similar to: optimising a loop

Hello Arnaud, You posted this question a long long time ago, however I found your answer so I decided to post it anyway in case somebody else have the same problem as you and me. You were actually very close in finding your solution. The function DoWritedbf is an internal function from the foreign package. To access it outside of the package just do: foreign:::DoWritedbf so in your line:

Hello R-users, I'm currently facing a pretty hard problem which I'm hopping you'll be able to help me with. I'm using R to create images. That alone is not the problem, the problem is that I'm using R to create 168 000 images... My code (which is given below) use different package (raster and rgdal) to import a image (size 20gig) and divide it into 168 000 pictures that are

DearR Users, I have a problem which I think you might be able to help. I have a dataframe which I'm trying to "filter" following different groups I specified. It's a little hard to explain, so here is an example: My dataframe: ESS DHP 1 EPB 22 2 SAB 10 3 SAB 20 4 BOJ 14 5 ERS 28 11 SAB 10 12 SAB 22 13 BOJ 26 20 SAB 10 21 SAB 22 22 BOJ 32 29 SAB 14 30 SAB

Dear R-users I have some datasets, all left-censoring, and I would like to fit distributions to (weibull,exponential, etc..). I read one solution using the function survreg in the survival package. i.e survreg(Surv(...)~1, dist="weibull") but it returns only the scale parameter. Does anyone know how to successfully fit the exponential, weibull etc... distributions to left-censoring

Hello Flac Boys! I've a little thing, without consequences, I try to understand since last evening; I will try to resume it clearly : You must know that I create an NTFS partition, for only coding my CD's in FLAC (for home using) and in MP3 (for car using). My partition inculudes some directories called WAV, FLAC and MP3, amongst others, for personal and paranoiac purposes (double

Let me present to you my problem : I have a character vector x and I would like to obtain the indices of the elements of this vector that yielded exactly a match. For example, x=nom, pattern="b", I would to obtain 2 because "b" is on the second position. First program : nom <- c("a","b","ab") grep("b",nom) 2 3 Then I try the

Hello I have the following problem : The dataframe TEST has multiple lines for a same person because : there are differents values of Nom or differents values of Prenom but the values of Matricule or Sexe or Date.de.naissance are the same. TEST <- structure(list(Matricule = c(66L, 67L, 67L, 68L, 89L, 90L, 90L, 91L, 108L, 108L, 108L), Nom = structure(c(1L, 2L, 2L, 4L, 8L, 5L, 6L, 9L, 3L, 3L,

Dear R-List, I would like to write nicely the names of some isotopes on a plot. The code bellow works fine. plot(1:10,1:10) text(c(2,4,8),c(2,4,8),labels=c(expression(italic(phantom(0)^{78}*Ge)), expression(italic(phantom(0)^{137}*Cs)), expression(italic(phantom(0)^{129*m}*Te))), cex=3 ) But, since I have a lot of

Dear R-List, I would like to write nicely the names of some isotopes on a plot. The code bellow works fine. plot(1:10,1:10) text(c(2,4,8),c(2,4,8),labels=c(expression(italic(phantom(0)^{78}*Ge)), expression(italic(phantom(0)^{137}*Cs)), expression(italic(phantom(0)^{129*m}*Te))), cex=3 ) But, since I have a lot of

Dear all, this is my first message to this mailing list - please advise if it is not the right place for the subject I've been using R very intensively the last 3-4 years and one of the most tedious tasks is modification of lookup or conversion tables So far, I have not found functions that create the commands for creating objects (vectors, data frames) based on the objects themselves -

Hi, We are currently moving from linuxconf/dovecot to a dovecot setup with sql support, the problem we currently facing is having a message sent to a aliase delivered to the user email inbox with dovecot-lda, i have created cedrict at mail.vdl and a alias test at mail.vdl, when i send to cedrict at mail.vdl the message is included in the user inbox file, but when i send to test at mail.vdl

Hy all, I wish to use a variable as rownames for a set of datas. By example : > nom<-"toto" > prenom<-"tutu" > res<-c(1,2) > res<-t(res) > res [,1] [,2] [1,] 1 2 > colnames(res)<-c(nom,prenom) > res toto tutu [1,] 1 2 > nom [1] "toto" > I wish to call the rowname by the

Dear R-List, I want to use the label function (from Hmisc library) to allow for the names of my isotopes. library(Hmisc) library(lattice) library(grid) num <- c("78","137","129m") nom <- c("Ge","Cs","Te") df <- data.frame(GE78=seq(nom),CS137=seq(nom),TE129m=seq(nom)) if I use this function to create the labels : lab <-

yop, http://rubyonrails.org/api/classes/ActionView/Helpers/FormHelper.html ici j''ai vu qu''on pouvait g?n?rer des ?l?ment d''un formulaire gr?ce des m?thodes. Apres quelque petite recherches j''ai trouv? comment g?n?rer un select <%= select(''category'', ''category.id'', Category.find_all.collect {|category| category.nom})

Dear R-Helpers, I'm working with immunoassay data and 5PL logistic model. I wanted to experiment with different forms of weighting and parameter selection, which is not possible in instrument software, so I turned to R. I am using R 2.14.2 under Win7 64bit, and the 'nls' library to fit the model - I started with the same model and weighting type (1/y) as in the instrument to see

Hi, Thanks for showing me how to use RODBC and odbcConnect. Now works nicely. The question I've got now is: noms <- list.files(pattern=".DBF") # removing extension names: noms <- sapply(noms, function(x) as.character(strsplit(x,".DBF")) , USE.NAMES=F) for (i in 1:length(noms)) { s <- sqlFetch(bdades, noms[i]) # etc. } But it seems that sqlFetch()

Dear all, I 'd like to keep the names of variables when calling them in a function. An example might help to understand my problem : The following function puts in a new data frame counts and percent of a data.frame called as "tablo" the step " nom.chiffr[1] <- names(vari) " is useless as names from the original data.frame aren't kept in the function environement.

Hi, I am trying to construct a logistic regression model from my data (104 patients and 25 events). I build a full model consisting of five predictors with the use of penalization by rms package (lrm, pentrace etc) because of events per variable issue. Then, I tried to approximate the full model by step-down technique predicting L from all of the componet variables using ordinary least squares

Hello I have the following problem : group the lines of a dataframe when no information change (Matricule, Nom, Sexe, DateNaissance, Contrat, Pays) and when the value of Debut of lines i = value Fin of lines i-1 I can obtain it with a do loop. Is it possible to avoid the loop ? The dataframe initial is df1 dput(df1) structure(list(Matricule = c(1L, 1L, 1L, 6L, 6L, 6L, 6L, 6L, 6L, 8L, 8L, 8L,

Hello all, I've setup samba Version 2.2.0a on Slackware 8.0 # uname -a Linux slackware 2.4.5 #6 Fri Jun 22 01:38:20 PDT 2001 i686 unknown I start samba as root from a console as: /usr/sbin/smbd -D -d10 -l /var/adm/smblogs/log -s /etc/samba/smb.conf /usr/sbin/nmbd -D -d1 -s /etc/samba/smb.conf In smb.conf I have: [files] comment = mystuff valid users = nigels path = /usr1 read