search for: vioplots

Dear all I am trying to make a graphic with the "vioplot" package. I use the following code: library(vioplot) x1 <- GSMrxDL x2 <- WIFI x3 <- UMT vioplot(x1, x2, x3, ylim=c(0, 10), names=c("GSMrxDL", "WIFI", "UMT"), col="gold") title("NIS Strahlung", xlab="Sender", ylab="V/m") Now I want to scale the y-axis

Hi, I have some data (lots of year,distance pairs), which I can straightforwardly boxplot: dists <- read.table("movedists.dat") with(dists,plot(as.factor(V1),V2)) If I want to plot these data as violin plots using vioplot, this approach doesn't work: > with(dists,vioplot(as.factor(V1),V2)) Error in Summary.factor(c(1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, : min not

...on how to do what I want. I have nine groups of values, each group containing two sets of numbers which show the difference between two values, such as this: Start dev Stop dev -1 10 5 -2 0 -4 and so on. This has uptil now been shown as vioplots with start deviation above the other, and I have had three groups within each vioplot. I would now like to have these two next to each other, each with their own zero point. Does anybody have any tips on how to achieve this? Any help much appreciated. Karin -- Karin Lagesen, PhD student karin.l...

I am trying to make horizontal violin plots. I have tried both vioplot and simple.violinplot, but both of them seem to not be willing to take the horizontal option. Is this correct, or am I just bungling it somehow? For instance, for vioplot (from the example shown, with the horizontal modification): > vioplot(bimodal,uniform,normal, horizontal=TRUE) Error in median(data) : need numeric data

Hi, I have a list of vectors and am trying to coerce them into something that vioplot will take as groups of data to be plotted independently. Can someone nudge me into the right direction? Thanks, Joh

Hi,? I have made violin plot with both ggplot2 and vioplot package with same data.? The results and code are as follows.? ################### ?Loading data? data.melt <- dget("https://gubox.box.com/shared/static/rirth0eym114afwyjxwe128sjzipzdym.txt") ################### ?Violin plot by library(vioplot) library(vioplot) data.use_11<- data.melt$value[data.melt$ident == 0]

Hi First post and a relative R newbie.... I am using the vioplot library to produce some violin plots. I have an input CSV with columns off irregular length that contain NAs. I want to strip the NAs out and produce a multiple violin plot automatically labelled using the headers. At the moment I do this Code:? ds1 = read.csv("http://www.lecturematerials.co.uk/data/spelling.csv")

Hi I am using violin plots (type of boxplots) and  I am trying to increase the font size in the plots. It looks like that the violin plots do not work as "normal" plots as the cex parameters are ignored. You can have a loot at the code below require('vioplot') data1<-rnorm(100) data2<-rnorm(10) data3<-rnorm(1000) vioplot(data1,data2,data3,cex.lab=2,cex.axis=2)

Dear Rgurus, To my knowledge the best way to visualize the distribution of a discrete variable X is plot(table(X)) The problem which I have is the following. I have to discrete variables X and Y which distribution I would like to compare. To overlay the distribution of Y with lines(table(Y)) gives not satisfying results. This is the same in case of using density or histogram. Hence, I am

I am creating boxplots from a dataframe and would like to add to the standard output a marker representing the value from a particular row in the dataframe. .....And I apologize if the solution is as trivial as it seems it should be. Thanks for any assistance. Keith

Dear list, How can I add the mean and standard deviation to each of the boxplots using the example provided in the boxplot function? boxplot(len ~ dose, data = ToothGrowth, boxwex = 0.25, at = 1:3 - 0.2, subset = supp == "VC", col = "yellow", main = "Guinea Pigs' Tooth Growth", xlab = "Vitamin C dose mg",

Hello R-helpers, I would like to calculate least square means after having built a GLM with quasipoisson errors. In my model the dependent variable is continuous, I have one continuous independent variable and one categorical independent variable (that is the variable for which I would like to calculate the least square means). I've looked around for the command to calculate the least

Hello, I saw a little discussion about this in the archives, but it was unclear to me whether someone had submitted a port to R of the Splus bagplot() function. If so, does anyone know where I could get it? Thanks. Best, Matt

I agree with Martin "R Graph Gallery" has a lot of neat stuff. I also think there should be a on CRAN website a list of "R websites". And in a perfect world one of the search engines scope would get extended to search them all. Jarek ====================================================\==== Jarek Tuszynski, PhD. o / \ Science Applications

I have read and reread the boxplot and the boxplot stats page, and I still cannot understand how and what boxplot shows. I realize that this might be due to me not knowing enough statistics, but anyway... First, how does boxplot determine the size of the box? And is the line inside the box the mean or the median (or something completely different?) And how does it determine how long out the

Hi All Please see the Rprofile file which i have modified as follows and after that when I start R then I see that R says to me "TRUE" for all the packages implying that all loaded at once. But when i try to use commands as simple as help("lm"), it doesnt work nor any of the menu "Packages" is not working. Although the regression using lm ( Y ~ X ) is working