LAN so no TLS needed, and these
backends are poor old machines (with old Docecots like
2018 Sep 17
1
Proxy secured incoming POP3/IMAP4 to unsecure backend?
auth process receives the protocol requested when performing authentication as variable %s (see https://wiki2.dovecot.org/Variables)
You can use this to choose the value you return for port.
Aki
> On 17 September 2018 at 16:56 Alexander Chekalin <alexander.chekalin at gmail.com> wrote:
>
>
> Seen that URL but port= is strange due to there is no protocol connection.
> So
2009 Jul 11
2
Date conversions
Hi all,
I'm having a little bit of trouble with some date conversions and
am hoping someone can help me out. Thanks in advance.
OK, I have two sources of data that provide date info in a csv file
differently. I've attached a small zipped file with two text files
that illustrate both. (Is it ok to send attachments to this list? Not
sure. It's very small.) I need to be able to
2012 Nov 10
4
help on date dataset
Hi everybody,
I am beginer in R and I need your precious help.
I want to create a small function in R as in sas to retrieve date.
I have a file with data that import in R.
DATE PAYS nb_pays.ILI.
1 24/04/2009 usa 0
2 24/04/2009 usa 0
3 24/04/2009 Mexique 0
4 24/04/2009
2005 Feb 24
2
Row median of Date class variables in a data frame
I am trying to calculate the median of each row of a
data frame where the data frame consist of
columns of class Date.
Below are my test data and best attempt at using apply.
I didn't see a solution via Google or the Baron search
site.
I'd be grateful for any suggestions or solutions.
I'm using R 2.0.0 on Mac OS X.
Thank you,
Stephen Weigand
### Test data
date1 <- c(1000,
2015 Nov 06
0
Puzzled by eval
On 06/11/2015 7:36 AM, Therneau, Terry M., Ph.D. wrote:
> I am currently puzzled by a seach path behavior. I have a library of a dozen routines
> getlabs(), getssn(), getecg(), ... that interface to local repositories and pull back
> patient information. All have a the first 6 arguments in common, and immediately call a
> second routine to do initial processing of these 6. The
2006 Dec 28
3
Dates in R
Hello all,
Can somebody point me to references or provide some code on dealing with
this date issue. Basically, I have two vectors of values that represent
dates. I want to convert these values into a date format and subtract the
differences to show elapsed time in days. More specifically, here is the
example:
Date1 Date2
032398 061585
032398 061585
111694 101994
111694
2015 Nov 06
4
Puzzled by eval
I am currently puzzled by a seach path behavior. I have a library of a dozen routines
getlabs(), getssn(), getecg(), ... that interface to local repositories and pull back
patient information. All have a the first 6 arguments in common, and immediately call a
second routine to do initial processing of these 6. The functions "joe" and "fred" below
capture the relevant
2009 Dec 09
1
reshape() makes R run out of memory (PR#14121)
Full_Name: Alexander L. Belikoff
Version: 2.8.1
OS: Ubuntu 9.04 (x86_64)
Submission from: (NULL) (67.244.71.200)
I'm trying to reshape the following data frame:
ID DATE1 DATE2 VALUE_TYPE VALUE
'abcd1233' 2009-11-12 2009-12-23 'TYPE1' 123.45
...
VALUE_TYPE is a string and is a factor with only 2 values
2012 May 12
1
Query regarding date as argument in functions - and about sqldf
Hi,
I have a query about sqldf, and dates in general. I couldnt find much on
the net or on the forums, hence I am here. Here is the issue:
I want to write a function that accepts 3 arguments: date1, date2 and a
dataframe, say 'df'. Within the function, I want to populate a temp
dataframe which essentially contains the output of the query "select * from
df where DATE between date1
2013 Apr 13
2
Comparison of Date format
Hi,
?In the example you provided, it looks like the dates in Date2 happens first.? So, I changed it a bit.?
DataA<- read.table(text="
ID,Status,Date1,Date2 ??? ??? ??????
1,A,3-Feb-01,15-May-01 ??? ???
1,B,15-May-01,16-May-01 ??? ???
1,A,16-May-01,3-Sep-01 ??? ??? ??? ??? ???
1,B,3-Sep-01,13-Sep-01 ??? ??? ??? ??? ???
1,C,13-Sep-01,26-Feb-04 ??? ??? ??? ??? ???
2011 Aug 07
1
all.equal doesn't work for POSIXlt objects
Hi all,
following sample code illustrates the problem :
Date1 <- Date2 <-
as.POSIXlt(seq.Date(as.Date("2010-04-01"),as.Date("2011-04-01"),by='day'))
identical(Date1,Date2)
all.equal(Date1,Date2)
identical() gives the correct answer. As there is no all.equal method
for POSIXlt objects, all.equal.list is used instead. Subsetting using
[[]] doesn't work
2012 Mar 07
1
date columns chooser
i have a data frame with 2 columns of dates.
with str(dataframe) i have ensured myself that they were indeed formatted
as dates.
one column has NA's in it.
the aim is now to make a third column that chooses date1 if it is a date,
and choose date2 if it is a NA.
i am trying
df$date3=ifelse(is.na(df$date1), df$date2, df$date1).
this leads to unexpected behaviour: the resulting column is
2006 Jan 15
4
form inputs resetting on sumbit
I searched for forum for something about this but couldn''t find
anything.
For example I have this in my view: (you enter start/end dates from
dropdowns, pick a category and a report is generated.)
<%= start_form_tag :action => ''display_report'' %>
From: <%= date_select ''report'', ''date1'' %> <br />
To: <%=
2009 Jan 27
1
Mystery Error in midnightStandard
I wasn't even aware I was using midnightStandard. You won't find it in my
script.
Here is the relevant loop:
date1 = timeDate(charvec = Sys.Date(), format = "%Y-%m-%d")
date1
dow = 3;
for (i in 1:length(V4) ) {
x = read.csv(as.character(V4[[i]]), header = FALSE, na.strings="");
y = x[,1];
year = V2[[i]];
week = V3[[i]];
dtstr =
2009 Dec 04
0
simple reshape of a large data frame (reshape() runs out of memory)
Hello everyone,
I'm having a problem performing reshape() on a large data frame. The
operation is fairly trivial but it makes R run out of memory.
The data frame has the following structure:
ID DATE1 DATE2 VALTYPE
VALUE
'abcd1233' 2009-11-12 2009-12-23 'TYPE1'
123.45
...
VALTYPE is a string and is a factor with
2011 Nov 09
4
Please advise on very fast search
Hello,
I try to create some kind of mail backup system. What I need is system
that will store mail for the whole domain, and allow me to restore
messages from/to specified email at that domain.
The scheme is pretty simple: on our main mail server the SMTP server
itself has a rule to send a copy of every message to
'backup at backupserver.host', and the backupserver.host domain is
2005 Oct 04
2
Joining Dataframes
I am attempting to join several dataframes that summarize sampling effort
for different samples into one large data.frame/table.
I have looked at the merge command, but have not been clever enough to
figure out how to get it to do what I want.
A simplified example of what I am trying to do:
The dataframes I have look like this (they were generated using the table
command)
species1.effort