search for: struktur

...s the problem with my data (I've attached the relevant file). Every time I tried to use the CANCOR-Function I got error messages. So I turned to check my two sets of variables separately by using the "colMeans"-Function. With one set no problem .. but with the other. My input : > struktur <- read.delim("struktur.csv", header=TRUE, sep = ";") >colMeans(struktur) And the resulting error: Error in colMeans(x, n, prod(dn), na.rm) : `x' must be numeric Can anyone give me a hint concerning the mistake I made? Many thanks in advance hardy --...

-----BEGIN PGP SIGNED MESSAGE----- Hash: SHA256 Hello everybody, first of all I want to excuse myself for crossposting. I can't estimate which mailinglist could be the right one for our concern. Struktur AG, member of the Linux Solutions Group e.V., wants to announce an Open Source tender for an implementation of an audio codec compatible with Nellymoser Asao Codec. Struktur wants to pay 6000 US$ for the project. Proposals can be sent to tenders@struktur.de until October, 31st 2006. Deadline for th...

-----BEGIN PGP SIGNED MESSAGE----- Hash: SHA256 Hello everybody, first of all I want to excuse myself for crossposting. I can't estimate which mailinglist could be the right one for our concern. Struktur AG, member of the Linux Solutions Group e.V., wants to announce an Open Source tender for an implementation of an audio codec compatible with Nellymoser Asao Codec. Struktur wants to pay 6000 US$ for the project. Proposals can be sent to tenders@struktur.de until October, 31st 2006. Deadline for th...

Hallo! I lese gro?e Zeitreihen in R ein z.B. mit: > disc<-read.table("F:/R/DATA/discount_rate_usa.txt") disc hat dann folgende Struktur: > disc[1:5] V1 V2 1 01/03/1955 1.5 2 01/04/1955 1.5 3 01/05/1955 1.5 4 01/06/1955 1.5 5 01/07/1955 1.5 ich will das disc als Zeitreihe erkannt wird und will z.B 01/03/1955 in ein Datum verwandeln, aber es wird als factor aufgefasst: > disc[1,1] [1] 01/03/1955 17647...

...aph pass is only available in opt. Is there any substantial reason for that? Or is it only because it seems not to be useful for llc? I want to use it in an backend that is derived from the CBackend. I need the information what functions are called in every other function to build communication struktures between the functions. The backend is generating VHDL from C code. (VHDL is a hardware description language, which means it is used to generate hardware, for those who are not familiar with this.) I've managed to compile my backend with the CallGraph pass, but when it try to use it, I get...

...OS, Red Hat, and another bunch of source code. Only now that I'm writing up my experience I see there's an inner structure to the list: LLVM, then LLVM-GCC 4.2, then LLVM-GCC 4.0. LLVM starts with sources, LLVM-GCC (inconsistently) starts with binaries and gives sources later. Suggestion 1: Strukture the download list, like so: * LLVM * LLVM source code (5.4M) * LLVM Test Suite (53M) * LLVM Binaries for Minw32/x86 (14M) * LLVM-GCC 4.2 Front End * Binaries for MacOS X/x86 (50M) * Binaries for Red Hat Enterprise Linux4/x86 (42M) ... * Source Code (49M) * LLVM-GCC 4.0 Front End *...

...M %u'$' logon script = logon.cmd logon drive = H: domain logons = Yes os level = 96 preferred master = Yes domain master = Yes dns proxy = No wins support = Yes -- ///////////////////////////////// Dr. Ulrich Harttig Protein Struktur Fabrik MPI f. molecular genetics WWW www.proteinstrukturfabrik.de Email harttig@rzpd.de /////////////////////////////////

...bstantial reason > for that? Or is it only because it seems not to be useful for llc? No, that's not true. > I want to use it in an backend that is derived from the CBackend. I > need the > information what functions are called in every other function to build > communication struktures between the functions. The backend is > generating > VHDL from C code. (VHDL is a hardware description language, which > means it is > used to generate hardware, for those who are not familiar with this.) > > I've managed to compile my backend with the CallGraph pass, bu...

In dovecot 1.2 I can create a shared name space like this: namespace shared { separator = / prefix = users/%%u/ location = Maildir:/PATH/TO/spool/%%u/maildir:INDEX=/PATH/TO/spool/%u/maildir/shared_idx subscriptions = no } now, when I subscribe to a shared mailbox of another user with an dot in the users id, like: users/2 at example.com/INBOX/foo and I list my subscribed mailboxes I get:

...program = /usr/bin/passwd %u passwd chat = *New*Password* %n\n *Retype*new*Password %n\n passwd:*all*authentication*tokens*updated*successfully* unix password sync = yes # hide local users = yes ##################################################################### # Logon Verzeichnis der Service-Struktur ##################################################################### [netlogon] path = /home/samba/netlogon write list = @admin @s_Admin writeable = no browseable = no guest ok = no [profiles] path = /home/samba/profiles read only = No create mask = 0600 directory mask = 0700 browseabl...

...bunch of source code. > Only now that I'm writing up my experience I see there's an inner > structure to the list: LLVM, then LLVM-GCC 4.2, then LLVM-GCC 4.0. LLVM > starts with sources, LLVM-GCC (inconsistently) starts with binaries and > gives sources later. > Suggestion 1: Strukture the download list, like so: > * LLVM > * LLVM source code (5.4M) > * LLVM Test Suite (53M) > * LLVM Binaries for Minw32/x86 (14M) > * LLVM-GCC 4.2 Front End > * Binaries for MacOS X/x86 (50M) > * Binaries for Red Hat Enterprise Linux4/x86 (42M) > ... > * Source Co...

...,23]<-eta[i,3] mu[i,24]<-lam[16]*eta[i,3] mu[i,25]<-lam[17]*eta[i,3] #faktor Persepsi Niat untuk Menggunakan mu[i,26]<-eta[i,4] mu[i,27]<-lam[18]*eta[i,4] mu[i,28]<-lam[19]*eta[i,4] #faktor Adopsi E-government mu[i,29]<-eta[i,5] mu[i,30]<-lam[20]*eta[i,5] #model persamaan struktural xi[i,1:5] ~dmnorm(u[1:5],phi[1:5,1:5]) eta[i,1]~dnorm(nu[i,1],pskp) nu[i,1]<-gam[1]*xi[i,2]+gam[2]*xi[i,3]+gam[3]*xi[i,4] dthat[i,1]<-eta[i,1]-nu[i,1] eta[i,2]~dnorm(nu[i,2],pspk) nu[i,2]<-gam[4]*xi[i,1]+beta[1]*eta[i,1] dthat[i,2]<-eta[i,2]-nu[i,2] eta[i,3]~dnorm(nu[i,3],pssp) nu...