search for: utkarshs

Hi R, I have an excel file in which the third column is "date" and others are "character" and "numeric". Number of columns are 12 If I use this to read the file in R: x = read.xls("D:\\file.xls") The problem is that my date column is read in julian dates. So I am using: x = read.xls("D:\\file.xls",

I am using the library(bigmemory) to handle large datasets, say 1 GB, and facing following problems. Any hints from anybody can be helpful. _Problem-1: _ I am using "read.big.matrix" function to create a filebacked big matrix of my data and get the following warning: > x = read.big.matrix("/home/utkarsh.s/data.csv",header=T,type="double",shared=T,backingfile

Hi All, I want to "merge" two datasets by column "ID" and I don't want the result to be sorted by "ID". I am doing the following: > z = merge(x, y, by = "ID", sort=F) The result is not sorted by "ID". But (as oppose to what I expected) it is not even in the original order of either "x" or "y". Can

...small enough to be read in usual R, just the combined dataset is huge. Any thoughts are welcome. Thanks, Utkarsh -------- Original Message -------- Subject: adding more columns in big.matrix object of bigmemory package Date: Thu, 16 Dec 2010 18:29:38 +0530 From: utkarshsinghal [1]<utkarsh.singhal at global-analytics.com> To: r help [2]<r-help at stat.math.ethz.ch> Hi all, Is there any way I can add more columns to an existing filebacked big.matrix object. In general, I want a way to modify an existing big.matrix object, i.e., add...

Hello everyone, I want to import data from huge sas files with 100s of columns. The good thing is that I am only interested in a few selected columns. Is there any way to do that without loading the full dataset. I have tried two functions: (1) read.sas7bdat *[from library 'sas7bdat']*, and (2) read_sas *[from library 'haven']. *But couldn't find what I am looking for. Best

hi, the sas universal viewer might be a free, non-R way to convert a sas7bdat file to non-proprietary formats, not sure if it's windows-only. those other formats should be easier to import only a subset of columns into R.. https://support.sas.com/downloads/browse.htm?fil=&cat=74 On Thu, Aug 10, 2017 at 7:42 AM, peter dalgaard <pdalgd at gmail.com> wrote: > I had a look at this

Hi All, I have vector of length 52, say, x=sample(30,52,replace=T). I want to sort x and split into five *nearly equal groups*. Note that the observations are repeated in x so in case of a tie I want both the observations to fall in same group. This seems a very common task to do, but still I couldn't find an R function to do this. Any help would be highly appreciated. Regards Utkarsh

I had a look at this a while back and it didn't seem to be easy. The path of least resistance would seem to be to use SAS itself to create a data set with fewer columns, but of course that requires you to get access to SAS. Otherwise, I think you'd have to modify sas7bdat::read.sas7bdat to drop unselected columns. That function is pure R code, so it might not be quite as hard as it

...ut I am unable to label the branches (not the nodes) of the tree. Can somebody help me out in this? Thank you, Regards Utkarsh Singhal | Amba Research Ph +91 80 3980 8017 | Mob +91 99 0295 8815 Bangalore * Colombo * London * New York * San José * Singapore * www.ambaresearch.com <mailto:utkarshs@ambaresearch.com> This e-mail may contain confidential and/or privileged i...{{dropped:13}}

Hi All, I ran the following lines in R: print(object.size(a <- rep(1,10^6)),units="Mb") print(object.size(a <- rep(3.542,10^6)),units="Mb") print(object.size(b <- rep("x",10^6)),units="Mb") print(object.size(b <- rep("xyzxyz xyz",10^6)),units="Mb") print(object.size(b <- 1:10^6),units="Mb") print(object.size(b

Hi All, I am currently doing the following to compute summary statistics of aggregated data: a = aggregate(warpbreaks$breaks, warpbreaks[,-1], mean) b = aggregate(warpbreaks$breaks, warpbreaks[,-1], sum) c = aggregate(warpbreaks$breaks, warpbreaks[,-1], length) ans = cbind(a, b[,3], c[,3]) This seems unnecessarily complex to me so I tried > aggregate(warpbreaks$breaks, warpbreaks[,-1],

...t solves my problem but I am not sure whether I am doing the right thing. Any comments are welcome. Thank you, Regards Utkarsh Singhal | Amba Research Ph +91 80 3980 8017 | Mob +91 99 0295 8815 Bangalore * Colombo * London * New York * San José * Singapore * www.ambaresearch.com <mailto:utkarshs@ambaresearch.com> This e-mail may contain confidential and/or privileged i...{{dropped:13}}

Hi all, I am performing a stepwise regression by running the "step" function on an "lm" object. Now I want to save the intermediate iterations. I know the argument trace=T will print it on the console, but I rather want to assign it to some R object or may be output it in a CSV or text file. Any help will be appreciated. Regards Utkarsh

Hi, I am trying to create a small extension for R here for embedding the current time on the R prompt: https://github.com/musically-ut/extPrompt Things seem to be working overall, but `R CMD check .` raised a warning: > File '[truncated]..Rcheck/extPrompt/libs/extPrompt.so?: > Found non-API call to R: ?ptr_R_ReadConsole? > > Compiled code should not call non-API entry points in

Hi All, I am currently using R version 2.8.1 on linux cent os 4.4 (i386) and want to upgrade to version 2.9.1. It seems to me that version-2.9.1 is it not for my OS. Am I right? Regards Utkarsh [[alternative HTML version deleted]]

Hi R, I am getting this error while trying to use 'lrm' function with nine independent variables: > res = lrm(y1994~WC08301+WC08376+WC08316+WC08311+WC01001+WC08221+WC08106+WC0810 1+WC08231,data=y) singular information matrix in lrm.fit (rank= 8 ). Offending variable(s): WC08101 WC08221 Error in j:(j + params[i] - 1) : NA/NaN argument Now, if I take choose only four

Hi all, I want to define a function such that one of its argument if passed do one thing and if not passed do the second thing. So basically, I have to check whether the argument is passed or not inside the function. I am trying to use 'exists' function to do this. > f = function(a,b){exists("b")} > f(a=3, b=4) [1] TRUE This is working as expected.

Hi all, I want to define a function such that one of its argument if passed do one thing and if not passed do the second thing. So basically, I have to check whether the argument is passed or not inside the function. I am trying to use 'exists' function to do this. > f = function(a,b){exists("b")} > f(a=3, b=4) [1] TRUE This is working as expected.

I never understood that why is the value returned by as.date function in the library(survival) never matches with the description given in the help file: Following is the extract from ?as.date Description: Converts any of the following character forms to a Julian date: 8/31/56, 8-31-1956, 31 8 56, 083156, 31Aug56, or August 31 1956. Usage: as.date(x, order = "mdy", ...)

I define the following function: (Please don't wonder about the use of this function, this is just a simplified version of my actual function. And please don't spend your time in finding an alternate way of doing the same as the following does not exactly represent my function. I am only interested in a good explanation) > f1 =