similar to: Why Numeric Values Become Factors in Data Frame

I've successfully reformatted data frames from long to wide with reshape2, but this time I'm getting errors that I want to understand and resolve. Here's the data frame structure and the results of the melt() and dcast() functions: str(waterchem) 'data.frame': 128412 obs. of 8 variables: $ site : Factor w/ 64 levels "D-1","D-2","D-3",..: 1 1

One of many scripts to produce 4 lattice plots on one page keeps throwing an error. I've tried manipulating the file to eliminate the error, but have not been able to do so. The error is: > source('bicarb.R') Error in source("bicarb.R") : bicarb.R:15:1: unexpected symbol 14: 15: hco33 ^ The 'h' is in column 0 so the caret would be column -1, but it's

hello, I wish to create some 3d scatter diagrams visualising different grouped data set by a given field in the database. I tried the scatterplot3d package, as well as the plot3d and scatter3d functions (both within the rgl resp. Rcmdr package). My first question is, whether is it possibe to group data in the scatterplot3d and plot3d, because I did not succeed to use the groups = ...

Is anyone else experiencing trouble with Teliax? I can only intermittently register to, and am not able to place any outgoing calls through my assigned gateway; voip-co3.teliax.com. -Rusty -------------- next part -------------- An HTML attachment was scrubbed... URL: http://lists.digium.com/pipermail/asterisk-users/attachments/20060120/aa8ab017/attachment.htm

Dear expeRts, I would simplify following code. --------------------------------------------- youtput <- function(x1, x2){ n <- length(x1) y <- vector(mode="numeric", length=n) for(i in 1:n){ if(x1[i] >=5 & x1[i] <= 10 & x2[i] >=5 & x2[i] <=10) y[i] <- 0.631 * x1[i]^0.55 * x2[i]^0.65 if(x1[i] >=10 & x1[i] <= 15 &

Hi: I am using the following command: xyplot(dat6$CO3*1e6 ~ dat6$irradiance, data=dat6, group=ref, xlab=list(label=expression(paste("Irradiance (", mu, "mol photons", m^"-2", " ", s^"-1", ")")), cex=1.3), ylab=list(label=expression(paste("Carbonate concentration (x ", 10^"6", " ", kg^"-1",

Hi friends - I'm plotting a ratio of bicarbonates i ggplot2 and ylab(expression(paste(frac("additive BIC","true BIC")))) worked OK - but now I have been asked to put the chemistry instead - so I wrote ?ylab(expression(paste(frac("additive",HCO[3]^"-","true",HCO[3]^"-")))) - and frac saw that as additive = numerator and HCO3- =

?s 10:01 de 02/02/2024, Troels Ring escreveu: > Hi friends - I'm plotting a ratio of bicarbonates i ggplot2 and > > ylab(expression(paste(frac("additive BIC","true BIC")))) worked OK - but > now I have been asked to put the chemistry instead - so I wrote > >

... or if I understand correctly, simply expression(frac(additive ~ HCO[3]^"-", true ~ HCO[3]^"-" ))) Cheers, Bert On Fri, Feb 2, 2024 at 3:06?AM Rui Barradas <ruipbarradas at sapo.pt> wrote: > ?s 10:01 de 02/02/2024, Troels Ring escreveu: > > Hi friends - I'm plotting a ratio of bicarbonates i ggplot2 and > > > >

I have measured values for 47 chemicals in a stream. After processing the original data frame through reshape2, the recast data frame has this structure: 'data.frame': 256 obs. of 47 variables: $ site : Factor w/ 143 levels "BC-0.5","BC-1",..: 1 1 1 2 2 2 2 2 2 2 ... $ sampdate : Date, format: "1996-04-19" "1996-05-21" ... $ Acid :

Hi I'm trying to measure the effect of a policy intervention (Box and Tiao, 1975). This query has to do with the coding of the model rather than with the particulars of my dataset, so I'm not providing the actual dataset (or a simulated one) in this case, apart from some general description. The time series are of length n=34 (annual observations between 1977 and 2010). The policy

Hi r-help forum, I have been collecting contact data (with proximity logger collars) between a few different species of animal. All animals wear the collars, and any contact between the animals should be detected and recorded by both collars. However, this isn't always the case and more contacts may be recorded on one collar of the two. This is fine, it depends on battery life and other

Hi everybody, do you know if is possible to run the Macromedia Flash environment under wine? Thanks you in advance T.E.D.

I need a nudge in the right direction to get started using NADA. I bought Helsel's second addition and am currently reading it; NADA is installed in R. My data has been restructured with a couple of awk scripts. The data frame structure now has a flag if the quantity is censored (ceneq1 column) as well as a lower and upper limit for censored data. For present purposes, interval censoring

Rich, The documentation for cenboxplot states that the second argument must be logical and not integer. the function cenboxplot substitutes synthetic values for censored values using ros, hence the error message from the ros method. I also do not understand how you expect group = 'SO4' to work. It is not clear that the function will replicate 'SO4' to make a single group.

Hi R help forum, I have a simple data frame of four columns - one of numbers (really a categorical variable), one of dates and one of data. I have over 500,000 data points to work with, spread over 40 files, each named after a different animal. These are contact data recorded by proximity loggers over two years between the animals of the file name and collars being worn by other animals. The

Mª Luz, si el comando de Carlos te devuelve 0 es que no hay NA's. Da igual que tus columnas sean caracteres o número. Lo que intuyo es que tienes celdas con la frase "NA" que interpretas como NA. Mandanos el summary de tu data.table y lo vemos... ----- Mensaje original ----- De: "MªLuz Morales" <mlzmrls en gmail.com> Para: "Carlos J. Gil Bellosta"

I believe that I have a basic understanding of zoo and how to use read.zoo on a text file, What I have not seen in the zoo help files and vignettes is how to convert a data frame to a zoo matrix for irregular time series analyses. An example data frame is structured like this: str(burns.cast) 'data.frame': 256 obs. of 47 variables: $ site : Factor w/ 143 levels

Hello I would like to transfer some Splus functions in R. But I have a problem first about this assignation in Splus : xnom <- deparse(substitute(x)) I am a bad programmer : I don't understand the R help How to modify these functions ? Thank you very much for your help Here are the four functions and a data test

Hi expeRts, I would like to calculate weighted mean by two factors. My code is as follows: R> tmp <- by(re$meta.sales.lkm[, c("pc", "sales")], re$meta.sales.lkm[, c("size", "yr")], function(x) weighted.mean(x[,1], x[,2])) The result is as follows: R> tmp size: micro yr: 1994 [1] 1.090