similar to: Help with dates and characters

Dear R Experts, I am having some trouble creating a variable in R. I have data on self-placement of voters, their placement of parties, and which party they feel closest to. The data is structured like this: Party_Close lrplaceself lrplaceParty1 lrplaceParty2 ... party1 2 4 5 party2 5 6 4 party1 6 2 1 etc... I want to format the data set so it looks like this: Party_Close

Dear All, I have some data in the following shape: ID begin_t1 end_t1 begin_t2 end_t2 Thomas 11/03/04 13/05/06 04/02/07 16/05/08 ... ... ... ... ... Jens 24/01/02 23/05/03 07/06/03 14/11/05 I would like to reshape this data to have the following form: ID Begin_Time End_Time Thomas 11/03/04 13/05/06 Thomas 04/02/07 16/05/08 ... ... ... Jens 24/01/02 23/05/03 Jens

Dear R list, I have an event history data set that is structured like this: Legislative act Discussion Agreement Time Event Act1 2006-05-30 2006-06-19 20 1 Act2 2004-03-01 2004-06-14 105 1 . . . I have information on the meetings in the legislature between adoption periods in a separate variable (the

Dear R-list, I have a problem which I think is quite basic, but so far google has not helped me. I have two vectors like this: vector_1 <- c(Belgium, Spain, Greece, Ireland, Luxembourg, Netherlands, Portugal) vector_2 <- c(Denmark, Luxembourg) I would like to find the elements in vector_1 that are not in vector_2 so that i get a vector with these countries: Belgium, Spain, Greece,

Hi all, I?m struggling to get the dates in proper format. I have dates as factors and is in the form 02/27/34( 34 means 1934). If I use as.Date with format %d%m%y it gets converted to 2034-02-27. I tried changing the origin in the as.Date command but nothing worked. Any help is appreciated. Thanks, Ramesh

Dear all, please, is there any possibility how to extract a date from data which are like this: .... "Date: Sat, 21 Feb 04 10:25:43 GMT" "Date: 13 Feb 2004 13:54:22 -0600" "Date: Fri, 20 Feb 2004 17:00:48 +0000" "Date: Fri, 14 Jun 2002 16:22:27 -0400"

Hola, Estoy encontrando un problema al intentar poner un objeto Dates en un vector o dataframe. Mi ejemplo # preliminares install.packages( lubridate ); library( lubridate ) v <- c(0, 0, 0) original<-c(2019,308,1700, 25) # c(año, día del año, hora, temperatura) esto sale así de un sensor de temperatura # convertimos los datos originales en algo que entienda R a <-

Dear R-list, Sorry for spamming the list lately, I am just learning the more advanced aspects of R! I have some data that looks like this: Out Country1 Country 2 Country 3 ... CountryN 1 1 1 1 1 0 1 1 0 1 1 1 0 1 0 I want to create a new variable that counts the number of zeros in every row whenever Out is equal to 1, and else it is a zero, so it would look like this: new_var 0 0 2 I

Dear all I have a 'character' vector containing mixed formats (thanks Excel!) and I'd like to translate it into a default "%Y-%m-%d" Date vector. x <- c("1/3/2005", "13/04/2004", "2/5/2005", "2/5/2005", "7/5/2007", "22/04/2004", "21/04/2005", "20080430", "13/05/2003",

Hello, Please excuse me if this question has been asked before. I'm new to R, and have been trying to google the answers without any success. I would like to convert a set of date and time into R date-time class. Right now, the dates and times are in integer format, so I first need to convert them into string, and then to R date-time using strptime. However, I have a problem converting them

Carlos, muchas gracias, voy a probarlo. Pero me sigue intrigando por que no puedo ponerlo como elemento de un vector... Misterios del R. SI lo averiguo os lo digo. Jaume. El sáb., 15 feb. 2020 a las 19:08, Carlos Ortega (<cof en qualityexcellence.es>) escribió: > Hola, > > Una alternativa que te puede ayudar es enfocar el problema de esta otra > forma. > Puedes ir guardando

Hello, I have some data that has dates in the form 27.02.37. I convert them to a date object as follows: as.Date(data$date,format="%d.%m.%y") But this gives me years such as 2037 when I would like them to be 1937. I thought of trying to take off some time i.e. as.Date(camCD$DoB,format="%d.%m.%y") - 100*365 But that doesn't seem to work out correctly. Any ideas how to

I am trying to generate a line graph with quarterly time buckets (with nice labels) on the x-axis. The first block of code below will generate the graph with nicely formatted x-axis labels, but the "type=" and "col=" options are not recognized when factors are used for the x-axis. The second block, where the quarter values are mapped into dates, will plot the line nicely but

Muchas gracias, Probaré eso también y ya os cuento. Jaume. El lun., 17 feb. 2020 a las 22:10, Javier Marcuzzi (< javier.ruben.marcuzzi en gmail.com>) escribió: > Estimado Jaume Tormo > > En lo personal yo utilizo un enfoque como el que comenta Carlos Ortega, se > me ocurre que posiblemente funcione si a su código le coloca algo de > formato, me refiero a esta forma: >

Dear all, Suppose I have a date variable: c = "99/05/12" I want to extract the parts of this date like month number, year and day. I can do it in SPSS. Is it possible to do this in R as well? Rgd, --------------------------------- Here’s a new way to find what you're looking for - Yahoo! Answers [[alternative HTML version deleted]]

Help-Rs,   I'm doing some string manipulation in a file where I converted a string date in mm/dd/yyyy format and returned the date yyyy.   I've used regexpr (hat tip to Gabor G for a very nice earlier post on this function) in steps (I've un-nested the code and provided it and an example of what I did below.  My question is: is there a more efficient way to do this.  Specifically is

Hello, I have the following problem: test is a data frame with 9 fields. The field test$Date is factorized with dates. The format is dd-mm-yyyy (using Oracle notation). I want to convert this to Date in '%Y-%m-%d format. What I am doing is: for (i in 1:nrow(test)) { test[i,]$Data<-strptime(substring(test[i,]$Data,1,10),"%d-%m-%Y") } test is a data frame. The error is:

dear R experts--- t <- 1:30 f <- function(t) { cat("f for", t, "\n"); return(2*t) } g <- function(t) { cat("g for", t, "\n"); return(3*t) } s <- ifelse( t%%2==0, g(t), f(t)) shows that the ifelse function actually evaluates both f() and g() for all values first, and presumably then just picks left or right results based on t%%2.

Hi, I've been trying to convert numbers from an online temperature database into dates and time that R recognizes. I've tried as.Date, as.POSIXlt and strptime the problem is that the database has put a T between the numbers and R will not accept any conversions. currently it sees the date as a factor with the format as 1981-01-02T08:00I would like to keep only the year and month, but my

What is the recommended/optimal way to perform aggregates on data frames with chron objects? Here is an example: >raw.data 1 07/09/01 4000 2 07/09/01 2000 3 07/11/01 1000 4 07/13/01 800 5 07/13/01 700 6 07/16/01 600 7 07/17/01 500 I'm trying to construct a function that would first aggregate the data (second column) by day (grouping by the first column) according to a