Displaying 1 result from an estimated 1 matches for "xlst_xlst".
1999 Oct 21
1
left.solve
...ares=F, f=NULL) {
jnk_par("fig")
relsize_relsize*(jnk[2]-jnk[1])*(jnk[4]-jnk[3])
if (!is.character(xlst))
xlst_names(df)[xlst]
if (!is.character(yname) || !is.character(outname))
stop("yname and outname must be in quotes")
if (length(xlst[xlst==yname])==1)
xlst_xlst[xlst!=yname]
if (length(xlst[xlst==outname])!=1)
stop(paste(outname,"is not in",paste(xlst, collapse=", ")))
if (is.null(main)) {
nam_xlst
nam[nam==outname]_paste("(",outname,")",sep="")
main_paste(yname,"~",sep="&...