search for: sulfat

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Descriptive Stats from Data Frame
2011 Aug 30
3
Descriptive Stats from Data Frame
...data) site_id.sample_date.param.quant BC-0.5|1996-04-19|Arsenic|0.01 : 1 BC-0.5|1996-04-19|Calcium|76.56 : 1 BC-0.5|1996-04-19|Chloride|12 : 1 BC-0.5|1996-04-19|Magnesium|43.23 : 1 BC-0.5|1996-04-19|Sulfate|175 : 1 BC-0.5|1996-04-19|Total Dissolved Solids|460: 1 (Other) :14880 I want first to calculate (and plot) descriptive stats by chemical, ignoring site and date and telling R to ignore missing data. (Incorporating those factors will...
Comparing data
2011 Nov 28
1
Comparing data
...028 0 ... $ Kalcij : num 0.192 0.566 0.172 0 0.303 ... $ Magnezij : num 0.321 0.568 0.29 0.352 0 ... $ Fluorid : num 0.6739 0.2283 0.7826 0.0109 0.2609 ... $ Hidrogenkarbonati: num 0.362 1 0.31 0 0.16 ... $ Kalij : num 0.335 0.456 0.335 0.426 0 ... $ Sulfat : num 0.692 0 0.517 0.609 0.609 ... $ Nitrati : num 0.3934 0.0195 0.5008 0.3835 0.2601 ... $ Silikati : num 0.55 1 0.5214 0.0429 0.7143 ... $ Fe : num 0.786 0 0.357 0.214 0 ... $ Natrij : num 0.1321 0.093 0.093 0.0579 0 ... $ m.Alkaliteta...
Linear Discriminant Analysis error: "Variables appear constant"
2011 May 16
1
Linear Discriminant Analysis error: "Variables appear constant"
...radient+NatComm+FishIBIUsed +QHEI+QHEIsub+QHEImwh_h+QHEIcov+QHEIchan+QHEIrip+QHEIpool+QHEIrif+QHEIgrads+ QHEIgradv+QHEImwh+QHEIcovtype+QHEIwwh+QHab+QHabBuff+QHabEros+QhabPool+ QHabWDRatio+QHabRif+QHabFines+QHabCov+QHabRating+QHabSize+TP+TKN+NH3+NH3Min +NO3NO2N+BOD+TSS+TSSMax+TDS+SSC+SSCMax+Chloride+Sulfate+Ecoli+ChlA+DOper+ DOperMin+DOperMin1_5+DOmgL+DOmgLMean+DOmgLMax+Cond+pH+pHMax+Trans+Temp+ TempMin+Temp4+Crop100+Crop500+CropSub+Dev100+Dev500+DevSub+For100+For500+ ForSub+Pas100+Pas500+PasSub+Wat100+Wat500+WatSub+Wet100+Wet500+WetSub+ Undev100+Undev500+UndevTotal+Undev100NoPas+Undev500NoPas+UndevT...
PrettyR (describe)
2008 Jun 19
1
PrettyR (describe)
...Silicon = c(4.6, 4.3, 3.9, 3.5, 4.1, 3.8, 1.6, 4.1, 3.8, 4.4, 4.5, 4.3, 4.1, 5, 4.1, 4.9, 5, 4.3, 4.1, 3.6, 4.1, 3.6, 3.6, 3.9, 4.1, 4.1, 4.3), Sodium = c(3.2, 3.6, 3.6, 3.8, 2.9, 2.9, 2.8, 3.4, 2.9, 2.6, 3.1, 2.8, 2.8, 3.2, 3, 3, 3.1, 3, 4, 3, 2.1, 4, 3.8, 3.7, 2.5, 2.7, 3.4), Sulfate = c(3, 2.2, 2.5, 2.2, 2.2, 2.2, 2.5, 2.2, 2.4, 2.4, 2.9, 3.4, 2.7, 3.2, 3.5, 4.1, 3.1, 3.1, 3.5, 3.3, 3, 2.9, 2.8, 2.7, 2.8, 3.6, 3), TDS = c(42L, 46L, 28L, 36L, 29L, 35L, 44L, 33L, NA, 43L, 29L, 42L, 35L, NA, 46L, 78L, 38L, 55L, 32L, 65L, 69L, 43L, 28L, 37L, 57L, 29L, 30L), TI...
confidence interval in "predict.lm"
2002 Nov 15
5
confidence interval in "predict.lm"
...The example: > x<-c(10,20,30,40,50,60,70) > y<-c(17,21,25,28,33,40,49) > dat <- data.frame(temp=x,amnt=y) temp amnt 1 10 17 2 20 21 3 30 25 4 40 28 5 50 33 6 60 40 7 70 49 being a table of temperatures (temp) and the corresponding amounts of copper sulfate that disolve in 100g of water at that temperature. The regression line: > mod <- lm(amnt ~ temp,dat) > summary(mod) Call: lm(formula = amnt ~ temp, data = dat) Residuals: 1 2 3 4 5 6 7 1.7857 0.7143 -0.3571 -2.4286 -2.5000 -0.5714 3.3571 C...