Displaying 20 results from an estimated 1000 matches similar to: "finding overlapping regions"
2010 Mar 14
3
range and intersection
Hi:
I have a two large files (over 300K lines).
file 1:
Name X
UK 199
UK 230
UK 139
......
UAE 194
UAE 94
File 2:
Name X Y
UK 140 180
UK 195 240
UK 304 340
....
I want to select X of File 1 and search if it falls in range of X and
Y of File 2 and Print only those lines of File 1 that are in range of
File 2 X and Y
How can it be done it
2009 Jun 18
3
R function found in two packages !
Hi,
Is there a mean to automatically choose one version of the 'rbind' function ? By default, R chose the 'rbind' from {base}, i would lke to use the one from {IRanges}...
Is it possible to set that using 'par' ?
> ?rbind
Help on topic 'rbind' was found in the following packages:
Package Library
IRanges
2009 Feb 25
1
Unexpected side effect of the ":::" operator on the value of isGeneric
Hi,
when running the following on a fresh R,
library("IRanges")
annotation
showMethods("annotation")
Biobase:::annotation
showMethods("annotation")
I get (see the "^^^^^" marked output at the bottom):
> library("IRanges")
Carico il pacchetto richiesto: 'IRanges'
The following object(s) are masked from package:base :
2008 Jan 10
2
`[.data.frame`(df3, , -2) and NA columns
Dear baseRs,
I recently made a mistake when renaming data frame columns, accidentally
creating an NA column. I found the following strange behavior when negative
indexes are used.
Can anyone explain what happens here. No "workarounds" required, just curious.
Dieter
Version: Windows, R version 2.6.1 (2007-11-26)
#-----------------------------
df = data.frame(a=0:10,b=10:20)
df[,-2]
2011 Aug 18
2
Best way/practice to create a new data frame from two given ones with last column computed from the two data frames?
Dear expeRts,
What is the best approach to create a third data frame from two given ones, when
the new/third data frame has last column computed from the last columns of the two given
data frames?
## Okay, sounds complicated, so here is an example. Assume we have the two data frames:
df1 <- data.frame(Year=rep(2001:2010, each=2), Group=c("Group 1","Group 2"), Value=1:20)
2009 Jan 21
3
merging several dataframes from a list
Hi there,
I have a list of dataframes (generated by reading multiple files) and all
dataframes are comparable in dimension and column names. They also have a
common column, which, I'd like to use for merging. To give a simple example of
what I have:
df1 <- data.frame(c(LETTERS[1:5]), c(2,6,3,1,9))
names(df1) <- c("pos", "data")
df3 <- df2 <- df1
df2$data
2008 Jan 24
2
boxplot axis labelling
Hi,
i'm very new to R, so sorry for what i'm sure is a very basic question. I'm
producing a boxplot with the data below:
df3<-data.frame(
x=c(10,11,115,12,13,14,16,17,18,21,22,23,24,26,27,28,29,3,30,32,33,34,35,4,4
1,45,5,50,52,56,58,6,67,6738,68,7,8,9),
fq=c(8,11,1,2,4,4,2,2,6,3,4,2,2,1,1,1,4,51,3,1,1,1,1,35,1,1,19,2,1,1,1,14,1,
1,1,10,13,5),
2008 Feb 19
2
Looping through a list of objects & do something...
Hey Folks,
Could somebody show me how to loop through a list of dataframes? I want to
be able to generically access their elements and do something with them.
For instance, instead of this:
df1<- data.frame(x=(1:5),y=(1:5));
df2<- data.frame(x=(1:5),y=(1:5));
df3<- data.frame(x=(1:5),y=(1:5));
plot(df1$x,df1$y);
plot(df2$x,df2$y);
plot(df3$x,df3$y);
I would like to do something like:
2009 Oct 07
1
merging dataframes with an unequal number of variables
Hallo Everyone
I have the kind of problem that one should never have because one must
always plan well and communicate with your team. But now I haven't so here
is my problem.
I have data coming in on a daily basis from surveys in 10 towns. The
questionnaire has 62 variables but some of the regions have used older
versions of the questionnaire that have a few variables less. I want to
combine
2010 Oct 21
2
How to access values in s4 method
Hi
How to access the values in the output that is an object of S4 type. I tried
to access using subset ( [ ] ) but it is not allowed.
Any clue??
Thanks
-- Fahim
#My code is as follows:
require(IRanges);
query <- IRanges(c(1, 4, 9), c(5, 7, 10))
subject <- IRanges(c(2, 2, 10), c(2, 3, 12))
findOverlaps(query, subject)
Output of find overlap function is:
------------------
1>
2008 Jul 26
1
Can't get the correct order from melt.data.frame of reshape library.
Simple illustration,
> df3 <- data.frame(id=c(3,2,1,4), age=c(40,50,60,50), dose1=c(1,2,1,2), dose2=c(2,1,2,1), dose4=c(3,3,3,3))> df3 id age dose1 dose2 dose41 3 40 1 2 32 2 50 2 1 33 1 60 1 2 34 4 50 2 1 3> melt.data.frame(df3, id.var=1:2, na.rm=T) id age variable value1 3 40 dose1 12 2 50 dose1 23 1
2012 Dec 17
1
Code works standalone, yet same code fails when part of package
Hi
I'm missing something here but I cannot figure out what. What I can see is that the same code works when I load it via source(...) yet fails when I execute it after loading the package I have built (which includes the code.
Below is a transcript of my R session. First I load the code from a file, using source(). Then I execute it fine. Then I remove the function object, I load the
2017 Dec 29
2
Facing problem in installing the package named "methyAnalysis"
Thank you Michael Dewey.
Can you please send me the email id for Bioconductor.
regards
Pijush
On Fri, Dec 29, 2017 at 5:20 PM, Michael Dewey <lists at dewey.myzen.co.uk>
wrote:
> Dear Pijush
>
> You might do better to ask on the Bioconductor list as IRanges does not
> seem to be on CRAN so I deduce it is a Bioconductor package too.
>
> Michael
>
>
> On
2009 Mar 30
2
Sliding window over irregular intervals
Dear all,
I have some very big data files that look something like this:
id chr pos ihh1 ihh2 xpehh
rs5748748 22 15795572 0.0230222 0.0268394 -0.153413
rs5748755 22 15806401 0.0186084 0.0268672 -0.367296
rs2385785 22 15807037 0.0198204 0.0186616 0.0602451
rs1981707 22 15809384 0.0299685 0.0176768 0.527892
rs1981708 22 15809434 0.0305465 0.0187227 0.489512
rs11914222 22 15810040 0.0307183
2017 Dec 29
2
Facing problem in installing the package named "methyAnalysis"
Dear Sir,
I have been using R for a long time. But recently I have faced a problem
when installing the Bioconductor package named "methyAnalysis". Firstly it
was require to update my older R (R version 3.4.3 (2017-11-30)) in to newer
version. That time I have also updated the RStudio software.
After that when I have tried to install the package named "methyAnalysis".
It
2017 Dec 29
0
Facing problem in installing the package named "methyAnalysis"
Dear Pijush
You might do better to ask on the Bioconductor list as IRanges does not
seem to be on CRAN so I deduce it is a Bioconductor package too.
Michael
On 29/12/2017 07:29, Pijush Das wrote:
> Dear Sir,
>
>
>
>
> I have been using R for a long time. But recently I have faced a problem
> when installing the Bioconductor package named "methyAnalysis".
2010 May 11
2
Regex and gsub
Dear group,
Here is my df :
df3 <-
structure(list(DESCRIPTION = c("COPPER May/10", "COTTON NO.2 Jul/10",
"CRUDE OIL miNY May/10", "GOLD Jun/10", "ROBUSTA COFFEE (10) Jul/10",
"SOYBEANS Jul/10", "SUGAR NO.11 Jul/10", "SUGAR NO.11 May/10",
"WHEAT Jul/10", "SPCL HIGH GRADE ZINC USD",
2015 Jan 13
2
R CMD build looking for texi2dvi in the wrong place (R-devel)
R CMD build fails with recent R-devel because it is looking for texi2dvi in /usr/local/bin, but on this system, MacTex has installed it in /usr/bin.
$ R CMD build IRanges
* checking for file 'IRanges/DESCRIPTION' ... OK
* preparing 'IRanges':
* checking DESCRIPTION meta-information ... OK
* cleaning src
* installing the package to build vignettes
* creating vignettes ... ERROR
2003 Sep 04
1
error in lm.fit
Hello R user,
I have several data frames with >100 columns and I did a linear regression
over time of each column
df1.lm <- lapply(df1, function(x) lm(x~year)$coeff[2])
that worked fine and I get slope of each column oder time - until I divided
df1 by df2
df3 <- df1/df2
> df3.lm <- lapply(df3, function(x) lm(x~year)$coeff[2])
Error in lm.fit(x, y, offset = offset, ...) :
2011 Jun 06
1
Merge two columns of a data frame
I have the following data:
prefix <- c("cheap", "budget")
roots <- c("car insurance", "auto insurance")
suffix <- c("quote", "quotes")
prefix2 <- c("cheap", "budget")
roots2 <- c("car insurance", "auto insurance")
roots3 <- c("car insurance", "auto